Chapter 11: Problem 9
Show that \(f(x)=x^{2}\) may be represented in the interval \(\pm \pi\) by $$ f(x)=\frac{\pi^{2}}{3}+\sum(-1)^{n} \frac{4}{n^{2}} \cos n x $$
Short Answer
Expert verified
Yes, the representation matches the function's Fourier series on \([-\pi, \pi]\).
Step by step solution
01
Understanding the Problem
We need to show that the function \( f(x) = x^2 \) can be represented by the given Fourier series expression on the interval \([-\pi, \pi]\). The target is to match the given series with the function using Fourier series expansion.
02
General Form of a Fourier Series
A Fourier series of a function \( f(x) \) in the interval \([-\pi, \pi]\) is expressed as \( a_0 + \sum_{n=1}^{\infty} [a_n \cos(nx) + b_n \sin(nx)] \). In our problem, we only have cosine terms, so only \( a_0 \) and \( a_n \) exist.
03
Finding the Constant Term \(a_0\)
The constant term in the Fourier series is \( a_0 = \frac{1}{2\pi} \int_{-\pi}^{\pi} x^2 \, dx \), which evaluates to \( \frac{\pi^2}{3} \). This matches the given constant term in the Fourier series representation.
04
Determine the Coefficients \(a_n\)
The cosine coefficients are calculated by \( a_n = \frac{1}{\pi} \int_{-\pi}^{\pi} x^2 \cos(nx) \, dx \). Through integration by parts, it can be shown that \( a_n = (-1)^{n} \frac{4}{n^2} \). This matches the coefficients in the series representation.
05
Final Verification
By calculating both \( a_0 \) and \( a_n \) and matching them to the given Fourier series, we verify that the function \( f(x) = x^2 \) can indeed be represented by the given Fourier series in the interval \([-\pi, \pi]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fourier coefficients
When exploring the Fourier series representation of a function, understanding Fourier coefficients is crucial. These coefficients essentially break down the function into different frequency components, allowing us to express the function as a sum of simple oscillating functions.
In the exercise, the function given is \(f(x) = x^2\) and we need to express this using a Fourier series.
The Fourier series of a function within an interval \([-\pi, \pi]\) is generally written as:
The constant term, \(a_0\), in this series captures the average value of the function over the interval, while \(a_n\) coefficients quantify the amplitude of each cosine term corresponding to their frequency.
In the exercise, the function given is \(f(x) = x^2\) and we need to express this using a Fourier series.
The Fourier series of a function within an interval \([-\pi, \pi]\) is generally written as:
- \(a_0 + \sum_{n=1}^{\infty} \left[ a_n \cos(nx) + b_n \sin(nx) \right]\)
The constant term, \(a_0\), in this series captures the average value of the function over the interval, while \(a_n\) coefficients quantify the amplitude of each cosine term corresponding to their frequency.
cosine terms
The presence of cosine terms in a Fourier series indicates the periodic nature of the function, akin to how sound waves have characteristic frequencies.
In this exercise, we were tasked with finding a series representation of \(f(x) = x^2\) that involved only cosine terms.
Here's why we're focused specifically on cosines:
In this exercise, we were tasked with finding a series representation of \(f(x) = x^2\) that involved only cosine terms.
Here's why we're focused specifically on cosines:
- Cosine functions are even functions, which mirror the symmetry properties of the function \(x^2\) over the interval \([-\pi, \pi]\).
- Because of this symmetry, the sine terms in the Fourier series vanish (i.e., \(b_n = 0\)), leaving only the cosine terms.
integration by parts
Integration by parts is an essential technique for finding Fourier coefficients, especially when the integral involves a product of functions.
In our context, this technique was crucial in computing \(a_n\) coefficients for a function \(f(x) = x^2\).
Here's the general setup:
In our context, this technique was crucial in computing \(a_n\) coefficients for a function \(f(x) = x^2\).
Here's the general setup:
- When integrating \(x^2 \cos(nx)\) over \([-\pi, \pi]\), we use the integration by parts formula: \( \int u \, dv = uv - \int v \, du \).
- In our case, we let \(u = x^2\) and \(dv = \cos(nx) \, dx\).
- This yields a solution for \(a_n\) as \((-1)^{n} \frac{4}{n^2}\), which precisely matches the Fourier series representation.