/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 A hydrogenic atom consists of a ... [FREE SOLUTION] | 91Ó°ÊÓ

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A hydrogenic atom consists of a single electron orbiting a nucleus with \(Z\) protons. \((Z=1 \text { would be hydrogen itself, } Z=2\) is ionized helium, \(Z=3\) is doubly ionized lithium, and so on.) Determine the Bohr energies \(E_{n}(Z)\) the binding energy \(E_{1}(Z),\) the Bohr radius \(a(Z),\) and the Rydberg constant \(\mathcal{R}(Z)\) for a hydrogenic atom. (Express your answers as appropriate multiples of the hydrogen values.) Where in the electromagnetic spectrum would the Lyman series fall, for \(Z=2\) and \(Z=3\) ? Hint: There's nothing much to calculate here in the potential (Equation \(4.52) e^{2} \rightarrow Z e^{2},\) so all you have to do is make the same substitution in all the final results.

Short Answer

Expert verified
Bohr energies scale as \(-13.6Z^2/n^2\). Binding energy is \(-13.6Z^2\, \text{eV}\). Bohr radius becomes \(a_0/Z\), and Rydberg constant is \(\mathcal{R}Z^2\). Lyman series for \(Z=2,3\) are in the UV spectrum.

Step by step solution

01

Understanding Bohr Energy Equation

In Bohr's model, the energy levels for an electron in a hydrogen atom are given by \( E_n = - \frac{13.6}{n^2} \, \text{eV} \). For a hydrogenic atom with atomic number \( Z \), this becomes \( E_n(Z) = - \frac{13.6 \times Z^2}{n^2} \, \text{eV} \).
02

Determine the Binding Energy

The binding energy \( E_1(Z) \) is the energy required to remove the electron from the ground state \( (n=1) \). For a hydrogenic atom, this is \( E_1(Z) = -13.6 \times Z^2 \, \text{eV} \).
03

Calculate the Bohr Radius

The Bohr radius for hydrogen is \( a_0 = 0.529 \times 10^{-10} \text{ m} \). For a hydrogenic atom, it is \( a(Z) = \frac{a_0}{Z} \) since the radius is inversely proportional to the atomic number \( Z \).
04

Determine Rydberg Constant

For hydrogen, the Rydberg constant \( \mathcal{R} = 1.097 \times 10^7 \text{ m}^{-1} \). For a hydrogenic atom, the Rydberg constant becomes \( \mathcal{R}(Z) = \mathcal{R} \times Z^2 \).
05

Identify Electromagnetic Spectrum Region for Lyman Series

The Lyman series occurs when an electron drops from a higher energy level to \( n = 1 \). The wavelength \( \lambda \) of light emitted for \( Z=2 \) and \( Z=3 \) can be determined using the modified Rydberg constant, from \( \frac{1}{\lambda} = \mathcal{R}(Z) \left(1 - \frac{1}{n^2}\right) \). For \( Z=2 \) and \( Z=3 \), this results in emissions that generally fall into the ultraviolet region of the electromagnetic spectrum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bohr Energy Levels
The Bohr model offers a simple and effective way to understand the discrete energy levels of electrons within an atom. In Bohr's atomic model, energy levels are quantified, meaning that electrons occupy certain allowed energy levels. For hydrogenic atoms, which include a single electron orbiting a nucleus with a higher atomic number than hydrogen (e.g., helium or lithium ions), the Bohr energy levels generalize to include the nuclear charge, characterized by the atomic number \( Z \). This modifies the classical formula for hydrogen:\[ E_n(Z) = - \frac{13.6 \times Z^2}{n^2} \, \text{eV} \]where \(n\) is the principal quantum number indicating the energy level. Notice that energy becomes more negative with increasing \(Z\), signifying a stronger attraction between the nucleus and the electron in hydrogenic atoms.
Binding Energy
Binding energy pertains to the energy required to remove an electron from its orbit around an atom, essentially the work needed to overcome the electrostatic force between the electron and the nucleus. In the context of hydrogenic atoms, the ground state binding energy is \[ E_1(Z) = -13.6 \times Z^2 \, \text{eV} \]. This equation tells us that as \(Z\) increases, the binding energy becomes more negative, showing increased stability of the electron at the ground state. This principle is critical in understanding why electrons in multi-electron atoms typically require more energy for removal compared to hydrogen, due to increased attraction from the more heavily charged nucleus.
Bohr Radius
The Bohr radius provides a scale for the typical distance between an electron and the nucleus in an atom. For hydrogen, this distance is given by \( a_0 = 0.529 \times 10^{-10} \, \text{m} \). For hydrogenic atoms, this radius changes to reflect the influence of the nuclear charge, quantified as:\[ a(Z) = \frac{a_0}{Z} \]. With a greater proton count, represented by \(Z\), the electron is drawn closer to the nucleus, effectively shrinking the atomic size and thus the Bohr radius when \(Z\) is greater than 1. This concept serves as a foundational basis for understanding atomic structure, especially for ions formed from elements beyond hydrogen.
Rydberg Constant
The Rydberg constant is fundamental in quantifying the wavelengths of spectral lines. For hydrogen, it is valued as \( \mathcal{R} = 1.097 \times 10^7 \, \text{m}^{-1} \). This constant describes the frequencies of light emitted or absorbed during electron transitions between energy levels. For hydrogenic atoms, which have an effective nuclear charge affecting the electron, the Rydberg constant adapts: \[ \mathcal{R}(Z) = \mathcal{R} \times Z^2 \]. The scaling with \(Z^2\) arises because the spectral line spacings become more frequent as the nucleus exerts a stronger pull on the electron, modifying the energies of its transitions. Thus, the concept of the Rydberg constant and its modified version for hydrogenic atoms is integral for understanding atomic emission spectra.
Electromagnetic Spectrum
The electromagnetic spectrum encompasses all types of electromagnetic radiation, classified by wavelengths and frequencies. When discussing the atomic spectra of hydrogenic atoms, the Lyman series is key. The Lyman series represents transitions where electrons drop from higher energy levels to the first level \((n=1)\). For hydrogenic atoms with higher \(Z\), the emission involves larger energy differences due to increased attraction, implying shorter emission wavelengths. For \(Z=2\) and \(Z=3\), these wavelengths typically fall in the ultraviolet region of the electromagnetic spectrum, a part not visible to the naked eye but crucial for certain technological and scientific applications. Understanding these transitions and the corresponding emission spectrum enriches the study of atomic physics and the analysis of stellar compositions.

