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Two thin lenses have focal lengths of -5 and \(+20 \mathrm{cm} .\) Determine their equivalent focal lengths when (a) cemented together and (b) separated by \(10 \mathrm{cm}\).

Short Answer

Expert verified
(a) -6.67 cm; (b) -20 cm.

Step by step solution

01

Understand Focal Length of Combined Thin Lenses - Cemented

For two lenses placed in contact (cemented together), the combined focal length \( F \) can be found using the formula: \( \frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} \), where \( f_1 \) and \( f_2 \) are the focal lengths of the lenses. In this case, \( f_1 = -5 \text{ cm} \) and \( f_2 = +20 \text{ cm} \).
02

Calculate Equivalent Focal Length - Cemented Together

Substitute the given values into the formula for combined focal length: \( \frac{1}{F} = \frac{1}{-5} + \frac{1}{20} \). First, calculate \( \frac{1}{-5} = -0.2 \) and \( \frac{1}{20} = 0.05 \). Now, add these values: \( \frac{1}{F} = -0.2 + 0.05 = -0.15 \). The equivalent focal length \( F \) is \( F = \frac{1}{-0.15} = -\frac{10}{1.5} = -\frac{20}{3} \approx -6.67\text{ cm} \).
03

Understand Focal Length of Separated Thin Lenses

When two lenses are separated by a distance \(d\), the formula for the effective focal length \( F \) is \( \frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} - \frac{d}{f_1f_2} \). Here, \( f_1 = -5 \text{ cm}, \ f_2 = +20 \text{ cm} \), and \( d = 10 \text{ cm} \).
04

Calculate Equivalent Focal Length - Separated by 10 cm

Substitute the given values into the separated lenses formula: \( \frac{1}{F} = \frac{1}{-5} + \frac{1}{20} - \frac{10}{(-5) \times 20} \). We know that \( \frac{1}{-5} = -0.2 \) and \( \frac{1}{20} = 0.05 \), and \(-\frac{10}{-100} = +0.1 \). Add these values: \( \frac{1}{F} = -0.2 + 0.05 + 0.1 = -0.05 \). So \( F = \frac{1}{-0.05} = -20 \text{ cm} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thin Lenses
Thin lenses are fundamental components in optics often used in glasses, cameras, and microscopes. Each thin lens has a specific focal length, which is the distance from the lens to the point where it converges light into a sharp image. Thin lenses can be either concave or convex.
- A **concave lens** has a negative focal length and diverges light rays, making them appear to originate from a single point. - A **convex lens** has a positive focal length, which converges light rays to a focus.
When thin lenses are placed together, their individual abilities to focus or diverge light combine. The principles that govern how lenses work individually also determine how they interact when combined. Understanding the focal length of each lens is crucial for calculating how lenses will work together.
Optical Principles
The optical principles that govern thin lenses are rooted in how light behaves when passing through different mediums. These principles help us understand how lenses can be used to alter the path of light.
1. **Refraction**: This is the bending of light as it passes from one material into another. Lenses use this property to manipulate light paths.2. **Lens Formula**: Lenses are governed by a formula that relates the focal length to the object's and image's distances. The thin lens formula is: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where \( f \) is the focal length, \( v \) is the image distance, and \( u \) is the object distance.
When dealing with the combination of two thin lenses, the above principles expand into combined lens formulas, which help determine an effective focal length. These combined lens formulas consider both lenses' focal lengths and the distance separating the lenses if they are not cemented.
Focal Length Calculation
Calculating the focal length of combined lenses involves specific formulas depending on their configuration:
- **Cemented Together**: When the lenses are in contact, the formula for equivalent focal length \( F \) is: \[ \frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} \] Here, each \( f \) represents the focal length of each lens. By understanding and applying this formula, we can easily find the combined focal length when lenses are cemented.
- **Separated by a Distance**: If they are separated by a distance \( d \), we need an additional term in the equation: \[ \frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} - \frac{d}{f_1f_2} \] This formula indicates that separation alters the optical power of the combination. The distance \( d \) plays a critical role as it affects the bending of light through the system.
Understanding and using these formulas can clarify how lenses in various configurations affect the overall focal length, allowing you to predict how a system of lenses will behave when used in real-world applications.

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Most popular questions from this chapter

A plano-convex lens having a focal length of \(25.0 \mathrm{cm}\) is to be made with glass of refractive index \(1.520 .\) Calculate the radius of curvature of the grinding and polishing tools to be used in making this lens.

An image of an object is formed on a screen by a lens. Leaving the lens fixed, the object is moved to a new position and the image screen moved until it again receives a focused image. If the two object positions are \(S_{1}\) and \(S_{2}\) and if the transverse magnifications of the image are \(M_{1}\) and \(M_{2},\) respectively, show that the focal length of the lens is given by $$f=\frac{\left(S_{2}-S_{1}\right)}{\left(\frac{1}{M_{1}}-\frac{1}{M_{2}}\right)}$$ This is \(A\) bbe's method for finding the focal length of a lens.

A diverging thin lens and a concave mirror have focal lengths of equal magnitude. An object is placed (3/2) f from the diverging lens, and the mirror is placed a distance \(3 f\) on the other side of the lens. Using Gaussian optics, determine the final image of the system, after two refractions (a) by a three-ray diagram and (b) by calculation.

Calculate the focal length of a thin meniscus lens whose spherical surfaces have radii of curvature of magnitude 5 and \(10 \mathrm{cm}\) The glass is of index \(1.50 .\) Sketch both positive and negative versions of the lens.

Derive an expression for the transit time of a ray of light that travels a distance \(x_{1}\) through a medium of index \(n_{1},\) a distance \(x_{2}\) through a medium of index \(n_{2}, \ldots,\) and a distance \(x_{m}\) through a medium of index \(n_{m} .\) Use a summation to express your result.

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