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An infinite number of different surfaces can be fit to a given boundary line, and yet, in defining the magnetic flux through a loop, \(\Phi=\int \mathbf{B} \cdot d \mathbf{a}\). I never specified the particular surface to be used. Justify this apparent oversight.

Short Answer

Expert verified
The magnetic flux is independent of the surface used, as long as the boundary is the same, due to Gauss's Law for Magnetism (\( \nabla \cdot \mathbf{B} = 0 \)).

Step by step solution

01

Define Magnetic Flux

The magnetic flux \( \Phi \) through a surface is given by the integral \( \Phi = \int \mathbf{B} \cdot d \mathbf{a} \), where \( \mathbf{B} \) is the magnetic field and \( d \mathbf{a} \) is the differential area vector of the surface.
02

Independence of Surface Choice

The value of the magnetic flux through a closed loop depends on the magnetic field and the orientation of the loop, but not on the specific shape of the surface spanning the loop. This is because magnetic fields have no divergence (per Gauss's Law for Magnetism, \( abla \cdot \mathbf{B} = 0 \)), meaning there are no 'sources' or 'sinks' of magnetic field lines.
03

Apply Gauss's Law for Magnetism

Gauss's Law for Magnetism states that the net magnetic flux out of any closed surface is zero. This implies that, within a closed loop, the integral of the magnetic field through any surface bounded by that loop will result in the same value for magnetic flux, as long as the boundary remains the same.
04

Conclude Surface Choice Redundancy

Due to the property that magnetic flux through a boundary loop is consistent regardless of the surface, the specific surface used in calculating \( \Phi = \int \mathbf{B} \cdot d \mathbf{a} \) does not need to be specified when the boundary is closed. It's the boundary that matters, not the surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gauss's Law for Magnetism
Gauss's Law for Magnetism is a fascinating principle that helps us understand the behavior of magnetic fields. According to this law, the net magnetic flux through any closed surface is always zero. Mathematically, it is expressed as \( abla \cdot \mathbf{B} = 0 \). This equation implies that magnetic field lines neither originate nor terminate within a closed surface. They form continuous loops.
  • This property tells us that there are no magnetic "charges" akin to electric charges for electric fields.
  • It highlights the closed nature of magnetic field lines and sets them apart from electric field lines, which can start and end on charges.

Understanding that the net magnetic flux over a closed surface is zero helps us rationalize why the shape of the surface used to calculate the magnetic flux through an open loop is irrelevant. The focus is on the loop itself, not how we span the surface.
Magnetic Fields
Magnetic fields are invisible forces that exert action at a distance. We often visualize them using field lines, which give us clues about the direction and strength of the magnetic field.
  • The direction of the magnetic field lines shows the direction a north pole would move if placed in the field.
  • The density of these lines signifies the strength of the magnetic field; more lines mean a stronger field.

Magnetic fields are created by moving charges (e.g., electric currents) and certain materials that are magnetized. Despite their invisibility, they play crucial roles in various natural phenomena and technologies like MRI machines and compasses. Importantly, magnetic fields have no beginning or end within space, consistent with Gauss's Law for Magnetism.
This continuous loop characteristic reinforces why any surface spanning a particular boundary loop will yield the same magnetic flux.
Surface Integrals
Surface integrals are an essential concept for calculating various physical properties across surfaces. In the context of magnetic flux, the surface integral \( \Phi = \int \mathbf{B} \cdot d \mathbf{a} \) represents the dot product between the magnetic field \( \mathbf{B} \) and the area element \( d \mathbf{a} \) over a given surface.
  • Each small patch of the surface contributes a component determined by aligning \( \mathbf{B} \) with the orientation of \( d \mathbf{a} \).
  • The integral sums all these contributions across the surface to give the total magnetic flux.

Because Gauss's Law confirms that magnetic fields have no divergence, the choice of surface is irrelevant when calculating the flux through a closed boundary. This is the beauty of surface integrals in this context – they focus solely on the boundaries, allowing flexibility in surface choice. Thus, understanding and using surface integrals is key to calculating magnetic flux effectively without worrying about the intricate shape of the surface considered.

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Most popular questions from this chapter

A perfectly conducting spherical shell of radius \(a\) rotates about the \(z\) axis with angular velocity \(\omega\), in a uniform magnetic field \(\mathbf{B}=B_{0}\). \(\mathbf{z}\). Calculate the emf developed between the "north pole" and the equator, [Answer: \(\left.\frac{1}{2} B_{0} \omega a^{2}\right]\)

A rectangular loop of wire is situated so that one end (height \(h\) ) is between the plates of a paralle]-plate capacitor (Fig. 7.9), oriented parallel to the field \(\mathbf{E}\). The other cnd is way outside, where the field is essentially zero. What is the emf in this loop? If the total resistance is \(R\), what current flows? Explain. [Warming: this is a trick question. so be careful: if you have invented a perpetual motion machine, there's probably something wrong with it.]

Sea water at frequency \(v=4 \times 10^{8} \mathrm{~Hz}\) has permittivity \(\epsilon=81 \epsilon_{0}\), permeability \(\mu=\mu_{0}\), and resistivity \(\rho=0.23 \Omega \cdot \mathrm{m}\). What is the ratio of conduction current to displacement current?

\(\mathrm{~A}\) square loop of wire, of side \(a\), lies midway between two long wires, \(3 a\) apart. and in the same planc. (Actually, the long wires are sides of a large rectangular loop. but the short ends are so far away that they can be neglected.) A clockwise current \(I\) in the square loop is gradually increasing: \(d I / d t=k\) (a constant). Find the emf induced in the big loop. Which way will the induced current flow?

A small loop of wire (radius \(a\) ) lies a distance \(z\) above the center of a large loop (radius \(b\) ), as shown in Fig. 7.36. The planes of the two loops are parallel. and perpendicular to the common axis. (a) Suppose current \(I\) flows in the big loop. Find the flux through the litle loop. (The little Ioop is so small that you may consider the field of the big loop to be essentially constant.) (b) Suppose current \(I\) flows in the liule loop. Find the flux through the big loop. (The little loop is so small that you may treat it as a magnetic dipole.) (c) Find the mutual inductances, and confirm that \(M_{12}=M_{21}\).

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