Chapter 2: Problem 11
Use Gauss's law to find the electric field inside and outside a spherical shell of radius \(R\), which carries a uniform surface charge density \(\sigma\). Compare your answer to Prob. \(2.7\).
Short Answer
Expert verified
The electric field is zero inside the shell and \(E = \frac{R^2 \sigma}{\varepsilon_0 r^2}\) outside.
Step by step solution
01
Understanding the Problem
We have a spherical shell of radius \(R\) carrying a uniform surface charge density \(\sigma\). The task is to find the electric field both inside (\(r < R\)) and outside (\(r > R\)) the shell using Gauss's law.
02
Gauss's Law
Gauss's Law states that the electric flux \(\Phi_{E}\) through a closed surface is \(\Phi_{E} = \frac{Q_{ ext{enc}}}{\varepsilon_0}\), where \(Q_{\text{enc}}\) is the enclosed charge. To find the electric field \(\mathbf{E}\), we choose a Gaussian surface.
03
Inside the Shell (\(r < R\))
Consider a Gaussian surface inside the shell, a sphere of radius \(r < R\). Since there is no charge enclosed by this surface (the charge is on the shell itself), \(Q_{\text{enc}} = 0\). Thus, \(\Phi_{E} = 0\) which implies \(\mathbf{E} = 0\) inside the shell.
04
Outside the Shell (\(r > R\))
For a Gaussian surface outside the shell, at radius \(r > R\), the enclosed charge is the total charge on the shell, \(Q = 4\pi R^2 \sigma\). Using Gauss's law, \(\Phi_{E} = E \cdot 4\pi r^2 = \frac{4\pi R^2 \sigma}{\varepsilon_0}\). Solving for \(E\), we find \(E = \frac{R^2 \sigma}{\varepsilon_0 r^2}\), directed radially outward.
05
Comparison with Problem 2.7
Problem 2.7 likely involved either a point charge or a uniformly charged sphere. Compared to a point charge, the field outside is similar to that due to a point charge at the center with charge \(Q\). But inside, for the spherical shell, the field is zero as per the shell theorem. A uniformly charged sphere would have a non-zero field inside unlike a shell.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electric Field
The electric field is a vector field that represents the force per unit charge exerted on a test charge placed within the field. In physics, understanding the behavior and calculation of electric fields is key, especially when dealing with charged objects like spherical shells.
Gauss's Law provides a powerful tool to calculate electric fields. It states that the electric flux passing through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space, \[\varepsilon_0\].
For spherical shells, the symmetry simplifies our calculations. By placing a Gaussian surface, typically a concentric sphere, within or outside the shell, the law helps us determine the electric field because such symmetry allows for constant electric field magnitude across the surface.
Gauss's Law provides a powerful tool to calculate electric fields. It states that the electric flux passing through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space, \[\varepsilon_0\].
For spherical shells, the symmetry simplifies our calculations. By placing a Gaussian surface, typically a concentric sphere, within or outside the shell, the law helps us determine the electric field because such symmetry allows for constant electric field magnitude across the surface.
- Inside the shell (\(r < R\)), any Gaussian surface will enclose zero charge, leading to zero electric field based on Gauss's Law.
- Outside the shell (\(r > R\)), the entire surface charge affects the field calculation, resulting in an expression similar to that of a point charge's field at a distance.
Spherical Shell
A spherical shell is a hollow object characterized by its symmetry. It can be imagined as a thin, curved surface forming the boundary at a constant distance from a center. The importance of such shells in electrostatics lies in their symmetry which vastly simplifies calculations using Gauss's Law.
One scenario is considering the shell having a radius \(R\), with a uniform surface charge density \(\sigma\). This configuration is particularly useful in many physics problems because it highlights the key differences between shells and solid spheres.
When we use a spherical Gaussian surface within the shell:
One scenario is considering the shell having a radius \(R\), with a uniform surface charge density \(\sigma\). This configuration is particularly useful in many physics problems because it highlights the key differences between shells and solid spheres.
When we use a spherical Gaussian surface within the shell:
- No charge is enclosed, as charges reside on the shell's surface, leading to zero electric field inside.
- However, an external Gaussian sphere will encompass all charges from the shell, simulating a scenario akin to a point charge at its center, but spread uniformly over the shell's surface.
Surface Charge Density
Surface charge density, often denoted by \(\sigma\), is a measure of how much electric charge resides on a given surface area of an object. It indicates the amount of charge per unit area, typically expressed in \(\text{C/m}^2\), and is crucial in analyzing charged surfaces like spherical shells.
In the context of a spherical shell, \(\sigma\) helps determine the total charge present on the shell. For a shell of radius \(R\), the total charge, \(Q\), is given by:\[Q = 4\pi R^2 \sigma\]
This expression allows us to calculate the electric field outside the shell using Gauss's Law. The simplicity and practicality of \(\sigma\) make it an important parameter in electrostatics, providing a manageable means to quantify and work with charge distributions.
In the context of a spherical shell, \(\sigma\) helps determine the total charge present on the shell. For a shell of radius \(R\), the total charge, \(Q\), is given by:\[Q = 4\pi R^2 \sigma\]
This expression allows us to calculate the electric field outside the shell using Gauss's Law. The simplicity and practicality of \(\sigma\) make it an important parameter in electrostatics, providing a manageable means to quantify and work with charge distributions.
- Uniform surface charge densities result in constant electric fields in specific regions, like zero fields inside a spherical shell.
- Changes in \(\sigma\) can lead to different electric field configurations, making it a dynamic and versatile concept in physics.