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Two soap bubbles \(A\) and \(B\) are kept in closed chamber where the air is maintained at pressure \(8 \mathrm{~N} / \mathrm{m}^{2}\). The radius of bubbles \(A\) and \(B\) are \(2 \mathrm{em}\) and \(4 \mathrm{~cm}\) respectively surface tension of the soap water used to make bubbles is \(0.04 \mathrm{~N} / \mathrm{m}\). Find the ratio \(n_{B} / n_{A}\), where \(n_{A}\) and \(n_{B}\) are the number of moles of air in bubbles \(A\) and \(B\) respectively [Neglect the effect of gravity] (a) 2 (b) 9 (c) 8 (d) \(\overline{6}\)

Short Answer

Expert verified
(d) 6

Step by step solution

01

Understanding the Problem

We need to determine the ratio of the moles of air in two soap bubbles, A and B. The given parameters are the external pressure, the radii of the bubbles, and the surface tension of the soap water. We are to find the ratio of moles in bubbles A and B based on these inputs.
02

Using the Equation for Excess Pressure in a Bubble

For a soap bubble, the excess pressure inside the bubble over the external pressure is given by: \[ P_{excess} = \frac{4T}{r} \]where \(T\) is the surface tension and \(r\) is the radius of the bubble. We will calculate this excess pressure for both bubbles A and B.
03

Calculating Excess Pressure for Bubble A

For bubble A, with radius \(r_A = 2 \text{ cm}\), the excess pressure \(P_{A}\) is:\[ P_{A} = \frac{4 \times 0.04}{0.02} = 8 \text{ N/m}^2 \]
04

Calculating Excess Pressure for Bubble B

For bubble B, with radius \(r_B = 4 \text{ cm}\), the excess pressure \(P_{B}\) is:\[ P_{B} = \frac{4 \times 0.04}{0.04} = 4 \text{ N/m}^2 \]
05

Determining Total Pressure Inside Bubbles

The total pressure inside each bubble is the sum of the external pressure and the excess pressure. Therefore:- For bubble A: \( P_{inside, A} = 8 + 8 = 16 \text{ N/m}^2 \)- For bubble B: \( P_{inside, B} = 8 + 4 = 12 \text{ N/m}^2 \)
06

Applying Ideal Gas Law

According to the ideal gas law, \(PV = nRT\). Assuming temperature and the gas constant are constant for both, we have:\[ n_A = \frac{P_{inside, A} \times \frac{4}{3}\pi r_A^3}{RT} \]\[ n_B = \frac{P_{inside, B} \times \frac{4}{3}\pi r_B^3}{RT} \]
07

Calculating Volume Ratio and Moles Ratio

The volume ratio gives us \(\left(\frac{r_B}{r_A}\right)^3 = \left(\frac{4}{2}\right)^3 = 8\). Thus, the moles ratio simplifies to:\[ \frac{n_B}{n_A} = \frac{P_{inside, B} \times V_B}{P_{inside, A} \times V_A} = \frac{12 \times 8}{16} = 6 \]
08

Finalizing the Answer

Based on our calculations, the ratio of the number of moles \(n_B/n_A\) is 6.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Excess Pressure in Soap Bubbles
In soap bubbles, the air inside is not at the same pressure as the air outside. This difference in pressure is known as excess pressure. Soap bubbles are surrounded by a thin layer of soap which has a certain surface tension. This tension causes the bubble to maintain a spherical shape and contributes to the excess pressure inside the bubble. Excess pressure in a soap bubble can be mathematically expressed as:\[ P_{excess} = \frac{4T}{r} \]Where:
  • \( P_{excess} \) is the excess pressure in the bubble.
  • \( T \) is the surface tension of the soap film.
  • \( r \) is the radius of the bubble.
With small bubbles, the excess pressure is higher because the radius \( r \) is smaller, making \( P_{excess} \) larger. In larger bubbles, such as bubble B in the problem, the excess pressure is less because the radius is larger.
Surface Tension and Radius
Surface tension is a force that acts on the surface of a liquid, which makes it behave like a stretched elastic membrane. In the case of soap bubbles, it is this surface tension that holds the bubble together. The radius of a bubble significantly affects its surface tension and its related physics. Larger bubbles have smaller excess pressure due to their larger radius, while smaller bubbles have bigger excess pressure due to their smaller radius. This relationship is inversely proportional and is a critical concept when understanding how bubbles behave in different conditions. For example, the surface tension of the soap solution remains constant, but as the radius changes, the pressure inside also changes due to excess pressure calculations as seen earlier. Understanding how surface tension and radius interact can help in predicting how easily a bubble will grow or burst. This interaction is essential in studying properties related to fluid dynamics and material science.
Volume and Moles Calculation
The volume of a bubble is critical when applying the Ideal Gas Law to calculate the number of moles of gas inside. The volume of a sphere, such as a bubble, is given by the formula:\[ V = \frac{4}{3} \pi r^3 \]Where \( V \) is the volume and \( r \) is the radius. This formula must be combined with the Ideal Gas Law, \( PV = nRT \), to calculate the number of moles \( n \) within the bubble.From the Ideal Gas Law equation:
  • \( P \) is the pressure inside the bubble.
  • \( V \) is the volume of the bubble.
  • \( n \) is the number of moles of air.
  • \( R \) is the ideal gas constant.
  • \( T \) is the absolute temperature (assumed constant).
By putting the pressure and volume of each bubble in the equation, you can find how many moles of gas are present. This approach helps in studying gas behavior in confined spaces, illustrating how pressure, volume, and temperature can influence the number of moles, and in this case, the burst of the bubble.

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