/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 In steady-state flow, downstream... [FREE SOLUTION] | 91Ó°ÊÓ

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In steady-state flow, downstream the density is \(1 \mathrm{kg} / \mathrm{m}^{3}\) the velocity is \(1000 \mathrm{m} / \mathrm{sec},\) and the area is \(0.1 \mathrm{m}^{2}\). Upstream, the velocity is \(1500 \mathrm{m} / \mathrm{sec},\) and the area is \(0.25 \mathrm{m}^{2}\). What is the density upstream?

Short Answer

Expert verified
The upstream density is around \(0.267 kg/ m^{3}\).

Step by step solution

01

Identify the variables

First, identify and write down the given elements of the equation: downstream density \(\rho_1 = 1 kg / m^{3}\), downstream velocity \(V_1 = 1000 m / sec\), downstream area \(A_1 = 0.1 m^{2}\), upstream velocity \(V_2 = 1500 m / sec\), and upstream area \(A_2 = 0.25 m^{2}\). The unknown is the upstream density, \(\rho_2\).
02

Write down the continuity equation

The continuity equation in this context is \(\rho_1 V_1 A_1 = \rho_2 V_2 A_2\). This equation represents the conservation of mass in steady-state flow.
03

Substitute the known values into the equation

Substitute the known values into the equation: \(1 kg / m^{3} * 1000 m / sec * 0.1 m^{2} = \rho_2 * 1500 m / sec * 0.25 m^{2}\).
04

Solve for the unknown

Solve the equation for \(\rho_2\): \(\rho_2 = (1 kg / m^{3} * 1000 m / sec * 0.1 m^{2}) / (1500 m / sec * 0.25 m^{2})\). Upon calculation, you will find that the upstream density is \(\rho_2 = 0.267 kg / m^{3}\).

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