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The height at which the acceleration due to gravity decreases by \(36 \%\) of its value on the surface of the earth. (The radius of the earth is \(R\) ). (a) \(\frac{R}{6}\) (b) \(\frac{R}{4}\) (c) \(\frac{R}{2}\) (d) \(\frac{2}{3} R\)

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01

Understanding Gravity’s Variation with Height

The acceleration due to gravity (abla gabla gdabla g = \frac{GM}{R^2} \frac{GM}{R^2} \frac{GM}{R^2} \frac{GM}{R^2}) is inversely proportional to the square of the distance from the center of the Earth, meaning it decreases with increasing height. It is related to the height above the surface by \( g_h = g \left( \frac{R}{R + h} \right)^2 \) where \( g_h \) is the gravity at height \( h \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is a fundamental force of nature that attracts two masses towards each other. This force happens because any object with mass exerts a force on other objects with mass.
The Earth, being massive, exerts a significant gravitational force that pulls objects towards its center. The formula for gravitational force is given by Newton's law of universal gravitation:
  • Formula: \( F = \frac{G \cdot m_1 \cdot m_2}{r^2} \)
  • Where \( F \) is the gravitational force, \( G \) is the universal gravitational constant, \( m_1 \) and \( m_2 \) are the masses involved, and \( r \) is the distance between the centers of the two masses.
By understanding this, it's clear that gravitational force decreases when the distance between two masses increases. This principle helps explain why as you move farther from the Earth's surface, the gravitational pull weakens.
This is an important concept to grasp when studying how gravity changes with altitude.
Variation of Gravity with Altitude
When you increase your altitude, say by climbing a mountain or flying in an airplane, the gravitational force exerted by the Earth decreases. Simply put, the further you are from the Earth's center, the less gravitational pull there is on you.
Gravity on the Earth's surface is strongest at sea level. As you ascend, the strength of gravity diminishes. The rate at which gravity decreases with altitude can be estimated using the formula:
  • \( g_h = g \left( \frac{R}{R + h} \right)^2 \)
  • Where \( g_h \) is the gravity at height \( h \), \( g \) is the standard gravity at the Earth's surface, and \( R \) is the Earth's radius.
This formula shows that gravity decreases significantly only at large heights compared to the Earth’s radius.
For everyday altitudes like the height of Mount Everest, the change in gravitational acceleration is relatively small.
Inverse Square Law
The inverse square law is a pivotal principle in physics that describes how a physical quantity decreases with the square of the distance from the source. This concept heavily influences how gravity operates in our universe.
For gravity, this law states that the force decreases proportionally to the square of the distance from the Earth's center. When we talk about the inverse square law in terms of gravity:
  • As the distance \( r \) increases, gravitational force \( F \) decreases as \( \frac{1}{r^2} \).
  • For example, doubling the distance from the Earth's center will cause the gravitational force to decrease by a factor of four (\(2^2\)).
This is why gravity becomes weaker at higher altitudes and distances.
Understanding the inverse square law helps in computing gravity's weakening effect as one moves away from the Earth's surface, providing significant insights into how our world works.

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Most popular questions from this chapter

A space ship moves from earth to moon and back. Th. greatest energy required for the space ship is \(t\) overcome the difficulty in (a) entering the earth's gravitational field (b) take off from earth's field (c) take off from lunar surface (d) entering the moon's lunar surface

A comet of mass \(m\) moves in a highly elliptical orbit around the sun of mass \(M\). The maximum and minimum distances of the comet from the centre of the sun are \(r_{1}\) and \(r_{2}\) respectively. The magnitude of angular momentum of the comet with respect to the centre of sun is (a) \(\left[\frac{G M r_{1}}{\left(r_{1}+r_{2}\right)}\right]^{1 / 2}\) (b) \(\left[\frac{G M m r_{1}}{\left(r_{1}+r_{2}\right)}\right]^{1 / 2}\) (c) \(\left(\frac{2 G m^{2} r_{12}}{r_{1}+r_{2}}\right)^{1 / 2}\) (d) \(\left(\frac{2 G M m^{2} r_{12}}{\left(r_{1}+r_{2}\right)}\right)^{1 / 2}\)

The gravitational attraction between the two bodies increases when their masses are (a) reduced and distance is reduced (b) increased and distance is reduced (c) reduced and distance is increased (d) increased and distance is increased

The earth is an approximate sphere. If the interior contained matter which is not of the same density everywhere, then on the surface of the earth, the acceleration due to gravity \(\quad\) [NCERT Exemplar] (a) will be directed towards the centre but not the same everywhere (b) will have the same value everywhere but not directed towards the centre (c) will be same everywhere in magnitude directed towards the centre (d) cannot be zero at any point

At a distance \(320 \mathrm{~km}\) above the surface of earth, the value of acceleration due to gravity will be lower than its value on the surface of the earth by nearly (radius of earth \(=6400 \mathrm{~km}\) ) (a) \(2 \%\) (b) \(6 \%\) (c) \(10 \%\) (d) 1496

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