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Two identical springs, each of spring constant \(k\) are connected first in series and then in parallel. A mass \(M\) is suspended from them. The ratio of their frequencies of vertical oscillations will be (a) \(2: 1\) (b) \(1: 1\) (c) \(1: 4\) (d) \(4: 1\) (e) \(1: 2\)

Short Answer

Expert verified
The ratio of their frequencies of vertical oscillations is \(2:1\).

Step by step solution

01

Understanding the Scenario

We have two identical springs, each with spring constant \(k\), and we will evaluate the system when they are connected in series and then in parallel, with a mass \(M\) suspended.
02

Determining Effective Spring Constant in Series

When two springs of spring constant \(k\) are connected in series, the effective spring constant, \(k_{series}\), is given by the formula: \[ \frac{1}{k_{series}} = \frac{1}{k} + \frac{1}{k} = \frac{2}{k} \] This simplifies to \(k_{series} = \frac{k}{2}\).
03

Calculating Frequency in Series

The frequency of oscillation \(f_{series}\) for a mass \(M\) on a spring is given by: \[ f_{series} = \frac{1}{2\pi} \sqrt{\frac{k_{series}}{M}} = \frac{1}{2\pi} \sqrt{\frac{k/2}{M}} = \frac{1}{2\pi} \sqrt{\frac{k}{2M}} \]
04

Determining Effective Spring Constant in Parallel

When two springs of spring constant \(k\) are connected in parallel, the effective spring constant, \(k_{parallel}\), is given by: \(k_{parallel} = k + k = 2k\).
05

Calculating Frequency in Parallel

The frequency of oscillation \(f_{parallel}\) for a mass \(M\) on two parallel springs is given by: \[ f_{parallel} = \frac{1}{2\pi} \sqrt{\frac{k_{parallel}}{M}} = \frac{1}{2\pi} \sqrt{\frac{2k}{M}} \]
06

Calculating Frequency Ratio

To find the ratio of the frequencies, \( \frac{f_{parallel}}{f_{series}} \), we use: \[ \frac{f_{parallel}}{f_{series}} = \frac{\sqrt{\frac{2k}{M}}}{\sqrt{\frac{k}{2M}}} = \sqrt{\frac{2k \cdot 2M}{k \cdot M}} = \sqrt{4} = 2 \] Thus, the frequency ratio is \(2:1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant in Series
When springs are arranged in series, their combined stiffness alters. This is important when considering oscillation systems because the spring constant directly affects the system's oscillation frequency.
When you connect two springs, each with spring constant, \( k \), in series, it's like they share the work of supporting the weight. This means the overall spring system becomes less stiff, making it easier to stretch the system compared to just one spring.
We calculate the effective spring constant, \( k_{series} \), using the formula:
  • \[ \frac{1}{k_{series}} = \frac{1}{k} + \frac{1}{k} = \frac{2}{k} \]
  • Solving this gives: \[ k_{series} = \frac{k}{2} \]
This means the effective spring constant in a series is half of a single spring's constant. With a softer system, the oscillation frequency will decrease, as it's less intense than a single spring.
Understanding this is crucial for calculating oscillations in a series spring setup, especially when predicting movements of attached masses.
Spring Constant in Parallel
Springs connected in parallel are handled differently from those in series. Here, the spring constant increases, manifesting more stiffness in response to a force. In this setup, each spring supports the load simultaneously, resulting in a greater overall system stiffness.
For springs arranged in parallel, each having the same spring constant, \( k \), the effective spring constant, \( k_{parallel} \), is obtained by summing their constants:
  • \( k_{parallel} = k + k = 2k \)
The outcome is a significantly stiffer setup. The system resists stretching more than an individual spring, affecting how quickly the system returns to the equilibrium position in an oscillation.
The greater stiffness directly translates to a higher frequency of oscillation, meaning that the system can oscillate more times in a given period. This is why, for mass-spring systems, the spring constant setup has major implications on oscillatory behavior.
Mass-Spring System
Understanding a mass-spring system involves looking at both spring arrangement types with a blob of mass attached. Both series and parallel arrangements affect how the mass and springs will oscillate. The frequency of these oscillations is key to understanding the mechanical action at play in such systems.
In a mass-spring system, frequency \( f \) is given by:
  • \[ f = \frac{1}{2\pi} \sqrt{\frac{k}{M}} \]
Here, \( k \) is the effective spring constant (be it series or parallel), and \( M \) is the mass.
When the mass is attached:
  • In a series system, the effective spring constant reduces to \( \frac{k}{2} \), leading to a lower frequency \( f_{series} \).
  • In parallel, the spring constant doubles to \( 2k \), resulting in a higher frequency \( f_{parallel} \).
This shift captures how the mass interacts with the spring force—dictating how fast it moves. Thus, the mass-spring system is a dynamic interplay of stiffness and mass, yielding specific oscillation frequencies.

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Most popular questions from this chapter

A particle is executing simple harmonic motion with an amplitude \(A\) and time period \(T\). The displacement of the particle after \(2 T\) period from its initial position is (a) \(\underline{A}\) (b) \(4 \mathrm{~A}\) (c) \(8 \mathrm{~A}\) (d) zero

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