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The dimensional formula of coefficient of permittivity for free space \(\left(\varepsilon_{0}\right)\) is (a) \(\left[\mathrm{ML}^{3} \mathrm{~A}^{-2} \mathrm{~T}^{-4}\right]\) (b) \(\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{4} \mathrm{~A}^{2}\right]\) (c) \(\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~A}^{-2} \mathrm{~T}^{-4}\right]\) (d) \(\left[M L^{3} A^{2} T^{-4}\right]\)

Short Answer

Expert verified
The dimensional formula of \(\varepsilon_{0}\) is \(\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{4} \mathrm{~A}^{2}\right]\), matching option (b).

Step by step solution

01

Understand the Given Problem

We need to find the dimensional formula for the coefficient of permittivity of free space, denoted as \( \varepsilon_0 \). This will involve understanding the related physical laws and dimensions involved.
02

Recall the Relevant Physical Formula

The coefficient of permittivity \( \varepsilon_0 \) appears in the formula for Coulomb's law of electrostatics for force between two point charges: \[ F = \dfrac{1}{4\pi\varepsilon_0} \dfrac{q_1q_2}{r^2}\]In this formula, \( F \) is the force, \( q_1 \) and \( q_2 \) are charges with the dimension \([\mathrm{I}\mathrm{T}]\), and \( r \) is the distance between charges.
03

Find the Dimensional Formula for Force

Using Newton's law, the dimensional formula for force \( F \) is: \[ F = [\mathrm{MLT}^{-2}]\]
04

Determine the Units of \( q_1q_2 \) and \( r^2 \)

The charge \( q \) has the dimension: \[ [\mathrm{I}\mathrm{T}] \]Thus, the product \( q_1 q_2 \) has the dimension: \[ [\mathrm{I}^2 \mathrm{T}^2] \]Distance \( r \) has the dimension: \[ [\mathrm{L}] \]Thus, \( r^2 \) has the dimension: \[ [\mathrm{L}^2] \]
05

Compute the Dimensional Formula for \( \varepsilon_0 \)

Rewriting Coulomb's law:\[ \varepsilon_0 = \dfrac{q_1 q_2}{4\pi r^2 F} \]Substitute dimensions:\[ [\varepsilon_0] = \dfrac{[\mathrm{I}^2 \mathrm{T}^2]}{[\mathrm{L}^2][\mathrm{MLT}^{-2}]} \]Simplification results in:\[ [\varepsilon_0] = [\mathrm{M}^{-1} \mathrm{L}^{-3} \mathrm{T}^{4} \mathrm{A}^{2}] \]
06

Match the Result with the Given Options

Compare our derived dimensional formula \([\mathrm{M}^{-1} \mathrm{L}^{-3} \mathrm{T}^{4} \mathrm{A}^{2}]\) with the options. It matches option (b).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Permittivity
The coefficient of permittivity is a fundamental concept in electromagnetism. It quantifies how much electric field (or force) is allowed to permeate a certain medium. Particularly, in a vacuum or free space, it's denoted by the symbol \( \varepsilon_0 \). This is also known as the permittivity of free space.
The coefficient plays a crucial role in determining the strength of electric forces between charges. It appears prominently in Coulomb's Law as a factor governing interactions in free space. Understanding this coefficient is key to solving many problems in electrostatics and understanding the behavior of electric fields in various media.
Coulomb's Law
Coulomb's Law is a pivotal theory in electrostatics that explains how forces act between electrically charged particles. Named after the French physicist Charles-Augustin de Coulomb, this law forms the foundation of understanding interactions in electric fields.
The law is mathematically represented as: \[ F = \frac{1}{4\pi\varepsilon_0} \frac{q_1q_2}{r^2} \] Here, \(F\) denotes the force between charges \(q_1\) and \(q_2\), which are separated by a distance \(r\). Within this formula, \(\varepsilon_0\) represents the permittivity of free space, acting as a moderating factor for the interaction strength.
Coulomb's Law helps us understand how charged particles attract or repel each other, directly influencing real-world phenomena like lightning, the operation of electronic devices, and even atomic structure.
Dimensional Formula Calculation
Dimensional analysis is a powerful tool to verify equations or deduce new ones. It's the method used to find the dimensional formula for physical quantities, allowing us to understand how different units relate.
To find the dimensional formula of the coefficient of permittivity (\(\varepsilon_0\)), one must consider the dimensions of each element in Coulomb's Law.
- Start with the force \( F \), which has dimensions \([MLT^{-2}]\). - The charge \(q\) has dimensions \([IT]\), leading to \(q_1q_2\) being \([I^2T^2]\). - The distance \(r\) is simply \([L]\), making \(r^2\) equal to \([L^2]\).
Using the relationship \(\varepsilon_0 = \frac{q_1q_2}{4\pi r^2 F}\), we substitute these dimensions, resulting in \([M^{-1}L^{-3}T^4A^2]\). This is the dimensional formula for \(\varepsilon_0\), helping verify the consistency of physics laws.
Electrostatics
Electrostatics is the branch of physics that studies stationary electric charges. Unlike moving charges that generate magnetic fields, electrostatics focuses on the forces and fields resulting from charges at rest. This study provides the basis for understanding electric forces in various materials.
Main concepts in electrostatics include:
  • Electric Charge: The intrinsic property of matter responsible for electric forces; can be positive or negative.
  • Electric Field: A field around a charged particle where forces are exerted on other charges.
  • Electric Potential: The potential energy per unit charge at a point in a field.
Electrostatics plays critical roles in numerous technologies, from capacitors storing energy in circuits to understanding forces at molecular levels in chemistry and biology. It helps in designing circuits, predicting molecule behaviors, and even in new medical technologies.

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Most popular questions from this chapter

Which of the following units denotes the dimensions \(\left[\mathrm{ML}^{2} / Q^{2}\right]\), where \(Q\) denotes the electric charge? [AIEEE 2006] (a) Henry (b) \(\mathrm{Hm}^{-2}\) (c) Weber (Wb) (d) \(\mathrm{Wbm}^{-2}\)

The pressure on a square plate is measured by measuring the force on the plate and the length of the sides of the plate by using the formula \(p=\frac{F}{l^{2}}\).If the maximum errors in the measurement of force and length are \(4 \%\) and \(2 \%\) respectively, then the maximum error in the measurement of pressure is (a) \(1 \%\) (b) \(2 \%\) (c) \(8 \%\) (d) \(10 \%\)

If \(1 \mathrm{~g} \mathrm{~cm} \mathrm{~s}^{-1}=x\) newton-sec, then the number \(x\) is equal to (a) \(1 \times 10^{-3}\) (b) \(3.6 \times 10^{-3}\) (c) \(1 \times \underline{10^{-5}}\) (d) \(6 \times \underline{10^{-4}}\)

Which of the following is the most precise device for measuring length? (a) A vernier callipers with 20 divisions on the sliding scale (b) A screw gauge of pitch \(1 \mathrm{~mm}\) and 100 divisions on the circular scale (c) An optical instrument that can measure length to within a wavelength of light? (d) All are equally precise device for measuring length

The velocity \(v\) of water waves may depend on their wavelength \((\lambda)\), the density of water \((\rho)\) and the acceleration due to gravity \((\mathrm{g})\). The method of dimensions gives the relation between these quantities as (a) \(v^{2} \propto \lambda^{-1} \rho^{-1}\) (b) \(v^{2} \propto g \lambda\) (c) \(v^{2} \propto g \lambda \rho\) (d) \(g^{-1} \propto \lambda\)

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