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For the infinite slot (Ex. 3.3), determine the charge density σ(y)on

the strip at x=0, assuming it is a conductor at constant potential V0.

Short Answer

Expert verified

Answer

The equation for the charge density on the strip at x=0is σy=4ε0V0a∑n=1,3,5...sinnÏ€²âa.

Step by step solution

01

Define functions

Write the expression for the potential V(x,y)in the infinite slot.

V(x,y)=4V0π∑n=1,3,5...1ne-nÏ€³æasin(nÏ€ya) …… (1)

Here, V0is the constant potential along the conductor, xis the x-coordinate, yis the y-coordinate, and nis the positive integer.

02

Determine the charge density

Derive the charge density in terms of electric potential.

σ=-e0∂V∂nσy=-e0∂V∂xx=0 …… (2)

Substitute 4V0π∑n=1,3,5...1ne-nÏ€³æasinnÏ€²âafor Vx,yin equation (2).

σy=ε0∂∂x4V0π∑1nenÏ€³æasinnÏ€²âax=0=ε04V0π∂∂x∑1nenÏ€³æasinnÏ€²âax=0=ε04V0π∑1n-nxaenÏ€³æasinnÏ€²âax=0=ε04V0Ï€1nnxa∑1nenÏ€³æasinnÏ€²âax=0

σy=4ε0V0a∑n=1,3,5...sinnÏ€²âa

Hence, the equation for the charge density on the strip at x=0is σy=4ε0V0a∑n=1,3,5...sinnÏ€²âa.

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Three point charges are located as shown in Fig. 3.38, each a distance

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(a) Show that the quadrupole term in the multipole expansion can be written as

V"quad"(r⃗)=14πε01r3∑(i,j=13r^ir^jQij     .....(1)

(in the notation of Eq. 1.31) where

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Here

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localid="1658485969560" Vmon=14πε0Qr;Vdip=14πε0∑r^ipjr2;Vquad(r⇶Ä)=14πε01r3∑i,j=13r^ir^jQIJ;...

The monopole moment localid="1658485018381" (Q) is a scalar, the dipole moment localid="1658485022577" (p⇶Ä) is a vector, the quadrupole moment localid="1658485026647" (Qij)is a second rank tensor, and so on.

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