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Most popular questions from this chapter

Use separation of variables in cartesian coordinates to solve the infinite cubical well (or "particle in a box"): \(V(x, y, z)=\left\\{\begin{array}{ll}0, & x, y, z \text { all between } 0 \text { and } a; \\ \infty, & \text { otherwise .}\end{array}\right.\) (a) Find the stationary states, and the corresponding energies. (b) Call the distinct energies \(E_{1}, E_{2}, E_{3}, \ldots,\) in order of increasing energy. Find \(E_{1}, E_{2}, E_{3}, E_{4}, E_{5},\) and \(E_{6} .\) Determine their degeneracies (that is, the number of different states that share the same energy). Comment: In one dimension degenerate bound states do not occur (see Problem 2.44 ), but in three dimensions they are very common. (c) What is the degeneracy of \(E_{14}\), and why is this case interesting?

What is the probability that an electron in the ground state of hydrogen will be found inside the nucleus? (a) First calculate the exact answer, assuming the wave function (Equation 4.80) is correct all the way down to \(r=0 .\) Let \(b\) be the radius of the nucleus. (b) Expand your result as a power series in the small number \(\epsilon \equiv 2 b / a\), and show that the lowest-order term is the cubic: \(P \approx(4 / 3)(b / a)^{3}\). This should be a suitable approximation, provided that \(b \ll a\) (which it \(i s\) ). (c) Alternatively, we might assume that \(\psi(r)\) is essentially constant over the (tiny) volume of the nucleus, so that \(P \approx(4 / 3) \pi b^{3}|\psi(0)|^{2}\). Check that you get the same answer this way. (d) Use \(b \approx 10^{-15} \mathrm{m}\) and \(a \approx 0.5 \times 10^{-10} \mathrm{m}\) to get a numerical estimate for \(P .\) Roughly speaking, this represents the "fraction of its time that the electron spends inside the nucleus."

A hydrogen atom starts out in the following linear combination of the stationary states \(n=2, \ell=1, m=1\) and \(n=2, \ell=1, m=-1\) \(\Psi(\mathbf{r}, 0)=\frac{1}{\sqrt{2}}\left(\psi_{211}+\psi_{21-1}\right)\) (a) Construct \(\Psi(\mathbf{r}, t) .\) Simplify it as much as you can. (b) Find the expectation value of the potential energy, \(\langle V\rangle\). (Does it depend on \(t ?\) Give both the formula and the actual number, in electron volts.

According to the Rydberg formula (Equation 4.93 ) the wavelength of a line in the hydrogen spectrum is determined by the principal quantum numbers of the initial and final states. Find two distinct pairs \(\left\\{n_{i}, n_{f}\right\\}\) that yield the same \(\lambda\). For example, \(\\{6851,6409\\}\) and \(\\{15283,11687\\}\) will do it, but you're not allowed to use those!

A particle of mass \(m\) is placed in a finite spherical well: \(V(r)=\left\\{\begin{array}{ll}-V_{0}, & r \leq a ;\\\ 0, & r>a.\end{array}\right.\) Find the ground state, by solving the radial equation with \(\ell=0 .\) Show that there is no bound state if \(V_{0} a^{2}<\pi^{2} \hbar^{2} / 8 m\).

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