/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 103 Air enters a duct, of diameter \... [FREE SOLUTION] | 91Ó°ÊÓ

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Air enters a duct, of diameter \(D=25.0 \mathrm{mm},\) through a well-rounded inlet with uniform speed, \(U_{1}=0.870 \mathrm{m} / \mathrm{s}\) At a downstream section where \(L=2.25 \mathrm{m},\) the fully developed velocity profile is \\[ \frac{u(r)}{U_{c}}=1-\left(\frac{r}{R}\right)^{2} \\] The pressure drop between these sections is \(p_{1}-p_{2}=1.92 \mathrm{N} /\) \(\mathrm{m}^{2}\), Find the total force of friction exerted by the tube on the air.

Short Answer

Expert verified
The total force of friction exerted by the tube on the air is \(0.000941 \, N\).

Step by step solution

01

Calculate the Radius

First, we calculate the radius of the duct, which will be used later on in the velocity profile equation. The radius \(R\) is half of the diameter \(D\), thus \(R = D / 2 = 25.0 \, mm / 2 = 12.5 \, mm = 0.0125 \, m\).
02

Identify the Average Speed

Then, we identify the average speed \(U_c\) from the problem. We are told that the uniform speed \(U_{1}\) is \(0.870 \, m/s\). Since for fully developed laminar flow in a circular duct the average speed equals the maximum speed divided by 2, \(U_c = U_{1} / 2 = 0.870 \, m/s / 2 = 0.435 \, m/s\). This equation can be derived from the velocity profile given in the problem.
03

Determine the Pressure Drop

We then use the pressure drop \(dp = p_{1} - p_{2} = 1.92 \, N/m^{2}\) provided in the problem. This value will be used in the force equation we formulate below.
04

Calculate the Total Force of Friction

Finally, we can calculate the total force of friction exerted by the tube on the air. The force of friction \(F\) can be calculated by multiplying the pressure drop \(dp\) by the area \(A\) of the duct. The area \(A\) of a circle is given by \(\pi r^{2}\). Therefore, we can calculate \(A = \pi * (0.0125 \, m)^{2} = 0.00049 \, m^{2}\), and then substitute these values into the force equation \(F = dp * A = 1.92 \, N/m^{2} * 0.00049 \, m^{2} = 0.000941 \, N\).

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