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A honeybee's position as a function of time is given by \(x=10 t-t^{3}\), where \(t\) is in seconds and \(x\) in meters. What is its acceleration at $t=3.0 \mathrm{~s} ?

Short Answer

Expert verified
The acceleration at \(t = 3\) seconds is \(-18\, \text{m/s}^2\).

Step by step solution

01

Understand Position Function

The position of the honeybee, as a function of time, is given by the equation \(x(t) = 10t - t^3\). This means that the bee's location on a straight path changes depending on the time \(t\).
02

Find the Velocity Function

To find the velocity function from the position function, compute the derivative with respect to time \(t\). The derivative of the position \(x(t) = 10t - t^3\) is the velocity \(v(t) = \frac{dx}{dt} = 10 - 3t^2\).
03

Find the Acceleration Function

To find the acceleration function, take the derivative of the velocity function with respect to \(t\). The derivative of \(v(t) = 10 - 3t^2\) is the acceleration \(a(t) = \frac{dv}{dt} = -6t\).
04

Calculate the Acceleration at \(t = 3\) seconds

Substitute \(t = 3\) seconds into the acceleration function \(a(t) = -6t\). This gives the acceleration as \(-6 \times 3 = -18\) meters per second squared.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position Function
In physics kinematics, the position function describes an object's location at any given time. It acts as a map, showing where the object is along a path. In our case with the honeybee, the position function is given as \(x(t) = 10t - t^3\). Here, \(t\) is the time in seconds, and \(x\) is the position in meters. This function tells us how the bee moves forward and then eventually starts to slow down and move backward, due to the cubic term. The position function is central to understanding the bee's motion, as it encapsulates how its position changes over time.
Analyzing the position function can tell us about intricate patterns in motion. For example, at \(t = 0\), the bee starts at \(x(0) = 0\) meters. As \(t\) increases, initially the linear term \(10t\) dominates, but over time, the cubic term \(-t^3\) causes the position to eventually decrease, showcasing more complex motion than simple linear movement.
Velocity Function
The velocity function represents the rate of change of position with respect to time. It is essentially the derivative of the position function. Think of it as how fast the object is moving and in which direction at any given moment.
For the honeybee, we find the velocity function by differentiating the position function: \(v(t) = \frac{dx}{dt} = 10 - 3t^2\). This tells us the velocity at any time \(t\). The function shows that the bee's speed and direction change over time due to the \(-3t^2\) term. Initially, the bee speeds up as \(t\) increases, but as \(t\) grows beyond certain values, the bee actually slows down.
  • The positive portion of the function indicates forward motion.
  • When the velocity is zero, the bee changes direction.
This velocity function offers insight into periods of acceleration and deceleration, reflecting the dynamic nature of the bee's path.
Acceleration Function
Acceleration is the rate of change of velocity, essentially measuring how quickly an object is speeding up or slowing down. For the honeybee, the acceleration function is found by taking the derivative of the velocity function: \(a(t) = \frac{dv}{dt} = -6t\).
This function shows that the acceleration changes linearly with time. Specifically, it indicates that as time increases, the bee experiences a steadily increasing deceleration, forcing it to eventually slow down.
By plugging \(t = 3\) seconds into the function, we calculate the acceleration at that moment: \(a(3) = -6 \times 3 = -18\) meters per second squared. The negative sign here indicates that the bee is decelerating at \(t = 3\) seconds and losing speed in the forward direction.
Understanding the acceleration function helps explain the forces affecting the bee's motion and emphasizes its dynamic motion through increasing and decreasing speeds.

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Most popular questions from this chapter

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