Chapter 15: Problem 14
A particle is acted simultaneously by mutually perpendicular simple hormonic motions \(x=a \cos \omega t\) and \(y=a \sin \omega t .\) The trajectory of motion of the particle will be [NCERT Exemplar] (a) an ellipse (b) a parabola \(\begin{array}{ll}\text { (c) a circle } & \text { (d) a straight line }\end{array}\)
Short Answer
Step by step solution
Analyze the equations of motion
Use trigonometric identities
Eliminate the parameter
Recognize the standard form of a conic
Conclude the trajectory
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Simple Harmonic Motion
- for the x-direction: \(x = a \cos \omega t\)
- for the y-direction: \(y = a \sin \omega t\)
SHM is not just an abstract concept; it is the basis for understanding many physical systems around us, from the motion of a pendulum in a clock to the vibrations of molecules.
Parametric Equations
- \(x = a \cos \omega t\)
- \(y = a \sin \omega t\)
By using parametric equations, each point on a trajectory or path is calculated in terms of the parameter \(t\). This flexibility makes them valuable in physics and engineering to model dynamic systems like the motion of a particle in this exercise.
Trigonometric Identities
- \(\cos^2\theta + \sin^2\theta = 1\)
By substituting \(\cos \omega t = \frac{x}{a}\) and \(\sin \omega t = \frac{y}{a}\) into this identity, and then substituting them into \(\cos^2 \omega t + \sin^2 \omega t = 1\), we get a simpler equation which describes the circle. Understanding and applying trigonometric identities such as this one is crucial for analyzing periodic motions like SHM.
Circle Equation
- \(\left(\frac{x}{a}\right)^2 + \left(\frac{y}{a}\right)^2 = 1\)
Understanding the structure of the circle equation is crucial in multiple fields including geometry, calculus, and even computer graphics, where defining circular paths becomes necessary.