/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q6.18P A sphere of linear magnetic mate... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A sphere of linear magnetic material is placed in an otherwise uniform magnetic field B0. Find the new field inside the sphere.

Short Answer

Expert verified

The value of new magnetic field inside the sphere is B→∞=3μrμr+2B→0.

Step by step solution

01

Write the given data from the question.

Consider asphere of linear magnetic material is placed in an otherwise uniform magnetic field B0.

02

Determine the formula of new magnetic field inside the sphere.

Write the formula of new magnetic field inside the sphere.

B→∞=B→0∑n=0∞23χmχm+1n …… (1)

Here,B→0 is uniform magnetic field andχm is magnetic susceptibility.

03

Determine the value of new magnetic field inside the sphere.

I'll apply the solution to issue 4.23. A magnetization is caused by the original magnetic field.

M→0=χmH→0=χmμB→0

Determine the modifies magnetic field within the sphere:

B→1=B→0+23μ0M→0=B→01+23χmχm+1

Determine the magnetization induced by this field is:

M→1=χmH→1=χmμB→1=χmμB→01+23χmχm+1

Now, field is further modified:

B→1=B→0+23μ0M→1=B→0+23μ0χmμB→01+23χmχm+1=B→01+23χmχm+1+23χmχm+12

Where this song and dance will take us is fairly evident. The final magnetic field is obviously B→∞:

Determine the new magnetic field inside the sphere.

B→∞=B→011−23χmχm+1=B→03(χm+1)3(χm+1)−2χm=3μrμr+2B→0

Therefore, the value of new magnetic field inside the sphere is B→∞=3μrμr+2B→0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the force of attraction between two magnetic dipoles, m1and m2, oriented as shown in Fig. 6.7, a distance r apart, (a) using Eq. 6.2, and (b) using Eq.6.3.

An infinitely long circular cylinder carries a uniform magnetization Mparallel to its axis. Find the magnetic field (due toM) inside and outside the cylinder.

Suppose the field inside a large piece of magnetic material is B0, so that H0=(1/μ0)B0-M, where M is a "frozen-in" magnetization.

(a) Now a small spherical cavity is hollowed out of the material (Fig. 6.21). Find the field at the center of the cavity, in terms of B0 and M. Also find H at the center of the cavity, in terms of H0 and M.

(b) Do the same for a long needle-shaped cavity running parallel to M.

(c) Do the same for a thin wafer-shaped cavity perpendicular to M.

Figure 6.21

Assume the cavities are small enough so M, B0, and H0 are essentially constant. Compare Prob. 4.16. [Hint: Carving out a cavity is the same as superimposing an object of the same shape but opposite magnetization.]

A current Iflows down a long straight wire of radius. If the wire is made of linear material (copper, say, or aluminium) with susceptibility Xm, and the current is distributed uniformly, what is the magnetic field a distances from the axis? Find all the bound currents. What is the net bound current flowing down the wire?

In Sect, 6.2.1, we began with the potential of a perfect dipole (Eq. 6.10), whereas in fact we are dealing with physical dipoles. Show, by the method of Sect. 4.2.3, that we nonetheless get the correct macroscopic field.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.