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In the ground state of the harmonic oscillator, what is the probability (correct to three significant digits) of finding the particle outside the classically allowed region?

Short Answer

Expert verified

Answer

The probability of finding the particle is0.157

Step by step solution

01

- Define probability in quantum mechanics

A probability amplitude is a complex quantity used to describe system behaviour in quantum mechanics.

Use the formula,P=x1x2y0*y0dx

Here, y0represent the wave function of the particle and Pis the probability

02

- Compute the probability

Born's interpretation is that 0(x,t)2represents the probability distribution for the particle's position in the ground state at time t. The likelihood that a particle will be found in a location that is traditionally permissible is -aa0(x,t)2dx.

The probability that it鈥檚 not in this region is,

1--aa0(x,t)2dx=1--aa0(x,t)0*(x,t)dx

localid="1660906664910" =1--aa-0(x)e-E0t/0(x)eiE0t/dx

=1--aa0(x)2dx

localid="1660906677303" =1--aam1/4exp-m2x22dx

Further evaluating,

localid="1660906688274" =1--aam1/2exp-mx2dx

localid="1660906698298" =1-m-aaexp-mx2dx

Use

localid="1660906707184" =mx

localid="1660906713573" d=mdx

localid="1660906720474" dx=md

Thus,

localid="1660906740360" 1--aa0x,t2dx=1-m-mme-2md

localid="1660906752800" =1-1-mme-2d

localid="1660906763118" =1-20me-2d

Now the error function is defined as

localid="1660906772839" 1--aa0(x,t)2dx=1-erfma

Thus the probability is,

localid="1660906782708" 1--aa0(x,t)2dx=1-erfma

localid="1660906791838" 0=m14e-2/2

The energy of the ground state is known, so

localid="1660906804773" 2=12m2a2

Evaluate for a and get,

localid="1660906820214" a=m

Thus the probability is,

1--ia0(x,t)2dx=1-erf1

0.157

Therefore, the probability that the particle lies outside the classically allowed region in the ground state is 0.157.

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Most popular questions from this chapter

A particle of mass m and kinetic energy E > 0 approaches an abrupt potential drop V0 (Figure 2.19).

(a)What is the probability that it will 鈥渞eflect鈥 back, if E = V0/3? Hint: This is just like problem 2.34, except that the step now goes down, instead of up.

(b) I drew the figure so as to make you think of a car approaching a cliff, but obviously the probability of 鈥渂ouncing back鈥 from the edge of a cliff is far smaller than what you got in (a)鈥攗nless you鈥檙e Bugs Bunny. Explain why this potential does not correctly represent a cliff. Hint: In Figure 2.20 the potential energy of the car drops discontinuously to 鈭扸0, as it passes x = 0; would this be true for a falling car?

(c) When a free neutron enters a nucleus, it experiences a sudden drop in potential energy, from V = 0 outside to around 鈭12 MeV (million electron volts) inside. Suppose a neutron, emitted with kinetic energy 4 MeV by a fission event, strikes such a nucleus. What is the probability it will be absorbed, thereby initiating another fission? Hint: You calculated the probability of reflection in part (a); use T = 1 鈭 R to get the probability of transmission through the surface.

A particle is in the ground state of the harmonic oscillator with classical frequency , when suddenly the spring constant quadruples, so '=2, without initially changing the wave function (of course, will now evolve differently, because the Hamiltonian has changed). What is the probability that a measurement of the energy would still return the value 2? What is the probability of getting ?

The scattering matrix. The theory of scattering generalizes in a pretty obvious way to arbitrary localized potentials to the left (Region I),V(x)=0so(x)=Aeikx+Be-ikx,wherek2mE

To the right (Region III),V(x)is again zero, so(x)=Feikx+Ge-ikxIn between (Region II), of course, I can't tell you what is until you specify the potential, but because the Schr枚dinger equation is a linear, second-order differential equation, the general solution has got to be of the form

where f(x)and g(x)are two linearly independent particular solutions. 48 There will be four boundary conditions (two joining Regions I and II, and two joining Regions II and III). Two of these can be used to eliminate C and D, and the other two can be "solved" for B and F in terms of \(A\) and G

B=S11A+S12G.F=S21A+S22G

The four coefficientsSijwhich depend on k (and hence on E), constitute a22matrix s called the scattering matrix (or S-matrix, for short). The S-matrix tells you the outgoing amplitudes (B and F) in terms of the incoming amplitudes (A and G):

(BF)=(S11S21S21S22)(AG)

In the typical case of scattering from the left, G=0so the reflection and transmission coefficients are

Rl=|B|2|A|2|G=0=|S11|2.TI=|F|2|A|2|G=0=|S2|2.

For scattering from the right, and

Rr=|F|2|G|2A=0=|S22|2.Tr=|B|2|G|2A=0=|S12|2.

(a) Construct the S-matrix for scattering from a delta-function well (Equation 2.114). (b) Construct the S-matrix for the finite square well (Equation 2.145). Hint: This requires no new work, if you carefully exploit the symmetry of the problem.

The transfer matrix. The S- matrix (Problem 2.52) tells you the outgoing amplitudes (B and F)in terms of the incoming amplitudes (A and G) -Equation 2.175For some purposes it is more convenient to work with the transfer matrix, M, which gives you the amplitudes to the right of the potential (F and G)in terms of those to the left (A and b):

(FG)=(M11M12M21M22)(AB)[2.178]

(a) Find the four elements of the M-matrix, in terms of the elements of theS-matrix, and vice versa. ExpressRI,TI,RrandTr(Equations 2.176and 2.177) in terms of elements of the M-matrix.,

(b) Suppose you have a potential consisting of two isolated pieces (Figure 2.23 ). Show that the M-matrix for the combination is the product of the twoM-matrices for each section separately: M=M2M1[2.179]

(This obviously generalizes to any number of pieces, and accounts for the usefulness of the M-matrix.)

FIGURE : A potential consisting of two isolated pieces (Problem 2.53 ).

(c) Construct the -matrix for scattering from a single delta-function potential at point V(x)=-(x-a) :

(d) By the method of part , find the M-matrix for scattering from the double delta functionV(x)=-[(x+a)+(X-a)] .What is the transmission coefficient for this potential?

a) Construct 2(x)

b) Sketch 0,1and2

c) Check the orthogonality of012 by explicit integration.

Hint:If you exploit the even-ness and odd-ness of the functions, there is really only one integral left to do.

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