/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 A circular ring in the ry plane ... [FREE SOLUTION] | 91Ó°ÊÓ

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A circular ring in the ry plane (radius \(R\), centered at the origin) carries a uniform line charge \(\lambda\). Find the first three terms \((n=0,1,2)\) in the multipole expansion for \(V(r, \theta)\).

Short Answer

Expert verified
V(r, \theta) = \frac{2\pi \lambda R^2}{r} + \frac{8\pi \lambda R^4}{3r^3} P_2(\cos{\theta}).

Step by step solution

01

Understanding the Setup

We are given a circular ring with radius \(R\) and uniform line charge density \(\lambda\). Our goal is to find the potential \(V(r, \theta)\) using a multipole expansion to the first three terms for \(n=0, 1, 2\).
02

Writing the Expression for Potential

The potential at a point \((r, \theta)\) can be expressed using the multipole expansion as: \[ V(r, \theta) = \sum_{n=0}^{\infty} \left( \frac{R}{r} \right)^{n+1} Q_n P_n(\cos{\theta}) \]where \(P_n\) are the Legendre polynomials and \(Q_n\) are the multipole moments, given as: \[ Q_n = \int_{0}^{2\pi} \lambda R P_n(\cos{\theta'}) \cdot R d\theta' \].
03

Calculating Zeroth Order Term (\(n=0\))

We compute the monopole moment: \[ Q_0 = \lambda R^2 \int_{0}^{2\pi} P_0(\cos{\theta'})d\theta' = \lambda R^2 (2\pi) \]Substitute back: \[ V_0(r, \theta) = \frac{\lambda R^2 (2\pi)}{r} \].
04

Calculating First Order Term (\(n=1\))

There is symmetry around the origin, making \(Q_1 = 0\) as the integral of \(\cos{\theta'}\) over the full circle results in zero. Thus, \[ V_1(r, \theta) = 0 \].
05

Calculating Second Order Term (\(n=2\))

We compute the quadrupole moment: \[ Q_2 = \lambda R^2 \int_{0}^{2\pi} P_2(\cos{\theta'})d\theta' = \frac{\lambda R^2 (8\pi)}{3} \]. Substitute back: \[ V_2(r, \theta) = \frac{\lambda R^4 (8\pi)}{3r^3} P_2(\cos{\theta}) \].
06

Combining the Terms

The first three terms of the multipole expansion are:\[ V(r, \theta) = \frac{2\pi \lambda R^2}{r} + 0 + \frac{8\pi \lambda R^4}{3r^3} P_2(\cos{\theta}) \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Legendre Polynomials
Legendre polynomials, often designated as \( P_n(x) \), play a crucial role in problems involving spherical coordinates. These polynomials are solutions to Legendre's differential equation and appear extensively in physics and engineering, especially in the context of potential theory.
They are linked to the angular portion of the solutions of Laplace's equation when problems possess spherical symmetry. Each polynomial is defined over the interval \([-1, 1]\) and has specific properties, making them orthogonal. Orthogonality means that the integral of the product of any two different Legendre polynomials over this interval is zero.
  • \( P_0(x) = 1 \): This represents the constant part, essentially a simple baseline.
  • \( P_1(x) = x \): This indicates the linear term related to symmetry about an axis.
  • \( P_2(x) = \frac{1}{2}(3x^2 - 1) \): This is more complex, addressing how the shape deviates from spherical when viewed through higher-order terms.
In multipole expansions, Legendre polynomials describe the angular dependence of potential functions, allowing for a systematic approach to solve electrostatic or gravitational problems in a space surrounding charged or massive objects.
Multipole Moments
Multipole moments are coefficients that appear in the series expansion of a potential function. These moments capture how different distributions of charge contribute to the potential at a distance.
A multipole expansion breaks down the potential into a series of terms, each representing a different distribution pattern.
  • Monopole Moment (\( Q_0 \)): This is the simplest moment and corresponds to the net charge or total mass if considering gravitation. It doesn't depend on the distance, showcasing the basic strength exerted by the source.
  • Dipole Moment (\( Q_1 \)): In many symmetrical settings, such as a circular ring with uniform charge, this moment often vanishes due to opposing charge distributions canceling each other out.
  • Quadrupole Moment (\( Q_2 \)): This captures the system's configuration, revealing how charge is aligned within it. It becomes significant in higher-order terms when monopoles or dipoles are not present.
These moments enable scientists to approximate potentials of complex distributions by only considering a few leading terms of the series.
Electrostatic Potential
The electrostatic potential \( V(r, \theta) \) represents the potential energy per unit charge at a point \((r, \theta)\). It is a scalar quantity that tells us how much work would be needed to bring a small positive test charge from a reference point, typically infinity, to a given position.
The potential due to a continuous charge distribution can be quite complex, so physicists often use multipole expansions as a powerful tool for simplifying these potential fields, especially at large distances.
The expression of electrostatic potential using a multipole expansion looks like this:
  • \( V(r, \theta) = \sum_{n=0}^{\infty} \left( \frac{R}{r} \right)^{n+1} Q_n P_n(\cos{\theta}) \)
Here,
- \( Q_n \) are the multipole moments that characterize the distribution of the source.
- \( P_n(\cos{\theta}) \) are the Legendre polynomials responsible for the angular dependence.
This expansion gives a clear roadmap to approach problems by analyzing contributions from different terms (monopole, dipole, etc.), providing a hierarchical technique to approximate potential based on symmetry and the distance of observation.

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Most popular questions from this chapter

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