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(a) Charge \(q_{A}\) is at rest at the origin in system \(\mathcal{S}\); charge \(q_{B}\) flies by at speed \(v\) on a trajectory parallel to the \(x\) axis, but at \(y=d\). What is the clectromagnetic force on \(q_{B}\) as it crosses the \(y\) axis? (b) Now study the same problem from system \(\overline{\mathcal{S}}\), which moves to the right with speed \(v\). What is the force on \(q_{B}\) when \(q_{A}\) passes the \(\bar{y}\) axis? [Do it two ways: (i) by using your answer to (a) and transforming the force; (ii) by computing the fields in \(\overline{\mathcal{S}}\) and using the Lorentz force law.]

Short Answer

Expert verified
In system \( \mathcal{S} \), calculate the electric and magnetic forces to get the net force on \( q_B \). In \( \overline{\mathcal{S}} \), use frame transformation or direct computation to find the equivalent force.

Step by step solution

01

Understanding the Problem

We have two charges, \( q_A \) at rest at the origin in system \( \mathcal{S} \), and \( q_B \) moving with velocity \( v \) parallel to the \( x \)-axis and crossing the \( y \)-axis at \( y = d \). We need to determine the electromagnetic force on \( q_B \) as it crosses the \( y \)-axis in the first scenario, and then transform this setup into another system \( \overline{\mathcal{S}} \).
02

Calculating Force in System \( \mathcal{S} \)

For system \( \mathcal{S} \), where \( q_B \) is moving, the electric force acting on it due to \( q_A \) is given by Coulomb's Law:\[ F = \frac{k_e q_A q_B}{r^2} \]Where \( r = \sqrt{x^2 + d^2} \) is the distance from \( q_A \) to \( q_B \) at \( y = d \) and \( k_e \) is Coulomb's constant. Since \( q_B \) is along the y-axis when crossing, \( x = 0 \) and hence \( r = d \).
03

Calculating the Magnetic Force

Since \( q_B \) is moving with velocity \( v \), it experiences a magnetic field generated by its motion through a stationary electric field created by \( q_A \). The magnetic force \( F_m \) can be determined using:\[ F_m = q_B (v \times B) \]Where \( B \) is the magnetic field at \( y = d \) due to \( q_A \), and can be calculated as \( B = \frac{\mu_0 q_A v}{2\pi d^2} \), resulting in \( F_m = q_B B v \).
04

Calculating Total Force

The net force on \( q_B \) is the vector sum of the electric and magnetic forces calculated earlier:\[ F_{net} = F_{electric} + F_{magnetic} \]The direction and vector nature of these forces must be accounted for in the final net force calculation.
05

Transforming to System \( \overline{\mathcal{S}} \) (i)

In system \( \overline{\mathcal{S}} \), both \( q_A \) and \( q_B \) are observed with the same velocity \( v \), since the whole system is moving rightward at speed \( v \). The forces can be transformed using Lorentz transformations for electromagnetic fields and forces.
06

Direct Computation in System \( \overline{\mathcal{S}} \) (ii)

Compute the fields in the new rest frame of \( \overline{\mathcal{S}} \). With \( q_A \) moving with \( -v \) in this system, its contribution to the magnetic field when it crosses close to position of \( q_B \) must be recalculated using Lorentz transformations, and then apply the Lorentz force law directly.
07

Comparing Results

Confirm that the forces calculated in both methods (i) and (ii) in system \( \overline{\mathcal{S}} \) are consistent, revealing the correct understanding and handling of electromagnetic forces and transformations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is a fundamental principle used to calculate the electric force between two point charges. Imagine two tiny charged objects. They exert a force on each other, which can be attractive or repulsive, depending on their charges. This force is described by the equation:
  • \( F = \frac{k_e q_1 q_2}{r^2} \)
Here, \( F \) is the force between the charges, \( k_e \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the amounts of charge, and \( r \) is the distance between the charges.
Coulomb's Law shows that the force is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.
In the scenario where a charge \( q_B \) moves past a stationary charge \( q_A \), as described in part of your exercise, the moving charge experiences a force explained by this law, which is vital to understanding electromagnetic interactions.
Lorentz Force Law
The Lorentz Force Law is critical for understanding the behavior of charged particles moving in electric and magnetic fields. It states that a charged particle will experience a force when it moves in a magnetic and an electric field.
This law can be expressed by the equation:
  • \( F = q(E + v \times B) \)
In this formula, \( F \) represents the total force on the charge \( q \). Here, \( E \) is the electric field, \( v \) is the velocity of the particle, and \( B \) is the magnetic field.
This law is utilized in the exercise to calculate the magnetic force experienced by \( q_B \) due to its motion in the magnetic field created by \( q_A \).
When charges move through a magnetic field, like in the system described where \( q_B \) experiences both an electric and magnetic influence, the Lorentz Force Law helps predict the resulting movement and direction of the charges.
Lorentz Transformations
Lorentz Transformations are equations that relate the space and time coordinates of two reference frames moving at a constant velocity relative to each other. They are fundamental to the theory of special relativity and are crucial when dealing with high-speed particles or charges.
For the exercise where system \( \overline{\mathcal{S}} \) moves to the right with speed \( v \), Lorentz Transformations help to adjust calculations of forces and fields when seen from another moving reference frame. This is particularly important when switching perspectives between systems \( \mathcal{S} \) and \( \overline{\mathcal{S}} \).
The transformations account for relative motion by using transformations for space and time:
  • \( x' = \gamma(x - vt) \)
  • \( t' = \gamma(t - \frac{vx}{c^2}) \)
Where \( \gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}} \) and \( c \) is the speed of light. These transformations ensure that electromagnetic phenomena appear consistent across different inertial frames.
Using these, the problem extends to compare and verify conditions across different frames, which is essential for your studies of electromagnetism in a dynamic context.
Magnetic Fields
Magnetic Fields are regions around magnets or moving charges where magnetic forces act on other charges. Whenever a charged particle moves, it creates a magnetic field around itself.
In the electric scenario shown in the exercise, a charge \( q_A \) at rest forms an electric field around it, while a moving charge \( q_B \) generates a magnetic field and experiences one due to its movement.
  • The magnetic field created by a moving charge can be calculated using the Biot-Savart Law, which in simple terms links the velocity, charge, and distance from the moving charge.
Moreover, as stated in the exercise, the magnetic field \( B \) experienced by \( q_B \) is expressed as \( B = \frac{\mu_0 q_A v}{2\pi d^2} \). Here, \( \mu_0 \) is the permeability of free space, \( q_A \) is the stationary charge, \( v \) is the velocity, and \( d \) is the perpendicular distance.
Understanding how magnetic fields interact with moving charges is vital in determining the net force as described by the Lorentz Force Law. This forms the basis for analyzing electromagnetic problems across various frames and is a key learning point in this exercise.

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