/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Two people in a rowboat wish to ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two people in a rowboat wish to move around without causing the boat to move. What should be true about their total momentum? Explain.

Short Answer

Expert verified
The total momentum of the system should remain zero to keep the boat from moving.

Step by step solution

01

Understanding the Problem

Imagine a scenario where two people in a rowboat wish to move around but do not want the boat itself to move. We need to figure out what must be constant or equal to achieve this.
02

Concept of Momentum

Momentum, in physics, refers to the product of an object's mass and its velocity. For an object or system to remain at rest or maintain its state of motion, the total momentum must remain unchanged according to the law of conservation of momentum.
03

Applying Momentum Concepts

Since the people in the boat wish to move without moving the boat, the total momentum of the system (people plus boat) must remain zero. This means any change in momentum by one person should be counteracted by an equal and opposite change by the other.
04

Achieving Zero Total Momentum

When one person moves in one direction, the other should either remain still or move in such a way that their motions balance out. This ensures their actions do not impart any net momentum to the boat, keeping it stationary.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum is a fundamental concept in physics that helps us understand motion in various contexts. It is defined as the product of an object's mass and its velocity. Formally, it is expressed as:
  • \( p = mv \)
where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. This implies that heavier objects or faster-moving objects have greater momentum. When discussing momentum, it's helpful to think of it as a measure of 'motion quantity’.
A unique characteristic of momentum is that it is a vector quantity, meaning it includes both magnitude and direction. This is important because it allows momentum to have directional properties that must be considered in calculations.
In practical terms, understanding momentum helps us predict how objects will react upon interacting with each other. Whether it's cars colliding, balls bouncing, or people shifting in a boat, momentum plays a key role in these movement patterns.
Law of Conservation
The law of conservation of momentum is a crucial principle in physics and is instrumental in understanding how systems behave. It states that in a closed system, free from external forces, the total momentum before any event must equal the total momentum after the event.
This principle helps explain why certain actions result in balancing movements elsewhere in the system. For the rowboat scenario, when one person moves, they inadvertently change the momentum of the boat-people system. To maintain the boat’s stationary state, the sum of their individual momentum changes must equal zero. This creates balance and ensures no net movement occurs.
It's also essential to know that the law of conservation of momentum applies universally, from large-scale celestial bodies to tiny particles in the microscopic world. It lays the groundwork for more complex analyses in fields like automotive safety and space exploration.
Boat Dynamics
When considering boat dynamics, the role of momentum becomes even more enlightening. As people move within a boat, they influence the boat's movement due to changes in momentum.
Here’s how it works: when one person shifts forward, their momentum compensates by requiring an opposite response to maintain equilibrium. The other person may need to counter the movement with an equal and opposite adjustment, such as moving backward.
This interaction exemplifies Newton's Third Law, which states that for every action, there is an equal and opposite reaction. Understanding this law within the context of a boat highlights the delicate balance needed to keep the boat stationary while the people inside adjust their positions.
By grasping boat dynamics, we learn more about real-world applications of physics, such as designing stable watercraft and enhancing safety measures for maritime activities.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A mass \(m\) moving at velocity \(v\) collides with a stationary target having the same mass \(m\). Find the maximum amount of energy that can be released as heat and sound.

A bullet leaves the barrel of a gun with a kinetic energy of 90 J. The gun barrel is 50 cm long. The gun has a mass of 4 kg, the bullet 10 g. (a) Find the bullet’s final velocity. (b) Find the bullet’s final momentum. (c) Find the momentum of the recoiling gun. (d) Find the kinetic energy of the recoiling gun, and explain why the recoiling gun does not kill the shooter.

Suppose a system consisting of pointlike particles has a total kinetic energy \(K_{c m}\) measured in the center-of-mass frame of reference. Since they are pointlike, they cannot have any energy due to internal motion. (a) Prove that in a different frame of reference, moving with velocity \(\mathbf{u}\) relative to the center-of-mass frame, the total kinetic energy equals \(K_{c m}+M|\mathbf{u}|^{2} / 2\), where \(M\) is the total mass. [Hint: You can save yourself a lot of writing if you express the total kinetic energy using the dot product.] (b) Use this to prove that if energy is conserved in one frame of reference, then it is conserved in every frame of reference. The total energy equals the total kinetic energy plus the sum of the potential energies due to the particles' interactions with each other, which we assume depends only on the distance between particles. [For a simpler numerical example, see problem 13 on p. \(312 .]\)

A very massive object with velocity \(v\) collides head-on with an object at rest whose mass is very small. No kinetic energy is converted into other forms. Prove that the low-mass object recoils with velocity \(2 v\). [Hint: Use the center-of-mass frame of reference.]

A flexible rope of mass \(m\) and length \(L\) slides without friction over the edge of a table. Let \(x\) be the length of the rope that is hanging over the edge at a given moment in time. (a) Show that \(x\) satisfies the equation of motion \(\mathrm{d}^{2} x / \mathrm{d} t^{2}=g x / L\) [Hint: Use \(F=\mathrm{d} p / \mathrm{d} t\), which allows you to handle the two parts of the rope separately even though mass is moving out of one part and into the other.] (b) Give a physical explanation for the fact that a larger value of \(x\) on the right-hand side of the equation leads to a greater value of the acceleration on the left side. (c) When we take the second derivative of the function \(x(t)\) we are supposed to get essentially the same function back again, except for a constant out in front. The function \(e^{x}\) has the property that it is unchanged by differentiation, so it is reasonable to look for solutions to this problem that are of the form \(x=b e^{c t}\), where \(b\) and \(c\) are constants. Show that this does indeed provide a solution for two specific values of \(c\) (and for any value of \(b\) ). (d) Show that the sum of any two solutions to the equation of motion is also a solution. (e) Find the solution for the case where the rope starts at rest at \(t=0\) with some nonzero value of \(x\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.