/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 The photograph of a house occupi... [FREE SOLUTION] | 91Ó°ÊÓ

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The photograph of a house occupies an area of \(1.75 \mathrm{~cm}^{2}\) on a \(35 \mathrm{~mm}\) slide. The slide is projected on to a screen and the area of the house on the screen is \(1.55 \mathrm{~m}^{2}\). The linear magnification of the projector-screen arrangement, is (a) \(84.1\) (b) \(96.1\) (c) \(94.1\) (d) \(86.1\)

Short Answer

Expert verified
The linear magnification is 94.1 (option c).

Step by step solution

01

Understanding the Concept of Magnification

Linear magnification is the ratio of the dimension of an image to the dimension of the original object. In terms of area, magnification can be determined as the square root of the area magnification ratio.
02

Convert Units if Necessary

The photograph area is given in square centimeters (\(1.75 \mathrm{~cm}^2\)) and the screen area in square meters (\(1.55 \mathrm{~m}^2\)). Both should be in the same unit before proceeding. \Convert the screen area to square centimeters: \\[1.55 \mathrm{~m}^2 = 1.55 \times 10^4 \mathrm{~cm}^2 = 15500 \mathrm{~cm}^2\]
03

Calculate the Area Magnification Ratio

Determine the ratio of the screen area to the photograph area: \[\text{Area Magnification Ratio} = \frac{\text{Screen Area}}{\text{Photograph Area}} = \frac{15500 \mathrm{~cm}^2}{1.75 \mathrm{~cm}^2} = 8857.14\]
04

Determine the Linear Magnification

Since magnification based on area is related to the square of linear magnification, compute linear magnification by taking the square root of the area magnification ratio: \[\text{Linear Magnification} = \sqrt{8857.14} \approx 94.1\]
05

Identify the Correct Answer

Compare the computed linear magnification, 94.1, with the given options. The correct answer is option (c) \(94.1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Area Magnification Ratio
When examining the concept of area magnification ratio, we're essentially looking at how much larger or smaller an image appears compared to its original size. In this exercise, the area magnification ratio is calculated by finding the ratio between the area of the image on the screen and the area of the image on the slide. The formula used is: \[ \text{Area Magnification Ratio} = \frac{\text{Screen Area}}{\text{Photograph Area}} \]. For our scenario, the screen area is 15500 square centimeters and the photograph area is 1.75 square centimeters. Thus, the area magnification ratio becomes \( \frac{15500}{1.75} = 8857.14 \). This ratio is crucial because it tells us how much the area has been magnified during the projection process. When dealing with such problems, always ensure both areas are in the same units to avoid any errors.
Unit Conversion
Converting between units is an essential step in problems involving measurements of different unit systems. In this exercise, the area of the house on the screen is initially provided in square meters, whereas the photograph's area is in square centimeters. To accurately compute the area magnification ratio, it's necessary to convert the screen's area into square centimeters.Remember that 1 square meter equals 10,000 square centimeters because each meter consists of 100 centimeters, both in width and length. Therefore, when converting square meters to square centimeters, multiply the given area by 10,000. So, from the example, \(1.55 \text{ m}^2 = 1.55 \times 10^4 \text{ cm}^2 = 15500 \text{ cm}^2\). By converting all measurements into the same unit, we ensure that calculations such as ratios are valid and meaningful.
Projector-Screen Arrangement
In a projector-screen setup, linear magnification determines how much larger the image on the screen is compared to the object itself, which is in this case, the photograph on the slide. The term linear magnification specifically refers to the ratio of the image size to the original size in terms of length.However, since we're dealing with areas, the linear magnification needs to be derived from the area magnification ratio by taking its square root. This is because area magnification is the square of linear magnification. For our exercise, \[ \text{Linear Magnification} = \sqrt{\text{Area Magnification Ratio}} = \sqrt{8857.14} \approx 94.1 \].Therefore, in the context of a projector-screen, this means that every linear dimension of the image is enlarged nearly 94.1 times compared to the slide dimensions. This clarifies why, when working with projectors, understanding both linear and area magnification is vital for achieving the desired image size.

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