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A short cylinder, of radius a and length L, carries a "frozen-in" uniform polarization P, parallel to its axis. Find the bound charge, and sketch the electric field (i) for L≫a, (ii) for L≪a, and (iii) for L≈a. [This is known as a bar electret; it is the electrical analog to a bar magnet. In practice, only very special materials-barium titanate is the most "familiar" example-will hold a permanent electric polarization. That's why you can't buy electrets at the toy store.]

Short Answer

Expert verified

(a) In the event that L≫a, the field will roughly resemble that of a physical dipole, with "point charges" of magnitude ±PAspaced Lapart.

(b) The field between the top and bottom of the cylinder in the case L≪awill roughly resemble that of a parallel-plate capacitor with surface charge densities ±Pon the top and bottom.

(c) Simply take a look at the preceding two situations; they both have surface charge densities ±Pon the top/bottom. About as the photo depicts, the field looks.

Step by step solution

01

Write the given data from the question.

Consider a short cylinder, of radius aand length L, carries a "frozen-in" uniform polarization P, parallel to its axis .

02

(a) Determine for L≫a.

Draw the circuit diagram of electric field forL≫a .

Figure 1

ForL≫a .

In the event that L≫a, the field will roughly resemble that of a physical dipole, with "point charges" of magnitude±PA spaced apart.

03

(b) Determine for L≪a.

Draw the circuit diagram of electric field for L≪a.

Figure 2

The field between the top and bottom of the cylinder in the case L≪awill roughly resemble that of a parallel-plate capacitor with surface charge densities±P on the top and bottom.

04

(b) Determine for L≈a.

Draw the circuit diagram of electric field for L≈a

Figure 3

Simply take a look at the preceding two situations; they both have surface charge densities±P on the top/bottom. About as the photo depicts, the field looks.

The surface bound charge is the only bound charge present in all three scenarios since the polarisation is constant, ÒÏb=0.

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Most popular questions from this chapter

A dielectric cube of side a,centered at the origin, carries a "frozen in"

polarization p→=kr→, where kis a constant. Find all the bound charges, and check

that they add up to zero.

A sphere of radius R carries a polarization

P(r)=kr,

Where k is a constant and r is the vector from the center.

(a) Calculate the bound charges σband ÒÏb.

(b) Find the field inside and outside the sphere.

An uncharged conducting sphere of radius ais coated with a thick

insulating shell (dielectric constant εr) out to radius b.This object is now placed in an otherwise uniform electric field E→0. Find the electric field in the insulator.

E2→Find the field inside a sphere of linear dielectric material in an otherwise uniform electric field E0→(Ex. 4.7) by the following method of successive approximations: First pretend the field inside is just E0→, and use Eq. 4.30 to write down the resulting polarization P0→. This polarization generates a field of its own, E1→ (Ex. 4.2), which in turn modifies the polarization by an amount P1→. which further changes the field by an amount E2→, and so on. The resulting field is E→0+E→1+E→2+.... . Sum the series, and compare your answer with Eq. 4.49.

The Clausius-Mossotti equation (Prob. 4.41) tells you how to calculatethe susceptibility of a nonpolar substance, in terms of the atomic polariz-ability. The Langevin equation tells you how to calculate the susceptibility of apolar substance, in terms of the permanent molecular dipole moment p. Here's howit goes:

(a) The energy of a dipole in an external field E isu=-p··¡³¦´Ç²õθ

(Eq. 4.6), whereθ is the usual polar angle, if we orient the z axis along E.

Statistical mechanics says that for a material in equilibrium at absolute temperature

T, the probability of a given molecule having energy u is proportional to

the Boltzmann factor,

exp(-u/kT)

The average energy of the dipoles is therefore

<u>=∫ue-(u/kt)»åΩ∫e-(u/kT)»åΩ

where »åΩ=²õ¾±²Ôθ»åθ»åÏ•, and the integration is over all orientations θ:0→π;Ï•:0→2Ï€Use this to show that the polarization of a substance

containing N molecules per unit volume is

P=Np[cothpE/kT-kT/pE] (4.73)

That's the Langevin formula. Sketch as a function ofPE/KT .

(b) Notice that for large fields/low temperatures, virtually all the molecules arelined up, and the material is nonlinear. Ordinarily, however, kT is much greaterthan p E. Show that in this regime the material is linear, and calculate its susceptibility,in terms of N, p, T, and k. Compute the susceptibility of water at 20°C,and compare the experimental value in Table 4.2. (The dipole moment of wateris 6.1×10-30C·m) This is rather far off, because we have again neglected thedistinction between E and Eelse· The agreement is better in low-density gases,for which the difference between E and Eelse is negligible. Try it for water vapor

at 100°C and 1 atm.

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