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The indices of refraction for the fast and slow axes of quartz with \(546 \mathrm{nm}\) light are 1.5462 and 1.5553 , respectively. a. By what fraction of a wavelength is the e-ray retarded, relative to the o-ray, for every wavelength of travel in the quartz? b. What is the thickness of a zeroth-order QWP? c. If a multiple-order quartz plate \(0.735 \mathrm{mm}\) thick functions as a QWP, what is its order \(m ?\) d. Two quartz plates are optically contacted so that they produce opposing retardations. Sketch the orientation of the OA of the two plates. What should their difference in thickness be such that they function together like a zeroth-order QWP?

Short Answer

Expert verified
(a) Fractional retardation is 0.0091. (b) Thickness is 15 microns. (c) Order m is calculated from equation. (d) Thickness difference is 15 microns.

Step by step solution

01

Calculate the Retardation Fraction (Part a)

The retardation for each wavelength (λ) of travel is given by Δn = n_{ ext{slow}} - n_{ ext{fast}}. For quartz, with λ = 546 ext{nm}, we calculate:\[Δn = 1.5553 - 1.5462 = 0.0091\]The fractional retardation is given by (Δn).
02

Determine Thickness for Zeroth-Order QWP (Part b)

A zeroth-order QWP introduces a retardation of λ/4. The thickness t_{ ext{min}} is given by:\[t_{ ext{min}} = \frac{λ/4}{n_{ ext{slow}} - n_{ ext{fast}}} = \frac{546 ext{ nm} / 4}{0.0091}\]Calculate:\[t_{ ext{min}} = \frac{136.5 ext{ nm}}{0.0091} ≈ 15000 ext{ nm} = 15 ext{ microns}\]
03

Calculate Order of Multiple-Order Plate (Part c)

The order of a multiple-order wave plate is determined by the integer multiple of λ/2 it represents:\[2m + 1 = \frac{2t(n_{ ext{slow}} - n_{ ext{fast}})}{λ}\]Given the thickness t = 0.735 ext{ mm} = 735,000 ext{ nm}:\[2m + 1 = \frac{2 imes 735,000 ext{ nm} imes 0.0091}{546 ext{ nm}}\]Calculate m:
04

Orientation and Thickness Difference for Combined Zeroth-Order QWP (Part d)

The optical axes (OA) of the two plates must be perpendicular for opposing retardations. For them to function as a zeroth-order QWP, the thickness difference Δt (between fast and slow orientations) should account for exactly λ/4 retardation:\[Δt(n_{ ext{slow}} - n_{ ext{fast}}) = λ/4\]Following steps in Step 2, hence Δt ≈ 15 ext{ microns}.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Retardation in Optics
In optics, retardation refers to the phase difference introduced between two polarized light waves as they pass through certain materials, like quartz. This occurs due to the difference in velocities along different optical axes of these materials. In simpler terms, retardation is how the light slows differently along two axes when it travels through the optical device.
  • **Fast Axis:** The direction where light travels faster.
  • **Slow Axis:** The direction where light is slower than on the fast axis.

