Chapter 6: Q6.18P (page 286)
A sphere of linear magnetic material is placed in an otherwise uniform magnetic field . Find the new field inside the sphere.
Short Answer
The value of new magnetic field inside the sphere is .
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Chapter 6: Q6.18P (page 286)
A sphere of linear magnetic material is placed in an otherwise uniform magnetic field . Find the new field inside the sphere.
The value of new magnetic field inside the sphere is .
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A familiar toy consists of donut-shaped permanent magnets (magnetization parallel to the axis), which slide frictionlessly on a vertical rod (Fig. 6.31). Treat the magnets as dipoles, with mass md and dipole moment m.
(a) If you put two back-to-hack magnets on the rod, the upper one will "float"-the magnetic force upward balancing the gravitational force downward. At what height (z) does it float?
(b) If you now add a third magnet (parallel to the bottom one), what is the ratio of the two heights? (Determine the actual number, to three significant digits.)

(a)Show that the energy of a magnetic dipole in a magnetic field is
[Assume that the magnitude of the dipole moment is fixed, and all you have to do is move it into place and rotate it into its final orientation. The energy required to keep the current flowing is a different problem, which we will confront in Chapter 7.] Compare Eq. 4.6.
Figure 6.30
(b) Show that the interaction energy of two magnetic dipoles separated by a displacement is given by
Compare Eq. 4.7.
(c) Express your answer to (b) in terms of the angles and in Fig. 6.30, and use the result to find the stable configuration two dipoles would adopt if held a fixed distance apart, but left free to rotate.
(d) Suppose you had a large collection of compass needles, mounted on pins at regular intervals along a straight line. How would they point (assuming the earth's magnetic field can be neglected)? [A rectangular array of compass needles aligns itself spontaneously, and this is sometimes used as a demonstration of "ferromagnetic" behaviour on a large scale. It's a bit of a fraud, however, since the mechanism here is purely classical, and much weaker than the quantum mechanical exchange forces that are actually responsible for ferromagnetism. 13]
Notice the following parallel:
Thus, the transcription ,, turns an electrostatic problem into an analogous magnetostatic one. Use this, together with your knowledge of the electrostatic results, to rederive.
(a) the magnetic field inside a uniformly magnetized sphere (Eq. 6.16);
(b) the magnetic field inside a sphere of linear magnetic material in an otherwise uniform magnetic field (Prob. 6.18);
(c) the average magnetic field over a sphere, due to steady currents within the sphere (Eq. 5.93).
A coaxial cable consists of two very long cylindrical tubes, separated by linear insulating material of magnetic susceptibility . A current flows down the inner conductor and returns along the outer one; in each case, the current distributes itself uniformly over the surface (Fig. 6.24). Find the magnetic field in the region between the tubes. As a check, calculate the magnetization and the bound currents, and confirm that (together, of course, with the free currents) they generate the correct field.
Figure 6.24
Question: Of the following materials, which would you expect to be paramagnetic and which diamagnetic: aluminum, copper, copper chloride (), carbon, lead, nitrogen (), salt ( ), sodium, sulfur, water? (Actually, copper is slightly diamagnetic; otherwise, they're all what you'd expect.)
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