Chapter 2: Problem 5
The electric vector of a wave is given by the real expression $$ \mathbf{E}=E_{0}[\hat{\mathbf{i}} \cos (k z-\omega t)+\hat{\mathbf{j}} b \cos (k z-\omega t+\phi)] $$ Show that this is equivalent to the complex expression $$ \mathbf{E}=E_{0}\left(\hat{\mathbf{i}}+\hat{\mathbf{j}} b e^{i \phi}\right) e^{i(k z-\omega t)} $$
Short Answer
Step by step solution
Identify Trigonometric Identities
Apply Trigonometric Identity
Substitute and Simplify
Group and Factor Similar Terms
Confirm the Complex Expression
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Key Concepts
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