/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 A body of mass \(120 \mathrm{~kg... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A body of mass \(120 \mathrm{~kg}\) and density \(600 \mathrm{kgm}^{-3}\) floats in water. What additional mass could be added to the body so that the body will just sink? (a) \(20 \mathrm{~kg}\) (b) \(\mathrm{BO} \mathrm{kg}\) (c) \(100 \mathrm{~kg}\) (d) \(120 \mathrm{~kg}\)

Short Answer

Expert verified
An additional mass of 80 kg would make the body just sink (option b).

Step by step solution

01

Understand the Concept of Buoyancy

A body floats in a fluid if its density is less than the fluid it is in because the buoyant force equals the weight of the displaced fluid. A body will sink if the buoyant force is less than the weight of the body.
02

Determine Water Density

The density of water is approximately \(1000 \mathrm{kg/m^3}\). We will use this value to calculate the volume of water displaced by the body.
03

Calculate Volume of the Body

The volume \(V\) of the body can be calculated using the formula for density: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). Thus, \( V = \frac{120 \text{ kg}}{600 \text{ kg/m}^3} = 0.2 \text{ m}^3\).
04

Calculate the Buoyant Force

The buoyant force can be calculated using Archimedes’ principle, which states that the force is equal to the weight of the displaced fluid: \( \text{Buoyant Force} = \rho_{\text{water}} \times V \times g \). Here \( g = 9.81 \text{ m/s}^2 \). So, \( \text{Buoyant Force} = 1000 \times 0.2 \times 9.81 = 1962 \text{ N}\).
05

Determine the Weight of the Body

The weight of the body is given by \( W = mg \). Thus \( W = 120 \times 9.81 = 1177.2 \text{ N}\).
06

Find Additional Mass Needed to Sink

For the body to just sink, the total weight \( W_{\text{total}} \) must equal the buoyant force: \( W_{\text{total}} = 1962 \text{ N} \). The weight of the body with additional mass \( x \) is \( (120 + x)\text{ kg} \times 9.81 \text{ m/s}^2 = 1962 \text{ N} \). Solving for \( x \): \( 1177.2 + 9.81x = 1962 \). \( 9.81x = 1962 - 1177.2 = 784.8 \). So, \( x = \frac{784.8}{9.81} = 80 \text{ kg}\).
07

Confirm the Correct Answer

We calculated that an additional mass of \(80\text{ kg}\) is needed for the body to just sink, matching option (b) from the given choices.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Archimedes' Principle
Archimedes' Principle is a fundamental concept in fluid mechanics. It dictates that a floating body will experience an upward buoyant force equivalent to the weight of the fluid it displaces.
This explains why objects can float or sink depending on their density compared to the fluid in which they are immersed. Floating occurs when the buoyant force matches or exceeds the weight of the object, while sinking happens if the object's weight outstrips the buoyant force.
This principle is not only crucial for understanding everyday phenomena, like why ships float, but also for solving physics problems related to buoyancy.
  • According to Archimedes, "Buoyant Force = Weight of Displaced Fluid."
  • This force relies directly on the volume and density of both the object and the fluid.
  • In exercises, to determine if an object will sink or float, compare its density with that of the fluid.
This principle guides many engineering applications, from designing flotation devices to building watercraft.
Density
Density is a measure of how much mass is contained in a given volume. It plays a pivotal role in determining whether an object will float or sink when it is immersed in a fluid. The formula for density is given by:\[\text{Density} = \frac{\text{Mass}}{\text{Volume}}\]A high-density object is more likely to sink in a less dense fluid, while a low-density object will float on a more dense fluid.
In the context of our problem, knowing the density of both the object and the surrounding fluid enables us to predict the outcomes related to buoyancy.
For instance:
  • The object in the problem had a density of 600 kg/m³, which is less than that of water (1000 kg/m³), allowing it to initially float.
  • To make the object sink, its effective density must increase beyond that of water, which can be done by adding more mass.
Understanding density gives insight into a material's composition and its interaction with surroundings.
Mass-Volume Relationship
The mass-volume relationship in the context of fluid mechanics helps us calculate important parameters like the volume of a body and, subsequently, the buoyant force it experiences in fluids.
This relationship is governed by the density formula: if you know any two of these variables—mass, volume, or density—you can determine the third.
This relationship is critical in the initial steps of solving buoyancy problems, such as the one presented:
  • The mass of the object was given as 120 kg, and its density 600 kg/m³, allowing the computation of its volume: 0.2 m³.
  • Knowing the volume and the density of water, the volume of displaced water and thus the buoyant force was determined.
  • These calculations aid in understanding how mass and volume affect the buoyancy and flotation characteristics of objects in fluid environments.
This concept underlays the practical applications of designing and predicting the behavior of submerged and floating objects.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If we dip capillary tubes of different radii \(r\) in water and the water rises to different height \(h\) in them, then we shall have constant (a) \(h / \underline{r^{2}}\) (b) \(h / r\) (c) \(h r^{2}\) (d) \(h r\)

A hemispherical bowl just floats without sinking in a liquid of density \(1.2 \times 10^{3} \mathrm{kgm}^{-3}\). If outer diameter and the density of the bowl are \(1 \mathrm{~m}\) and \(2 \times 10^{4} \mathrm{kgm}^{-3}\) respectively, then the inner diameter of the bowl will be (a) \(0.94 \mathrm{~m}\) (b) \(0.96 \mathrm{~m}\) (c) \(0.98 \mathrm{~m}\) (d) \(0.99 \mathrm{~m}\)

Two soap bubbles \(A\) and \(B\) are formed at the two open ends of a tube. The bubble \(A\) is smaller than bubble \(B\). Valve and air can flow freely between the bubbles, then (a] there is no change in the size of the bubbles (b) the two bubbles will become of equal size (c) \(A\) will become smaller and \(B\) will become larget (d) \(B\) will become smaller and \(A\) will become larger

Density of ice is \(\rho\) and that of water is \(\sigma\). What will be the decrease in volume when a mass \(M\) of ice melts? (a) \(\frac{M}{\sigma-\rho}\) (b) \(\frac{a-\rho}{M}\) (c) \(M\left(\frac{1}{\rho}-\frac{1}{\sigma}\right)\) (d) \(\frac{1}{M}\left(\frac{1}{\rho}-\frac{1}{\sigma}\right)\)

An aeroplane of \(\operatorname{mass} 3 \times 10^{4} \mathrm{~kg}\) and total wing area of \(120 \mathrm{~m}^{2}\) is in a level flight at some height. The difference in pressure between the upper and lower surfaces of its wings in kilo pascal is \(\left(g=10 \mathrm{~ms}^{-2}\right.\) ) (a) \(2.5\) (b) \(5.0\) (c) \(10.0\) (d) \(12.5\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.