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Use the WKB approximation to find the allowed energies of the harmonic oscillator.

Short Answer

Expert verified

The allowed energies of the harmonic oscillator are(12,32,52,).

Step by step solution

01

To find the energies of harmonic oscillator. 

Consider a harmonic oscillator with mass and frequency . The associated potential is

Vx=12m2x2whichcorrespondstoapotentialwellwithnoverticalwalls.Thus,theEquationsaysx1x2pxdx=n-12蟺魔,n=1,2,3,....(1)wherex1andx2aretheturningpointssatisfyingE=12m蝇2x12=12m蝇2x22,orx1=x2=12Em.Inthiscase,px=2mE-12m蝇2x2px=m蝇x22-x2Thus,x1x2pxdx=2m蝇0x2x22-x2dxThisintegralisdoneusingthesubstitutionxx2sin,sox1x2pxdx=2m蝇x22=蟺贰,andthequantizationcondition(Equation(1))yieldsEn=n-12魔蝇=12,32,52,...魔蝇.InthisparticularcasetheWKBapproximationactuallydeliverstheexactallowedenergies,

The drawn the potential of a harmonic oscillator with mass m and frequency w.

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Most popular questions from this chapter

Use the WKB approximation to find the allowed energies of the general power-law potential:

V(x)=|x|vwhere v is a positive number. Check your result for the case v=2 .

Use appropriate connection formulas to analyze the problem of scattering from a barrier with sloping walls (Figurea).

Hint: Begin by writing the WKB wave function in the form

(x)={1pxAeihxx1px'dx'+Be-ihxr1px'dx',x<x11pxCeihx1'px'dx'+De-1hx1Xpx'dx',X1<X<X21pxFeihx2xpx'dx.x>x2

Do not assume C=0 . Calculate the tunneling probability, T=|F|2/|A|2, and show that your result reduces to Equation 8.22 in the case of a broad, high barrier.

Consider the quantum mechanical analog to the classical problem of a ball (mass m) bouncing elastically on the floor.
(a) What is the potential energy, as a function of height x above the floor? (For negative x, the potential is infinite x - the ball can't get there at all.)
(b) Solve the Schr枚dinger equation for this potential, expressing your answer in terms of the appropriate Airy function (note that Bi(z) blows up for large z, and must therefore be rejected). Don鈥檛 bother to normalize (x).
(c) Using g=9.80m/s2and m=0.100kg , find the first four allowed energies, in joules, correct to three significant digits. Hint: See Milton Abramowitz and Irene A. Stegun, Handbook of Mathematical Functions, Dover, New York (1970), page 478; the notation is defined on page 450.
(d) What is the ground state energy, in ,eV of an electron in this gravitational field? How high off the ground is this electron, on the average? Hint: Use the virial theorem to determine <x> .

Analyze the bouncing ball (Problem 8.5) using the WKB approximation.
(a) Find the allowed energies,En , in terms of , and .
(b) Now put in the particular values given in Problem8.5 (c), and compare the WKB approximation to the first four energies with the "exact" results.
(c) About how large would the quantum number n have to be to give the ball an average height of, say, 1 meter above the ground?

Derive the connection formulas at a downward-sloping turning point, and confirm equation8.50.

(x)={D'|p(x)|exp-1hxx1|p(x')|dx'.ifx<x12D'p(x)sin-1hx1xp(x')dx'+4.ifx<x1

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