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At what height above the earth's surface, does the force of gravity decrease by \(10 \% ?\) The radius of the earth is \(6400 \mathrm{~km} ?\) (a) \(345.60 \mathrm{~km}\) (b) \(687.20 \mathrm{~km}\) (c) \(1031.8 \mathrm{~km}\) (d) \(12836.80 \mathrm{~km}\)

Short Answer

Expert verified
345.60 km

Step by step solution

01

Understand the Problem

We need to find the height above the Earth's surface where the gravitational force is reduced by 10% of its value on the surface. We're given the radius of the Earth as 6400 km.
02

Apply Gravitational Formula

The gravitational force at a distance \( r \) from the center of the Earth is given by \( F = \frac{G M m}{r^2} \), where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, and \( m \) is the mass of the object.
03

Set Up the Equation

Let the force of gravity at the Earth's surface be \( F_0 \). At a height \( h \), the force is reduced to 10% less, or 90% of the original force. Therefore, \( F_h = 0.9 F_0 \).
04

Compute Forces Using Ratios

The force at the Earth's surface is \( F_0 = \frac{G M m}{(6400)^2} \). At height \( h \), we have \( F_h = \frac{G M m}{(6400 + h)^2} \). Set \( F_h = 0.9 F_0 \) and substitute the expressions: \[ \frac{G M m}{(6400 + h)^2} = 0.9 \frac{G M m}{(6400)^2} \].
05

Solve for Height h

Cancel \( G M m \) from both sides: \[ \frac{1}{(6400+h)^2} = 0.9 \frac{1}{6400^2} \]. Rearrange and solve for \( h \): \( (6400 + h)^2 = \frac{6400^2}{0.9} \). Take the square root: \( 6400 + h = \sqrt{ \frac{6400^2}{0.9} } \).
06

Simplify and Calculate Height

Solve for \( h \): \( 6400 + h = \frac{6400}{\sqrt{0.9}} \). Calculate \( \sqrt{0.9} \approx 0.9487 \). Thus, \( 6400 + h = \frac{6400}{0.9487} \approx 6745.693 \). So, \( h \approx 6745.693 - 6400 = 345.693 \) km.
07

Choose the Closest Answer

Among the given options, the closest value to our calculated height \( 345.693 \) km is (a) 345.60 km.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Earth's Radius
Understanding Earth's radius is essential for many calculations related to gravity and space. Earth's radius is the distance from the center of the Earth to its surface which in this exercise is given as 6400 kilometers. This measurement is crucial in determining how gravitational forces change as you move away from the surface.

The radius is a baseline for calculations, as it allows us to estimate distances and forces acting upon objects when they are moved vertically from the Earth. Whether you're working with satellites or simply calculating the impact of gravity at different heights, knowing Earth's radius gives a starting point to determine how height alters gravitational pull.
Gravitational Formula
The gravitational formula is central to understanding how planets and objects interact through the force of gravity. This formula is expressed as: \[ F = \frac{G M m}{r^2} \] where:
  • \( F \) is the gravitational force
  • \( G \) is the gravitational constant
  • \( M \) is the mass of the larger object (like Earth)
  • \( m \) is the mass of an object experiencing the force
  • \( r \) is the distance from the center of the mass
This formula shows that gravitational force is inversely proportional to the square of the distance between two objects. This means that as you move farther from the Earth, the gravitational force decreases quickly. Using this formula, one can calculate the forces exerted on objects at varying distances from Earth.
Forces Ratio
When you need to determine how much gravity decreases at a height above Earth's surface, using a forces ratio helps simplify calculations. Suppose the gravitational force on Earth's surface is \( F_0 \). At a certain height, it becomes less than \( F_0 \)—this is where the forces ratio is applied. Such tasks involve expressions like:
\[ F_h = 0.9 F_0 \] where \( F_h \) is the force at height \( h \) above Earth.

To use the forces ratio effectively, we adapt the formula given for gravity at Earth's surface and at height \( h \): \[ \frac{G M m}{(6400 + h)^2} = 0.9 \frac{G M m}{6400^2} \]. By simplifying these equations, you eliminate common variables to focus on the distance and proportional change of forces.
Height Calculation
Calculating the height at which the force of gravity decreases by a certain percentage can be intriguing. Once we have arranged the forces ratio, the next step is to solve for \( h \). You find \( h \) by rearranging the equation as:\[ (6400 + h)^2 = \frac{6400^2}{0.9} \].

After setting the equation, taking the square root helps isolate \( h \): \[ 6400 + h = 6400 / \sqrt{0.9} \]. Solving for this value, you find that \( \sqrt{0.9} \approx 0.9487 \). Simplifying gives: \[ 6400 + h \approx 6745.693 \]. Therefore, \( h \approx 345.693 \text{ km} \), which when analyzed against given options, most closely matches with 345.60 km. Understanding each step in the calculation helps students grasp not only the final result but also the significance behind the math.

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Most popular questions from this chapter

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