Chapter 4: Problem 18
Consider a low-speed subsonic wind tunnel with a nozzle contraction ratio of \(1: 20\). One side of a mercury manometer is connected to the settling chamber and the other side to the test section. The pressure and temperature in the test section are \(1 \mathrm{~atm}\) and \(300 \mathrm{~K}\), respectively. What is the height difference between the two columns of mercury when the test section velocity is \(80 \mathrm{~m} / \mathrm{s} ?\)
Short Answer
Step by step solution
Understand the Setup
Apply Bernoulli's Equation
Calculate Air Density
Calculate Pressure in the Settling Chamber
Find Mercury Height Difference
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bernoulli's Equation
- \( P \) is the pressure exerted by the fluid.
- \( \rho \) represents the fluid's density.
- \( V \) is the velocity of the fluid.
- \( h \) is the height above a reference point.
- \( g \) is the acceleration due to gravity.
Air Density Calculation
- \( P \) is the pressure of the air.
- \( R \) is the specific gas constant for air, approximately \( 287 \text{ J/(kg K)} \).
- \( T \) is the air temperature in Kelvin.