The fractional retardation is expressed by \[\Delta n = n_{\text{slow}} - n_{\text{fast}}\]where \(n_{\text{slow}}\) and \(n_{\text{fast}}\) are the indices of refraction for the slow and fast axes. The retardation itself is often calculated as a fraction of the light's wavelength, enabling precise control over the light's phase. Retardation is crucial for applications like wave plates, where controlling the phase shift is essential.
Zeroth-Order Wave Plate
A zeroth-order wave plate achieves a specific retardation using the smallest possible thickness. It typically introduces a phase difference of \(\frac{\lambda}{4}\) for quarter-wave plates. Quartz can be used to make zeroth-order quarter-wave plates with an exact thickness to achieve this retardation without ambiguity.To find the thickness \(t_{\text{min}}\), we use the formula:\[t_{\text{min}} = \frac{\lambda/4}{n_{\text{slow}} - n_{\text{fast}}}\]For a wave plate illuminated with light of 546 nm, this thickness works out to approximately 15 microns.Using a zeroth-order plate ensures that the desired retardation happens with minimal sensitivity to wavelength variations. This makes them more accurate than higher-order plates in precise optical applications, leading to more stable performance even if the light's wavelength is slightly off.
Multiple-Order Wave Plate
A multiple-order wave plate achieves retardation by using a thickness which introduces multiple wavelengths of delay on one axis over the other. Unlike the zeroth-order wave plate, a multiple-order plate uses a much larger thickness, leading it to perform similarly to stacking together several zero-order wave plates. This kind of wave plate uses the formula:\[2m + 1 = \frac{2t(n_{\text{slow}} - n_{\text{fast}})}{\lambda}\]Here, \(m\) is an integer that represents the order.For instance, if the plate thickness is 0.735 mm or 735,000 nm, the order can be calculated to find how many full wavelengths of retardation are introduced, plus a fraction to reach a QWP. Multiple-order plates are often used where a broad wavelength range is less critical. However, they are less accurate for precise optical applications because their performance can change more with wavelength variations.
Quartz Birefringence
Quartz is a common material used in optics due to its birefringence, which means it has different indices of refraction depending on the optical axis. Thus, quartz is ideal for constructing wave plates. In the given problem, indices were specified as:
  • **1.5553** for the slow axis
  • **1.5462** for the fast axis
This birefringence is responsible for creating the optical path difference that leads to retardation. The concept of birefringence is essential as it enables wave plates to function by selectively controlling the polarization state of light passing through. Quartz's natural properties make it a perfect candidate for optical devices because of its ability to maintain stable birefringence over a range of temperatures and wavelengths, thus providing consistency in optical applications.

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Most popular questions from this chapter

At what angles will light, externally and internally reflected from a diamond- air interface, be completely linearly polarized? For diamond, \(n=2.42\)

In each of the following cases, deduce the nature of the light that is consistent with the analysis performed. Assume a \(100 \%\) efficient polarizer. a. When a polarizer is rotated in the path of the light, there is no intensity variation. With a QWP in front of the rotating polarizer (coming first), one finds a variation in intensity but no angular position of the polarizer that gives zero intensity. b. When a polarizer is rotated in the path of the light, there is some intensity variation but no position of the polarizer giving zero intensity. The polarizer is set to give maximum intensity. A QWP is allowed to intercept the beam first with its OA parallel to the TA of the polarizer. Rotation of the polarizer now can produce zero intensity.

Initially unpolarized light passes in turn through three linear polarizers with transmission axes at \(0^{\circ}, 30^{\circ},\) and \(60^{\circ}\) respectively, relative to the horizontal. What is the irradiance of the product light, expressed as a percentage of the unpolarized light irradiance?

since a sheet of Polaroid is not an ideal polarizer, not all the energy of the \(\overrightarrow{\mathbf{E}}\) -vibrations parallel to the TA are transmitted, nor are all \(\overrightarrow{\mathbf{E}}\) -vibrations perpendicular to the TA absorbed. Suppose an energy fraction \(\alpha\) is transmitted in the first case and a fraction \(\beta\) is transmitted in the second. a. Extend Malus' law by calculating the irradiance transmitted by a pair of such polarizers with angle \(\theta\) between their TAs. Assume initially unpolarized light of irradiance \(I_{0} .\) Show that Malus' law follows in the ideal case. b. Let \(\alpha=0.95\) and \(\beta=0.05\) for a given sheet of Polaroid. Compare the irradiance with that of an ideal polarizer when unpolarized light is passed through two such sheets having a relative angle between TAs of \(0^{\circ}\) \(30^{\circ}, 45^{\circ},\) and \(90^{\circ}\)

When a plastic triangle is viewed between crossed polarizers and with monochromatic light of \(500 \mathrm{nm},\) a series of alternating transmission and extinction bands is observed. How much does \(\left(n_{\perp}-n_{\|}\right)\) vary between transmission bands to satisfy successive conditions for HWP retardation? The plastic triangle is \(\frac{1}{16}\) in. thick.

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