/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A blimp is initially at rest, ho... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A blimp is initially at rest, hovering, when at \(t=0\) the pilot turns on the engine driving the propeller. The engine cannot instantly get the propeller going, but the propeller speeds up steadily. The steadily increasing force between the air and the propeller is given by the equation \(F=k t\), where \(k\) is a constant. If the mass of the blimp is \(m\), find its position as a function of time. (Assume that during the period of time you're dealing with, the blimp is not yet moving fast enough to cause a significant backward force due to air resistance.)

Short Answer

Expert verified
The position of the blimp is \(x(t) = \frac{k}{6m} t^3\).

Step by step solution

01

Understanding the problem

The blimp is initially at rest at time \(t=0\), and a force \(F=k t\) is applied to it as the propeller speeds up. We need to find the position of the blimp as a function of time, which involves integrating the acceleration to find velocity and then integrating velocity to find position.
02

Expressing Acceleration

The force exerted on the blimp is given by \(F=k t\). Using Newton's Second Law, \(F=ma\), where \(a\) is acceleration, we express the acceleration as \(a = \frac{F}{m} = \frac{k t}{m}\).
03

Integrating Acceleration to find Velocity

To find the velocity \(v(t)\), we integrate the acceleration with respect to time. Since the acceleration \(a = \frac{k t}{m}\), we have:\[v(t) = \int a(t) \, dt = \int \frac{k t}{m} \, dt = \frac{k}{m} \int t \, dt = \frac{k}{m} \frac{t^2}{2} + C_1\]Since the blimp is initially at rest when \(t=0\), \(v(0)=0\), it follows that \(C_1 = 0\), so:\[v(t) = \frac{k}{2m} t^2\]
04

Integrating Velocity to find Position

Next, we integrate the velocity to determine the position \(x(t)\) of the blimp:\[x(t) = \int v(t) \, dt = \int \frac{k}{2m} t^2 \, dt = \frac{k}{2m} \int t^2 \, dt = \frac{k}{2m} \frac{t^3}{3} + C_2\]Given that the blimp is initially at \(x=0\) when \(t=0\), we can solve for \(C_2\). Substituting \(x(0)=0\), \(C_2\) must be 0, thus:\[x(t) = \frac{k}{6m} t^3\]
05

Final Position Function

The final expression for the position of the blimp as a function of time is given by the cubic equation:\[x(t) = \frac{k}{6m} t^3\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law of Motion is fundamental in understanding how forces affect the motion of objects. It states that the force acting on an object is equal to the mass of that object multiplied by its acceleration, mathematically represented as \( F = ma \).
This law helps us determine how a force will change the motion of an object. In the case of the blimp in our problem, a force \( F = kt \) is applied. Here, \( k \) is a constant and \( t \) is time.
The law tells us that the force results in an acceleration of the blimp. Since the blimp starts at rest, we first solve \( F = ma \) to find the acceleration \( a = \frac{F}{m} = \frac{kt}{m} \).
The beauty of Newton's Second Law is its ability to connect dynamics—how a force leads to acceleration—with the kinematic equations, which describe motion.
Integration
Integration is a mathematical technique used to find quantities like area under a curve, or to go from a rate of change (like acceleration) to an accumulated total (like velocity). In this problem, we use integration to find both velocity and position from acceleration.
First, we integrate acceleration to find velocity. We have \( a = \frac{kt}{m} \), so we integrate this expression with respect to time \( \int a(t) \, dt \). This gives us the velocity function \( v(t) = \frac{k}{2m} t^2 \), taking into account that the initial velocity is zero.
Next, to find the blimp's position as a function of time, we integrate the velocity function \( v(t) \).
  • Velocity \( v(t) \) represents the rate of change of the position.
  • By integrating \( v(t) = \frac{k}{2m} t^2 \), we find the position equation \( x(t) = \frac{k}{6m} t^3 \).
The process of integration is crucial here as it lets us transition from knowing how fast things change to knowing the state of motion.
Acceleration
Acceleration is the rate of change of velocity with respect to time. It's a vector quantity, which means it has both magnitude and direction. In scenarios governed by linear motion—like the blimp—acceleration tells us how quickly velocity is increasing or decreasing.
In this problem, the blimp's acceleration comes from the force exerted by the propeller, described by \( a = \frac{F}{m} = \frac{kt}{m} \).
  • As time progresses, the force—and hence the acceleration—increases linearly since \( F = kt \).
  • This results in a quadratic increase in velocity because velocity is the integral of acceleration.
Essentially, the steady increase in force ensures that the acceleration also steadily increases over time, gradually speeding up the blimp.
Velocity
Velocity indicates how fast something is moving in a specific direction. It's different from speed since it includes direction. In our exercise, once we know the acceleration \( a = \frac{kt}{m} \), we can find the velocity by integrating the acceleration over time.
The blimp starts from rest, so its initial velocity is zero. We find the velocity function by the integral:
\[ v(t) = \int a(t) \, dt = \frac{k}{2m} t^2 \]
This shows that velocity is not just a simple function of time \( t \), but of time squared \( t^2 \).
  • This quadratic nature indicates that as time goes on, the blimp gains speed more rapidly.
  • The blimp starts slowly, but its velocity increases as \( t \) increases.
This insight into velocity helps us understand how objects accelerate and gain speed over time due to an applied force.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An object is observed to be moving at constant speed in a certain direction. Can you conclude that no forces are acting on it? Explain. [Based on a problem by Serway and Faughn.

At low speeds, every car's acceleration is limited by traction, not by the engine's power. Suppose that at low speeds, a certain car is normally capable of an acceleration of \(3 \mathrm{~m} / \mathrm{s}^{2} .\) If it is towing a trailer with half as much mass as the car itself, what acceleration can it achieve? [Based on a problem from PSSC Physics.]

When I cook rice, some of the dry grains always stick to the measuring cup. To get them out, I turn the measuring cup upsidedown and hit the "roof" with my hand so that the grains come off of the "ceiling." (a) Explain why static friction is irrelevant here. (b) Explain why gravity is negligible. (c) Explain why hitting the cup works, and why its success depends on hitting the cup hard enough.

(a) Let \(T\) be the maximum tension that an elevator's cable can withstand without breaking, i.e., the maximum force it can exert. If the motor is programmed to give the car an acceleration \(a(a>0\) is upward), what is the maximum mass that the car can have, including passengers, if the cable is not to break? (b) Interpret the equation you derived in the special cases of \(a=0\) and of a downward acceleration of magnitude \(g\). ("Interpret" means to analyze the behavior of the equation, and connect that to reality, as in the self-check on page \(139 .)\)

At the turn of the 20th century, Samuel Langley engaged in a bitter rivalry with the Wright brothers to develop human flight. Langley's design used a catapult for launching. For safety, the catapult was built on the roof of a houseboat, so that any crash would be into the water. This design required reaching cruising speed within a fixed, short distance, so large accelerations were required, and the forces frequently damaged the craft, causing dangerous and embarrassing accidents. Langley achieved several uncrewed, unguided flights, but never succeeded with a human pilot. If the force of the catapult is fixed by the structural strength of the plane, and the distance for acceleration by the size of the houseboat, by what factor is the launch velocity reduced when the plane's \(340 \mathrm{~kg}\) is augmented by the \(60 \mathrm{~kg}\) mass of a small man?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.