Chapter 16: Problem 48
For the \(y=20 \sin \pi\left(\frac{x}{4}+\frac{t}{2}\right)\) the correct statement is (where \(x\) is in metre and time is in second) (a) amplitude is \(20 \mathrm{~m}\) and frequency is \(0.25\) (b) wavelength is \(20 \mathrm{~m}\) and frequency is 1 (c) frequency is \(\frac{1}{2}\) and wavelength is \(20 \mathrm{~cm}\) (d) \(\omega=2 \pi\) and \(k=\frac{\pi}{2}\)
Short Answer
Step by step solution
Identify Amplitude
Determine Frequency
Find Wavelength and Wave Number
Identify Angular Frequency and Wave Number
Evaluate given options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amplitude Calculation
The given wave equation is \(y = 20 \sin \pi \left(\frac{x}{4} + \frac{t}{2}\right)\). Here, the amplitude, \(A\), is clearly stated as \(20\). This means that the wave will oscillate 20 meters above and below the midpoint of its motion.
- Amplitude is always a positive value.
- It's a measure of the wave's energy; larger amplitude means more energy.
Frequency Determination
Solving for \(f\), \[ f = \frac{1}{4}. \] This indicates that the wave completes a quadrant (or one full wave cycle) every four seconds.
- Frequency is measured in Hertz (Hz), which is cycles per second.
- Higher frequency means more oscillations per unit time.
Wavelength Calculation
In the general wave form \(y = A \sin(2\pi f t + kx + \phi)\), the wave number \(k\) relates to the wavelength as \(k = \frac{2\pi}{\lambda}\). For our equation \(y = 20 \sin \pi \left(\frac{x}{4} + \frac{t}{2}\right)\), \[ k = \frac{\pi}{4}. \] Substituting into \(k = \frac{2\pi}{\lambda}\), we find that
\[ \frac{\pi}{4} = \frac{2\pi}{\lambda}\]
leads to \[ \lambda = 8 \text{ meters}. \] This wavelength indicates the spatial period of the wave, telling us the physical "length" of one full cycle.
- Wavelength has a direct relationship with the wave's speed and frequency.
- Inversely proportional to the frequency; longer wavelengths mean lower frequencies and vice versa.
Angular Frequency
For waves, \(\omega\) can be found using the relation \(\omega = 2\pi f\).
In our wave equation, the term involving \(t\) is \(\frac{\pi}{2}\), and since it typically includes \(\omega\), we identify \[ \omega = \frac{\pi}{2}. \]
- This means the wave progresses by \(\pi/2\) radians per second.
- The connection between \(f\) and \(\omega\) is such that \(\omega\) increases as \(f\) increases.
Wave Number
Given \(y = 20 \sin \pi \left(\frac{x}{4} + \frac{t}{2}\right)\), we notice \[ k = \frac{\pi}{4}. \]
Wave number \(k\) is connected to wavelength \(\lambda\) by \(k = \frac{2\pi}{\lambda}\). Here, \(\frac{\pi}{4}\) indicates how many radians exist per meter through which the wave advances.
- Higher \(k\) values indicate more wave cycles per meter, meaning shorter wavelengths.
- Wave number provides a link between the wave’s spatial characteristics and its wavelength.