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If a particle's kinetic energy is \(n\) times its rest energy, what is its speed?

Short Answer

Expert verified
The particle's speed is \( v = c \sqrt{1 - \frac{1}{(n+1)^2}} \).

Step by step solution

01

Understand Rest Energy and Kinetic Energy

The rest energy is given by the equation \(E_0 = mc^2\), where \(m\) is the rest mass and \(c\) is the speed of light. The relativistic kinetic energy is given by \(K = E - E_0\), where \(E\) is the total energy.
02

Express Kinetic Energy in Terms of Total Energy

Given that the particle's kinetic energy \(K\) is \(n\) times its rest energy: \[ K = nE_0. \]
03

Relate Total Energy with Rest and Kinetic Energy

The total energy \(E\) can be written as the sum of the rest energy and the kinetic energy: \[E = E_0 + K.\] Replace \(K\) with \(nE_0\): \[E = E_0 + nE_0 = (n+1)E_0.\]
04

Use the Relativistic Energy-Momentum Relation

The relativistic energy is also given by \[E = \gamma mc^2,\] where \(\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\). Therefore,\[(n+1)mc^2 = \gamma mc^2.\] This simplifies to \[\gamma = n+1.\]
05

Solve for Speed \(v\) using Lorentz Factor

Relate the Lorentz factor \(\gamma\) to speed \(v\): \[\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}} = n + 1.\] Rearrange and solve for \(v^2\): \[1-\frac{v^2}{c^2} = \frac{1}{(n+1)^2}.\]Thus\[\frac{v^2}{c^2} = 1 - \frac{1}{(n+1)^2}.\]
06

Calculate Speed of the Particle

Solve for \(v\): \[v = c \sqrt{1 - \frac{1}{(n+1)^2}}.\] This is the speed of the particle in terms of its kinetic and rest energies.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy a particle possesses due to its motion. In relativistic mechanics, it is an important concept because as objects move at high speeds, their kinetic energy increases significantly. The formula for relativistic kinetic energy is different from the classical \(\frac{1}{2}mv^2\). Instead, it is derived from the total energy \(E\) minus the rest energy \(E_0\):
  • Relativistic Kinetic Energy: \(K = E - E_0\)
This means that the greater the speed of the particle, the greater its kinetic energy, which can be especially large when the particle approaches the speed of light. It is crucial to understand how kinetic energy relates to the total and rest energy, especially at such high speeds.
In the context of this problem, the kinetic energy is given as \(n\) times the rest energy, which helps us understand the relationship between these energies and the particle’s speed.
Lorentz Factor
The Lorentz factor, denoted by \(\gamma\), is a key concept in relativistic mechanics. It describes how time, length, and relativistic mass change for an object moving close to the speed of light. The Lorentz factor is expressed by the formula:
  • \(\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}\)
The larger the Lorentz factor, the closer the object is moving to the speed of light \(c\).
It plays a crucial role in determining the total energy of a moving particle:
  • Total Energy: \(E = \gamma mc^2\)
In the exercise, we find that \(\gamma = n + 1\), indicating how relativistic effects become pronounced as kinetic energy increases. Understanding the Lorentz factor is vital, as it directly influences the particle’s speed calculations.
Rest Energy
Rest energy is the energy inherent to a particle when it is not moving. This concept is pivotal in Einstein's theory of relativity. The rest energy is the energy equivalent of the mass of a particle at rest and is given by the famous equation:
  • \(E_0 = mc^2\)
Here, \(m\) is the rest mass of the particle, and \(c\) is the speed of light. Rest energy is an essential baseline from which kinetic and total energy are measured.
In the formulated problem, the rest energy is compared to the particle's kinetic energy, showing how much more energy the particle gains as it moves. This comparison helps us comprehend the scales at which changes in velocity affect the overall energy of the particle.
Speed of Light
The speed of light, denoted \(c\), is a constant in physics inherently related to many concepts in relativity. It is approximately \(299,792,458 \, m/s\).
In the realm of relativistic mechanics, nothing with mass can reach or exceed the speed of light. This constraint affects the calculation of relativistic speed and energy. As a particle's velocity approaches this limit, relativistic effects such as time dilation and increase in mass become significant.
  • The speed of light acts as a universal speed limit.
In the context of the exercise, we utilize the limit imposed by the speed of light to calculate the particle's velocity. It is reflected in the equation:
  • \(v = c \sqrt{1 - \frac{1}{(n+1)^2}}\)
This showcases how speed in relation to light plays a decisive role in calculations using relativistic mechanics.

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Most popular questions from this chapter

A Lincoln Continental is twice as long as a VW Beetle, when they are at rest. As the Continental overtakes the VW, going through a speed trap, a (stationary) policeman observes that they both have the same length. The VW is going at half the speed of light. How fast is the Lincoln going? (Leave your answer as a multiple of c.)

In a laboratory experiment, a muon is observed to travel \(800 \mathrm{~m}\) before disintegrating. A graduate student looks up the lifetime of a muon \(\left(2 \times 10^{-6} \mathrm{~s}\right)\) and concludes that its speed was $$ v=\frac{800 \mathrm{~m}}{2 \times 10^{-6} \mathrm{~s}}=4 \times 10^{8} \mathrm{~m} / \mathrm{s} $$ Faster than light! Identify the student's error, and find the actual speed of this muon.

A neutral pion of (rest) mass \(m\) and (relativistic) momentum \(p=\) \(\frac{3}{4} m_{c}\) decays into two photons. One of the photons is emitted in the same direction as the original pion, and the other in the opposite direction. Find the (relativistic) energy of each photon.

You may have noticed that the four-dimensional gradient operator \(\partial / \partial x^{\mu}\) functions like a covariant 4 -vector-in fact, it is often written \(\partial_{\mu}\), for short. For instance, the continuity equation, \(\partial_{\mu} J^{\mu}=0\), has the form of an invariant product of two vectors. The corresponding contravariant gradient would be \(\partial^{\mu}=\partial / \partial x_{\mu}\). Prove that \(\partial^{\mu} \phi\) is a (contravariant) 4 -vector, if \(\phi\) is a scalar function, by working out its transformation law, using the chain rule.

Calculate the threshold (minimum) momentum the pion must have in order for the process \(\pi+p \rightarrow K+\Sigma\) to occur. The proton \(p\) is initially at rest. Use \(m_{\pi} c^{2}=150, m_{K} c^{2}=500, m_{p} c^{2}=900, m_{\Sigma} c^{2}=1200\) (all in MeV). [Hint: To formulate the threshold condition, examine the collision in the center-ofmomentum frame (Prob, 12.31).

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