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Show that the second equation in Eq. 12.127 can be expressed in terms of the field tensor F渭谓as follows:

localid="1654746948628" F渭谓x+F谓位x+F位渭x=0

Short Answer

Expert verified

The second equation Gx=0can be expressed in terms of field tensor as

F渭谓x+F谓位x+F位渭x=0

Step by step solution

01

Expression for Maxwell’s equation:

Write the expression for Maxwell鈥檚 equation.

Gx=0

....................(1)

Ifthe-0then,equation(1)becomes,G慰谓x=G00x0+G01x1+G02x2+G03x3G慰谓x=Bxx+Byy+BZzBxx+Byy+BZz=.B.B=0If=1thenequation(1)becomes,G1x=G10x0+G11x1+G12x2+G13x3G1x=-1cBxt-1cEzt+1cEyz-1cBxt-1cEzt+1cEyz=-1cBt+EE=-Bt

02

Show that∂Fμν∂xλ+∂Fνλ∂xμ+∂Fμν∂xν=0

Takethesumofthespatialcomponents.

If=1,v=2and=3,then,theequation(2)becomes,F12x3+F23x1+F31x2=Bzx2+Fxz+Fyy.B=0If=0,v=1and=2,thezcomponentfromequation(2)becomes,F01x2+F12x1+F30x2=Ex/cy+Bzct+Ex/cxE=-BtIf=0,v=2and=3,thexandycomponentfromequation(2)becomes,F02x3+F23x0+F30x2=Ey/cx3+Bxct+Ez/cx2E=-BtSo,ItcanbeseenthetthefunctionG渭谓x=0canbeexpressedintermsoffieldtensorasF渭谓x+F谓位x+F位渭x=0Therefore,thesecondequationG渭谓x=0canbeexpressedintermsoffieldtensorasF渭谓x+F谓位x+F位渭x=0

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Most popular questions from this chapter

Inertial system S moves at constant velocity v=尾肠(肠辞蝉蠒x^+蝉颈苍蠒y^)with respect to S. Their axes are parallel to one other, and their origins coincide at data-custom-editor="chemistry" t=t=0, as usual. Find the Lorentz transformation matrix A.

Prove that the symmetry (or antisymmetry) of a tensor is preserved by Lorentz transformation (that is: if is symmetric, show that is also symmetric, and likewise for antisymmetric).

鈥淚n a certain inertial frame S, the electric field E and the magnetic field B are neither parallel nor perpendicular, at a particular space-time point. Show that in a different inertial system S, moving relative to S with velocity v given by

v1+v2/c2=EBB2+E2/c2

the fieldsEandBare parallel at that point. Is there a frame in which the two are perpendicular?

A particle of mass m collides elastically with an identical particle at rest. Classically, the outgoing trajectories always make an angle of 90. Calculate this angle relativistically, in terms of , the scattering angle, and v, the speed, in the center-of-momentum frame.

The natural relativistic generalization of the Abraham-Lorentz formula (Eq. 11.80) would seem to be

Krad=0q26cddb

This is certainly a 4-vector, and it reduces to the Abraham-Lorentz formula in the non-relativistic limitvc .

(a) Show, nevertheless, that this is not a possible Minkowski force.

(b) Find a correction term that, when added to the right side, removes the objection you raised in (a), without affecting the 4-vector character of the formula or its non-relativistic limit.

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