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Estimate the correction to the ground state energy of hydrogen due to the finite size of the nucleus. Treat the proton as a uniformly charged spherical shell of radius b, so the potential energy of an electron inside the shell is constant:-e2/(4蟺系0b);this isn't very realistic, but it is the simplest model, and it will give us the right order of magnitude. Expand your result in powers of the small parameter, (b / a) whereis the Bohr radius, and keep only the leading term, so your final answer takes the form 螖贰E=A(b/a)n. Your business is to determine the constant Aand the power n. Finally, put in b10-15m(roughly the radius of the proton) and work out the actual number. How does it compare with fine structure and hyperfine structure?

Short Answer

Expert verified

Ground state energy correction is roughly 10-10E1, which is less than fine structure and hyperfine structure correction.

Step by step solution

01

Definition ofhyperfine spliting.

The interaction of the magnetic moments of the electron and proton causes hyperfine splitting, which results in a slightly variable magnetic energy for each spin state.

02

The hyperfine splitting in the ground state of muonic hydrogen.

Inside an evenly charged sphere, the potential is equal to:

V(r)=e24蟺蔚01b-1rH'=-e24蟺蔚01b-1r

Wave function of ground state:

0=e-r/a蟺补2a=4蟺蔚0h2me2

Energy correction of ground state,

E01=<H'0>=-e24蟺蔚01蟺补3e-2r/a1b-1rr2诲谤蝉颈苍蠎诲蠎诲蠁=-e24蟺蔚0a341b0br2e-2r/adr-0bre-2r/adr=-e2蟺蔚0a3a34be-2b/a-2baba+1-1+1-a4a-e-2b/a(a+2b)=-e2蟺蔚0a3a4a2b1+e-2b/a-2b2a2-2ba-1-a+e-2b/a(a+2b)=-e24蟺蔚0a2a2b-e-2b/a2b+2a+a2b-a+e-2b/a(a+2b)=e24蟺蔚0a2a1-ab+e-2b/a1+ab

If ba<<1then e-2b/a1-2ba+124b2a2-168b3a3.

Energy is then equal to:

E01=e24蟺蔚0a1-ab+1+ab1-2ab+2b2a2-4b33a3=e24蟺蔚0a1-ab+1-2ba+2b2a2+ab-2+2ba-4b23a2=e24蟺蔚0a2b2a2-4b23a2=e24蟺蔚0a1a2b23a2

Energy of unperturbed ground state,

E1=-12ae24蟺蔚0E1a=-e24蟺蔚012E01.aE1..a=-43ba2A=-43n=2

If a=510-11then, E01aE1a-510-10which is smaller then correction of fine structure 10-5and hyperfine structure 10-8.

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Most popular questions from this chapter

Problem 6.6 Let the two "good" unperturbed states be

0=a0+b0

whereandare determined (up to normalization) by Equation 6.22(orEquation6.24). Show explicitly that

(a)are orthogonal;role="math" localid="1655966589608" (+0-0=0);

(b) +0|H'|-0=0;

(c)0|H'|0=E1,withE1given by Equation 6.27.

By appropriate modification of the hydrogen formula, determine the hyperfine splitting in the ground state of

(a) muonic hydrogen (in which a muon-same charge and g-factor as the electron, but 207times the mass-substitutes for the electron),

(b) positronium (in which a positron-same mass and g-factor as the electron, but opposite charge-substitutes for the proton), and

(c) muonium (in which an anti-muon-same mass and g-factor as a muon, but opposite charge-substitutes for the proton). Hint: Don't forget to use the reduced mass (Problem 5.1) in calculating the "Bohr radius" of these exotic "atoms." Incidentally, the answer you get for positronium (4.8210-4eV)is quite far from the experimental value; (8.4110-4eV)the large discrepancy is due to pair annihilation (e++e-+), which contributes an extra localid="1656057412048" (3/4)螖贰,and does not occur (of course) in ordinary hydrogen, muonic hydrogen, or muoniun.

Question: The most prominent feature of the hydrogen spectrum in the visible region is the red Balmer line, coming from the transition n = 3to n = 2. First of all, determine the wavelength and frequency of this line according to the Bohr Theory. Fine structure splits this line into several closely spaced lines; the question is: How many, and what is their spacing? Hint: First determine how many sublevels the n = 2level splits into, and find Efs1for each of these, in eV. Then do the same for n = 3. Draw an energy level diagram showing all possible transitions from n = 3to n = 2. The energy released (in the form of a photon) is role="math" localid="1658311193797" (E3-E2)+E, the first part being common to all of them, and the E(due to fine structure) varying from one transition to the next. Find E(in eV) for each transition. Finally, convert to photon frequency, and determine the spacing between adjacent spectral lines (in Hz- -not the frequency interval between each line and the unperturbed line (which is, of course, unobservable), but the frequency interval between each line and the next one. Your final answer should take the form: "The red Balmer line splits into (???)lines. In order of increasing frequency, they come from the transitionsto (1) j =(???),toj =(???) ,(2) j =(???) to j =(???)鈥︹. The frequency spacing between line (1)and line (2)is (???) Hz, the spacing between line (2)and (3) line (???) Hzis鈥︹..鈥

Question: In a crystal, the electric field of neighbouring ions perturbs the energy levels of an atom. As a crude model, imagine that a hydrogen atom is surrounded by three pairs of point charges, as shown in Figure 6.15. (Spin is irrelevant to this problem, so ignore it.)

(a) Assuming that rd1,rd2,rd3show that

H'=V0+3(1x2+2y2+3z2)-(1+2+3)r2

where

i-e4蟺蔚0qidi3,andV0=2(1d12+2d22+3d32)

(b) Find the lowest-order correction to the ground state energy.

(c) Calculate the first-order corrections to the energy of the first excited states Into how many levels does this four-fold degenerate system split,

(i) in the case of cubic symmetry1=2=3;, (ii) in the case of tetragonal symmetry1=23;, (iii) in the general case of orthorhombic symmetry (all three different)?

Calculate the wavelength, in centimeters, of the photon emitted under a hyperfine transition in the ground state (n=1) of deuterium. Deuterium is "heavy" hydrogen, with an extra neutron in the nucleus; the proton and neutron bind together to form a deuteron, with spin 1 and magnetic moment

dl=gde2mdSd

he deuteron g-factor is 1.71.

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