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What resistance values can be created by combining a \(1 \mathrm{k} \Omega\) resistor and a \(10 \mathrm{k} \Omega\) resistor?

Short Answer

Expert verified
Resistance values: \(1 \text{k} \Omega\), \(10 \text{k} \Omega\), \(11 \text{k} \Omega\) series, and \(909.09 \text{ } \Omega\) parallel.

Step by step solution

01

Identify Single Resistors

First, understand that you have two resistors: one with a value of \(1 \text{k} \Omega\) and another with a value of \(10 \text{k} \Omega\). These resistors can be used independently or in combination to form different total resistances.
02

Series Combination

When resistors are connected in series, their resistance values add up. Thus, the total resistance for the series combination of the \(1 \text{k} \Omega\) and \(10 \text{k} \Omega\) resistors is calculated as: \[ R_{\text{series}} = R_1 + R_2 = 1 \text{k} \Omega + 10 \text{k} \Omega = 11 \text{k} \Omega \]
03

Parallel Combination

When resistors are connected in parallel, the total resistance can be calculated using the formula: \[ \frac{1}{R_{\text{parallel}}} = \frac{1}{R_1} + \frac{1}{R_2} \] Substituting the given values: \[ \frac{1}{R_{\text{parallel}}} = \frac{1}{1 \text{k} \Omega} + \frac{1}{10 \text{k} \Omega} \] \[ \frac{1}{R_{\text{parallel}}} = \frac{1}{1000} + \frac{1}{10000} = \frac{11}{10000} \] Hence, \[ R_{\text{parallel}} = \frac{10000}{11} \approx 909.09 \text{ } \Omega \]
04

List Possible Combinations

Compile all the resistance values: \(1 \text{k} \Omega\), \(10 \text{k} \Omega\), \(11 \text{k} \Omega\) from series, and approximately \(909.09 \text{ } \Omega\) from parallel.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Combination
When resistors are connected end-to-end, they are said to be in a series combination. In this arrangement, the current flowing through each resistor is the same. The total resistance of the circuit is simply the sum of the individual resistances.
This is because the current has to pass through each resistor one after the other.
As a result, the series combination provides a simple way to increase the overall resistance of the circuit.
The formula for calculating the total resistance when resistors are in series is:
  • \[ R_{\text{series}} = R_1 + R_2 + R_3 + \ldots \]
For example, when you connect a \(1 \text{k} \Omega\) resistor and a \(10 \text{k} \Omega\) resistor in series, the total resistance becomes \(11 \text{k} \Omega\).
This is calculated as:
  • \[ R_{\text{series}} = 1 \text{k} \Omega + 10 \text{k} \Omega = 11 \text{k} \Omega \]
This concept is especially useful in circuits where a specific higher resistance is needed by combining existing resistor values.
Parallel Combination
A parallel combination of resistors is when all resistor terminals connect to the same two points, creating multiple paths for the current to travel.
In this setup, the voltage across each resistor is the same, but the overall current through the circuit increases. This is because electrical charge can take multiple routes across the resistors.
The formula for calculating the total resistance of a parallel configuration is:
  • \[ \frac{1}{R_{\text{parallel}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots \]
Applying this to our situation with a \(1 \text{k} \Omega\) and a \(10 \text{k} \Omega\) resistor yields:
  • \[ \frac{1}{R_{\text{parallel}}} = \frac{1}{1 \text{k} \Omega} + \frac{1}{10 \text{k} \Omega} = \frac{11}{10000} \]
Solving for \(R_{\text{parallel}}\) gives approximately \(909.09 \text{ } \Omega\).
It’s noteworthy that in parallel configurations, the total resistance is always less than the smallest individual resistor.
Resistance Calculation
Resistance calculation is a fundamental concept in electronics, allowing for the design of circuits with desired electrical properties.
Understanding how to combine resistors in both series and parallel configurations is essential for accurate resistance measurement.
This is crucial when designing electric circuits for various applications. The key differences between these two configurations are:
  • **Series:** The total resistance increases as resistors are added. Used to increase total resistance.
  • **Parallel:** The total resistance decreases with additional resistors. Used to decrease total resistance or to maintain the same voltage across components.
Each combination method alters the total resistance in specific ways, allowing flexibility in circuit designs.
By calculating these correctly, one can effectively control the behavior of the electrical circuit.
The ability to predict how different resistor configurations impact total resistance is invaluable for constructing efficient and functional electronic systems.

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Most popular questions from this chapter

You have a circuit consisting of two unknown resistors in series, and a second circuit consisting of two unknown resistors in parallel. (a) What, if anything, would you learn about the resistors in the series circuit by finding that the currents through them were equal? (b) What if you found out the voltage differences across the resistors in the series circuit were equal? (c) What would you learn about the resistors in the parallel circuit from knowing that the currents were equal? (d) What if the voltages in the parallel circuit were equal?

(a) Express the power dissipated by a resistor in terms of \(R\) and \(\Delta V\) only, eliminating \(I\). (b) Electrical receptacles in your home are mostly \(110 \mathrm{~V}\), but circuits for electric stoves, air conditioners, and washers and driers are usually \(220 \mathrm{~V}\). The two types of circuits have differently shaped receptacles. Suppose you rewire the plug of a drier so that it can be plugged in to a \(110 \mathrm{~V}\) receptacle. The resistor that forms the heating element of the drier would normally draw \(200 \mathrm{~W}\). How much power does it actually draw now?

Wire is sold in a series of standard diameters, called "gauges." The difference in diameter between one gauge and the next in the series is about \(20 \%\). How would the resistance of a given length of wire compare with the resistance of the same length of wire in the next gauge in the series?

A \(1.0 \Omega\) toaster and a \(2.0 \Omega\) lamp are connected in parallel with the \(110-\mathrm{V}\) supply of your house. (Ignore the fact that the voltage is \(A C\) rather than \(D C\).) (a) Draw a schematic of the circuit. (b) For each of the three components in the circuit, find the current passing through it and the voltage drop across it. \(\sqrt{ }\) (c) Suppose they were instead hooked up in series. Draw a schematic and calculate the same things.

You are given a battery, a flashlight bulb, and a single piece of wire. Draw at least two configurations of these items that would result in lighting up the bulb, and at least two that would not light it. (Don't draw schematics.) Note that the bulb has two electrical contacts: one is the threaded metal jacket, and the other is the tip (at the bottom in the figure). If you're not sure what's going on, there are a couple of ways to check. The best is to try it in real life by either borrowing the materials from your instructor or scrounging the materials from around the house. (If you have a flashlight with this type of bulb, you can remove the bulb.) Another method is to use the simulation at phet.

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