91Ó°ÊÓ

Write the expression for the potential.

$V\left(r\right)=\frac{1}{4\mathrm{Ï€}{\mathrm{Î\mu }}_0}\left(\frac{q}{r_{+}}-\frac{q}{r_{-}}\right)$ …… (1)

Here,q is the charge and v is the potential.

As,

$$\begin{gathered} \frac{1}{r_{+}}=\frac{1}{r}\underset{n=0}{\overset{∞}{∑}}{\left(\frac{r^r}{r}\right)}^n{P}_n\left(\cos \mathrm{θ}\right) \\ \frac{1}{r_{-}}=\frac{1}{r}\underset{n=0}{\overset{∞}{∑}}{\left(\frac{r^r}{r}\right)}^n{P}_n\left(\cos \mathrm{θ}\right) \end{gathered}$$

Here,$P_n$ is the Legendre polynomial of order n .

Keep$r\text{'}=d/2$ in above equation.

$\frac{1}{r_{-}}=\frac{1}{r}\underset{n=0}{\overset{∞}{∑}}{\left(\frac{d}{2r}\right)}^n{P}_n\left(\cos \mathrm{θ}\right)$

For r take $\mathrm{θ}=180-\mathrm{θ}$, so$\cos \mathrm{θ}→-\cos \mathrm{θ}$

Then,$\frac{1}{r_{-}}=\frac{1}{r}\underset{n=0}{\overset{∞}{∑}}{\left(\frac{d}{2r}\right)}^n{P}_n\left(-\cos \mathrm{θ}\right)$

As,

$\begin{array}{rcl}{P}_n\left(-n\right)& =& {\left(-1\right)}^n{P}_n\left(x\right)\\ P_n\left(-\cos \mathrm{θ}\right)& =& {\left(-1\right)}^n{P}_n\left(\cos \mathrm{θ}\right)\\ & & \end{array}$

Then,

$V\left(r\right)=\frac{q}{4\mathrm{Ï€}{\mathrm{Î\mu }}_{0}r}\left[\underset{n=0}{\overset{∞}{∑}}{\left(\frac{d}{2r}\right)}^n{P}_n\left(\cos \mathrm{θ}\right)-\underset{n=0}{\overset{∞}{∑}}{\left(-1\right)}^n{\left(\frac{d}{2r}\right)}^n{P}_n\left(\cos \mathrm{θ}\right)\right]$…… (2)

Put $n=1$for dipole,

$$\begin{gathered} V_{dipole}=\frac{q}{4\mathrm{Ï€}{\mathrm{Î\mu }}_{0}r}\left[P_1\left(\cos \mathrm{θ}\right)+P_1\left(\cos \mathrm{θ}\right)\right] \\ {V}_{dipole}=\frac{q}{4\mathrm{Ï€}{\mathrm{Î\mu }}_{0}r}\frac{2qd\cos \mathrm{θ}}{2r^2} \\ {V}_{dipole}=\frac{q}{4\mathrm{Ï€}{\mathrm{Î\mu }}_{0}r}\frac{qd\cos \mathrm{θ}}{r^2} \end{gathered}$$

$P_1\left(\cos \mathrm{θ}\right)=\cos \mathrm{θ}$

Now, put $n=2$for quadruple term,

$$\begin{gathered} V_{quad}=\frac{1}{4\mathrm{Ï€}{\mathrm{Î\mu }}_0}\frac{q}{r}{\left(\frac{d}{2r}\right)}^2\left[P_2\left(\cos \mathrm{θ}\right)-P_2\cos \mathrm{θ}\right] \\ =0 \end{gathered}$$

Now, put $n=3$for octuplet term,

$\begin{array}{rcl}{V}_{oct}& =& \frac{1}{4\mathrm{Ï€}{\mathrm{Î\mu }}_0}\frac{q}{r}{\left(\frac{d}{2r}\right)}^3\left[P_3\left(\cos \mathrm{θ}\right)+P_3\left(\cos \mathrm{θ}\right)\right]\\ & =& \frac{2q}{4\mathrm{Ï€}{\mathrm{Î\mu }}_{0}r}{\left(\frac{d}{2r}\right)}^3{P}_3\left(\cos \mathrm{θ}\right)\\ & =& \frac{q}{4\mathrm{Ï€}{\mathrm{Î\mu }}_{0}r}{\left(\frac{d}{2r}\right)}^3\left(5{\cos }^3\mathrm{θ}-3\cos \mathrm{θ}\right)\\ & =& \frac{q{d}^3}{32\mathrm{Ï€}{\mathrm{Î\mu }}_0{r}^4}\left(5{\cos }^3\mathrm{θ}-3\cos \mathrm{θ}\right)\end{array}$

Hence, the quadruple and octuplet terms in the potential are 0 and .

$\frac{q{d}^3}{32\mathrm{Ï€}{\mathrm{Î\mu }}_0{r}^4}\left(5{\cos }^3\mathrm{θ}-3\cos \mathrm{θ}\right)$