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Normalize (x)the equation 2.151, to determine the constants D and F.

Short Answer

Expert verified

D=1a+1k

F=ekacoslaa+1k

Step by step solution

01

 Define the Schrödinger equation

A differential equation describes matter in quantum mechanics in terms of the wave-like properties of particles in a field. Its answer is related to a particle's probability density in space and time.

02

Determine the Constants

=20||2dx=2|D|20acos2lx+|F|20e2kxdx

=2|D|2x2+14lsin2lx|0a+||F|212ke2kx|a2[|D|2a2+sin2la4l+|F|2e2ka2k

But F=Dekacosla(Eq2.152), so role="math" localid="1656054797733" 1=|D|2a+sin(2la)2l+cos2(la)k

Furthermore k=ltan(la)(Eq.2154), so

=|D|2a+2sinlacosla2l+cos3lalsinla

=|D|2a+coslalsinla(sin2la+cos2la)

=|D|2a+1ltanla

=|D|2a+1k

D=1a+1k

F=ekacoslaa+1k

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Most popular questions from this chapter

If two (or more) distinct44solutions to the (time-independent) Schr枚dinger equation have the same energy E . These states are said to be degenerate. For example, the free particle states are doubly degenerate-one solution representing motion to the right. And the other motion to the left. But we have never encountered normalizable degenerate solutions, and this is no accident. Prove the following theorem: In one dimension45 there are no degenerate bound states. Hint: Suppose there are two solutions, 1and 2with the same energy E. Multiply the Schr枚dinger equation for 1by 2and the Schr枚dinger equation for 2by 1and subtract, to show that 2d1/dx-2d1/dxis a constant. Use the fact that for normalizable solutions 0atto demonstrate that this constant is in fact zero.Conclude that 2s a multiple of 1and hence that the two solutions are not distinct.

Show that [Aeikx+Be-ikx] and [Ccos(kx)+Dsin(kx)] are equivalent ways of writing the same function of x, and determine the constants C and D in terms of Aand B, and vice versa.

What is the Fourier transform (x) ? Using Plancherel鈥檚 theorem shows that(x)=12eikxdk.

-consider the 鈥渟tep鈥 potential:

v(x)={0,ifx0,V0,ifx>0,

a.Calculate the reflection coefficient, for the case E < V0, and comment on the answer.

b. Calculate the reflection coefficient, for the case E >V0.

c. For potential such as this, which does not go back to zero to the right of the barrier, the transmission coefficient is not simply F2A2(with A the incident amplitude and F the transmitted amplitude), because the transmitted wave travels at a different speed . Show thatT=E-V0V0F2A2,for E >V0. What is T for E < V0?

d. For E > V0, calculate the transmission coefficient for the step potential, and check that T + R = 1.


Although the overall phase constant of the wave function is of no physical significance (it cancels out whenever you calculate a measurable quantity), the relative phase of the coefficients in Equation 2.17 does matter. For example, suppose we change the relative phase of 1and2in problem 2.5:(x,0)=A[1x+ei2x]Where is some constant. Find (x,t),|x,t|2, and (x), and compare your results with what you got before. Study the special cases =2and=.

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