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Question: (a) Find the magnetic field at the center of a square loop, which carries a steady current I.Let Rbe the distance from center to side (Fig. 5.22).

(b) Find the field at the center of a regular n-sided polygon, carrying a steady current

I.Again, let Rbe the distance from the center to any side.

(c) Check that your formula reduces to the field at the center of a circular loop, in

the limit n.

Short Answer

Expert verified

(a) The magnetic field at the center of a square loop carrying a steady current Iand Rdistance from center to side is 20l蟺搁.

(b) The magnetic field at the center of a regular n-sided polygon carrying a steady current Iand Rdistance from center to side is n0l2Rsinn .

(c) For nthe field at the center of a regular n-sided polygon reduces to the field at the center of a circular loop.

Step by step solution

01

Given data

There is a square loop which carries a steady current Iwith Rdistance from center to side.

There is a regular n-sided polygon carrying a steady current Iwith Rdistance from the center to any side.

02

Magnetic field of a straight wire

The magnetic field at a distance R from a straight wire carrying current l isB=0l4蟺搁(蝉颈苍胃2-蝉颈苍胃1)

Here, 0is the permeability of free space and 2and 1are the angles made by the ends of the wire with the point at which the field is calculated.

03

Magnetic field of a straight wire

For a square, the angles made by the vertices with the center is 45.

Thus, from equation (1),

B=0l4Rsin45-sin-45=0l4R2

Including four sides of the square, the net field is

B=40l4R2=20l4R

Thus, the field is 20l4蟺搁.

04

Magnetic field of a regular n sided polygon

For a regular n sided polygon, the angles made by the vertices with the center is n. Thus, from equation (1),

B=0l4R-sinn=0l2Rsinn

Including n sides of the polygon, the net field is

B=n0l2Rsinn=n0l2Rsinn

Thus, the field is n0l2Rsinn.

05

Magnetic field of a regular n sided polygon with n→∞

As n becomes infinitely large, nbecomes infinitely small and thus,

sinnn

Equation (2) thus becomes,

B=n0l2Rsinnn0l2Rsinn=0l2R

This is the magnetic field at the centre of a circle.

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Most popular questions from this chapter

Question: Using Eq. 5.88, calculate the average magnetic field of a dipole over

a sphere of radius Rcentered at the origin. Do the angular integrals first. Compare your answer with the general theorem in Prob. 5.59. Explain the discrepancy, and indicate how Eq. 5.89 can be corrected to resolve the ambiguity at . (If you get stuck, refer to Prob. 3.48.) Evidently the truefield of a magnetic dipole is

Bdip(r)=04蟺谤3[3(mr^)r^-m]+203m3(r)Bdip(r)=04r3[3mr^r^-m]+203m3(r)

Compare the electrostatic analog, Eq. 3.106.

(a) A phonograph record of radius R, carrying a uniform surface charge , is rotating at constant angular velocity . Find its magnetic dipole moment.

(b) Find the magnetic dipole moment of the spinning spherical shell in Ex. 5.11. Show that for pointsr>R the potential is that of a perfect dipole.

Consider the motion of a particle with mass m and electric charge qein the field of a (hypothetical) stationary magnetic monopole qmat the origin:

B=04qmr2r^

(a) Find the acceleration of qe, expressing your answer in terms of localid="1657533955352" q, qm, m, r (the position of the particle), and v(its velocity).

(b) Show that the speed v=|v|is a constant of the motion.

(c) Show that the vector quantity

Q=m(rv)-0qeqm4r^

is a constant of the motion. [Hint: differentiate it with respect to time, and prove-using the equation of motion from (a)-that the derivative is zero.]

(d) Choosing spherical coordinates localid="1657534066650" (r,,), with the polar (z) axis along Q,

(i) calculate , localid="1657533121591" Q^and show that is a constant of the motion (so qemoves on the surface of a cone-something Poincare first discovered in 1896)24;

(ii) calculate Qr^, and show that the magnitude of Qis

Q=04|qeqm肠辞蝉胃|;

(iii) calculate Q^, show that

诲蠒dt=kr2,

and determine the constant k .

(e) By expressing v2in spherical coordinates, obtain the equation for the trajectory, in the form

drd=f(r)

(that is: determine the function )f(r)).

(t) Solve this equation for .r()

(a) By whatever means you can think of (short of looking it up), find the vector potential a distance from an infinite straight wire carrying a current . Check that .A=0and A=B.

(b) Find the magnetic potential inside the wire, if it has radius R and the current is uniformly distributed.

The magnetic field on the axis of a circular current loop (Eq. 5.41) is far from uniform (it falls off sharply with increasing z). You can produce a more nearly uniform field by using two such loops a distanced apart (Fig. 5.59).

(a) Find the field (B) as a function of z, and show that Bzis zero at the point midway between them (z=0)

(b) If you pick d just right, the second derivative ofBwill also vanish at the midpoint. This arrangement is known as a Helmholtz coil; it's a convenient way of producing relatively uniform fields in the laboratory. Determine dsuch that

2B/z2=0at the midpoint, and find the resulting magnetic field at the center.

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