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In the ground state of the harmonic oscillator, what is the probability (correct to three significant digits) of finding the particle outside the classically allowed region? Hint: Look in a math table under "Normal Distribution" or "Error Function".

Short Answer

Expert verified
The probability is approximately 0.159, or 15.9%.

Step by step solution

01

Understand the Classical Region

For a quantum harmonic oscillator in its ground state, the classically allowed region is within the limits where the potential energy is less than or equal to the total energy. This region corresponds to the interval \[-a \leq x \leq a\] where \(a\) is the classical turning point.
02

Identify the Quantum Formula

The probability of finding the particle outside the classically allowed region can be determined using the ground state wave function of a harmonic oscillator and its properties. This problem relates to the tail probability of the Gaussian distribution.
03

Use the Gaussian Distribution

The probability of the ground state wave function outside the classically allowed region relies on the cumulative distribution function (CDF) of the normal distribution. For a standard normal variable \(Z\), the CDF \( P(Z > z) \) is used to calculate tail probabilities.
04

Consult the Error Function

The standard form for calculating probabilities using error functions involves \[P(x > a) = \frac{1}{2}\left[1 - \text{erf}(\frac{a}{\sqrt{2}})\right]\]where \( \text{erf} \) is the error function. You can find values in a math table or a calculator.
05

Calculate the Probability

In this step, evaluate \[P(x > a) = \frac{1}{2}\left[1 - \text{erf}(a/\sqrt{2})\right]\] Use a mathematical table or a calculator to determine the \( \text{erf} \) value at \( a/\sqrt{2} \) and compute the probability. Given that \( a = 1 \) for this specific ground state case, compute using its corresponding \( \text{erf} \) value.
06

Compute the Final Probability

After finding the appropriate error function value for \( a = 1 \), plug it into the formula to find the probability of the particle being outside the allowed region. Typically, a value near approximately 15.9% or 0.159 is reached for a standard harmonic oscillator.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ground State Wave Function
The ground state wave function is a fundamental concept in quantum mechanics, especially when studying the quantum harmonic oscillator. The wave function describes the quantum state of a particle, indicating its probability amplitude and subsequently, the likelihood of finding the particle at different positions.

For a harmonic oscillator, the ground state wave function, often denoted as \(\psi_0(x)\), has a Gaussian form: \[\psi_0(x) = \left(\frac{m \omega}{\pi \hbar}\right)^{1/4} e^{-m \omega x^2 / 2 \hbar}\]
This equation shows how the wave function is related to the mass \(m\), angular frequency \(\omega\), and reduced Planck's constant \(\hbar\).

Understanding this function allows us to explore probabilities, such as the chance of finding a particle outside the classical bounds of its motion.
Classical Turning Point
The classical turning point in a quantum harmonic oscillator sets the boundary for the classically allowed region of motion. It's defined by the point where the potential energy equals the total energy. In simpler terms, it's the furthest point that a particle can reach given its energy.
For a harmonic oscillator, when considering energy levels, the classical turning points are symmetric around the point of equilibrium and typically defined as \[-a \leq x \leq a\] where \(a\) is the distance from the equilibrium to the turning point.
Understanding this concept helps bridge classical and quantum mechanics, clarifying how quantum probabilities extend beyond classical predictions.
Gaussian Distribution
The Gaussian distribution, often referred to as the "normal distribution," is central to the probabilistic interpretation of the quantum harmonic oscillator's ground state. In quantum mechanics, the Gaussian distribution describes the position probability density of a particle.
In math terms, it is represented as:\[P(x) = \frac{1}{\sigma \sqrt{2\pi}} e^{-(x - \mu)^2 / 2\sigma^2}\]where \(\mu\) is the mean, \(\sigma\) is the standard deviation, and \(x\) represents position.
For a quantum harmonic oscillator, the centered Gaussian reflects the likelihood of finding the particle near its equilibrium position (\(\mu = 0\)). The tails of the distribution, which extend to infinity, represent the probability of finding the particle at positions far from equilibrium, thus helping to explain phenomena, like tunneling beyond classical limits.
Error Function
The error function, \(\text{erf}(x)\), is crucial when calculating probabilities in normal distributions, especially for finding the likelihood of a particle's position being outside the classically allowed region. It is a mathematical function that quantifies the probability that a random variable with a normal distribution falls within a specific range from the mean.
The typical formula that uses the error function in this context is:\[P(x > a) = \frac{1}{2}\left[1 - \text{erf}\left(\frac{a}{\sqrt{2}}\right)\right]\]This calculation can be practically done using tables or scientific calculators, since the error function is not elementary.
In the case of finding particles outside the classical region, the error function helps determine how much probability mass lies in the tails of the distribution, essential for quantum predictions.

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Most popular questions from this chapter

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