/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 A substance breaks down by a str... [FREE SOLUTION] | 91Ó°ÊÓ

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A substance breaks down by a stress of \(10^{6} \mathrm{Nm}^{-2}\). If the density of the material of the wire is \(3 \times 10^{3} \mathrm{~kg} \mathrm{~m}^{-2}\), then the length of the wire of the substance which will break under its own weight when suspended vertically is (a) \(66.6 \mathrm{~m}\) (b) \(60.0 \mathrm{~m}\) (c) \(33.3 \mathrm{~m}\) (d) \(30.0 \mathrm{~m}\)

Short Answer

Expert verified
The wire will break at a length of approximately 33.3 meters.

Step by step solution

01

Understand the Problem

We need to determine the length of the wire hanging vertically that would break under its own weight. The breaking stress and density of the material are provided. The goal is to find the length at which the stress due to the weight of the wire reaches the breaking stress.
02

Define Breaking Condition

The wire will break when the stress due to its own weight equals the breaking stress. This can be expressed as \( \sigma = \rho \cdot g \cdot L \), where \( \sigma \) is the breaking stress, \( \rho \) is the density, \( g \) is the acceleration due to gravity (approximately \( 9.8 \mathrm{~m/s^2} \)), and \( L \) is the length of the wire.
03

Substitute Given Values

Substitute the given values into the equation: breaking stress \( \sigma = 10^6 \mathrm{Nm}^{-2} \) and density \( \rho = 3 \times 10^3 \mathrm{~kg/m^3} \). The equation becomes: \( 10^6 = 3 \times 10^3 \times 9.8 \times L \).
04

Solve for Length \( L \)

Rearrange the equation to solve for \( L \), \( L = \frac{10^6}{3 \times 10^3 \times 9.8} \).
05

Calculate Length

Plug the numbers into the equation: \[ L = \frac{10^6}{3 \times 10^3 \times 9.8} = \frac{10^6}{29400} \approx 33.33 \]. Thus, the length \( L \approx 33.3 \mathrm{~m} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stress-Strain Relationship
The stress-strain relationship is a fundamental concept in material science. Stress is defined as the force applied per unit area on a material. Strain, on the other hand, is the deformation or change in dimension caused by the applied stress. Understanding this relationship helps to predict how materials will behave under various forces.

In our scenario, the stress caused by the weight of the hanging wire is what leads to its eventual breaking. If the material reaches its breaking stress, it will fail or break. Mathematically, stress can be expressed as \( \sigma = \frac{F}{A} \), where \( F \) is the force exerted, and \( A \) is the cross-sectional area.

The breaking stress provides a threshold value beyond which the material cannot sustain the applied force without failure. This exercise demonstrates the importance of knowing the breaking limit of materials to ensure safety and durability in practical applications.
Material Density
Density is a physical property that describes how much mass is contained in a given volume of a material. It is expressed in units of kilograms per cubic meter (\( \mathrm{kg/m^3} \)). The density of a material affects its weight and behavior when forces are applied.

In this problem, the wire has a density of \( 3 \times 10^3 \mathrm{kg/m^3} \). This value is used in the calculation for determining the length at which the wire will break. The higher the density, the heavier the material, meaning more weight stress will act on its own length when suspended vertically.

Understanding material density is crucial when designing structures to ensure they can withstand their own weight, especially when designing for high-rise buildings, bridges, or any vertically-oriented structures.
Gravitational Force
Gravitational force is the force by which a planet or other celestial body draws objects towards its center. On Earth, this force gives us our sense of weight. Mathematically, it is defined as \( F = m \cdot g \), where \( m \) is mass and \( g \) is the acceleration due to gravity, approximately \( 9.8 \mathrm{m/s^2} \) on Earth's surface.

The gravity-induced force acts downward on the wire, and the longer the wire, the more force it experiences due to its own mass. This force contributes to the stress in the material, which we calculated to see if it reaches the breaking stress.

Understanding gravitational force is key to calculating the stress experienced by objects. This is particularly important in engineering, where the structural integrity of buildings and bridges must account for both the gravitational force and additional loads they might bear.
Length Calculation
Calculating the maximum length that a vertical wire can hang without breaking involves understanding the stress that results due to its weight. The given problem provides a breaking stress of \(10^6 \mathrm{Nm}^{-2}\) and density of \(3 \times 10^3 \mathrm{~kg/m^3}\).

Using the formula \( \sigma = \rho \cdot g \cdot L \), we substitute the values to find the length \( L \):
  • Breaking stress \( \sigma = 10^6 \mathrm{Nm}^{-2} \)
  • Density \( \rho = 3 \times 10^3 \mathrm{~kg/m^3} \)
  • Gravitational acceleration \( g = 9.8 \mathrm{m/s^2} \)
Substituting, we solve for \( L \):\[L = \frac{10^6}{3 \times 10^3 \times 9.8} \approx 33.3 \mathrm{~m}.\]This calculation shows that a wire with a length greater than 33.3 meters will break under its own weight. Understanding length calculation in such contexts is essential in real-world applications like designing cables and structures that must withstand their own gravitational load.

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