Chapter 12: Problem 21
Two soap bubbles \(A\) and \(B\) are kept in closed chamber where the air is maintained at pressure \(8 \mathrm{~N} / \mathrm{m}^{2}\). The radius of bubbles \(A\) and \(B\) are \(2 \mathrm{em}\) and \(4 \mathrm{~cm}\) respectively surface tension of the soap water used to make bubbles is \(0.04 \mathrm{~N} / \mathrm{m}\). Find the ratio \(n_{B} / n_{A}\), where \(n_{A}\) and \(n_{B}\) are the number of moles of air in bubbles \(A\) and \(B\) respectively [Neglect the effect of gravity] (a) 2 (b) 9 (c) 8 (d) \(\overline{6}\)
Short Answer
Step by step solution
Understanding the Problem
Using the Equation for Excess Pressure in a Bubble
Calculating Excess Pressure for Bubble A
Calculating Excess Pressure for Bubble B
Determining Total Pressure Inside Bubbles
Applying Ideal Gas Law
Calculating Volume Ratio and Moles Ratio
Finalizing the Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Excess Pressure in Soap Bubbles
- \( P_{excess} \) is the excess pressure in the bubble.
- \( T \) is the surface tension of the soap film.
- \( r \) is the radius of the bubble.
Surface Tension and Radius
Volume and Moles Calculation
- \( P \) is the pressure inside the bubble.
- \( V \) is the volume of the bubble.
- \( n \) is the number of moles of air.
- \( R \) is the ideal gas constant.
- \( T \) is the absolute temperature (assumed constant).