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A 1550 kg car moving south at \(10.0 \mathrm{m} / \mathrm{s}\) collides with a \(2550 \mathrm{kg}\) car moving north. The cars stick together and move as a unit after the collision at a velocity of \(5.22 \mathrm{m} / \mathrm{s}\) to the north. Find the velocity of the \(2550 \mathrm{kg}\) car before the collision.

Short Answer

Expert verified
The magnitude of the velocity of the \(2550 \mathrm{kg}\) car before the collision is \(\approx) -7.03 \mathrm{m/s}\), which implies that the car is moving south with a speed of \(7.03 \mathrm{m/s}\).

Step by step solution

01

Identify known quantities

The mass and speed of the first car from the south: \(m_1 = 1550 \mathrm{kg}\) and \(v_1 = 10.0 \mathrm{m} / \mathrm{s}\). The mass of the second car from the north: \(m_2 = 2550 \mathrm{kg}\). The speed and direction of both cars together after the collision: \(V_f = 5.22 \mathrm{m} / \mathrm{s}\) moving to the north. It's important to adopt a consistent convention about direction. Let's take the direction toward the north as positive.
02

Calculate initial and final momentum

Knowing that the total momentum before the collision should equal to the total momentum after the collision (due to the principle of the conservation of momentum), first calculate the initial momentum and the final momentum. The initial momentum is the sum of the momenta of the two cars before the collision: \[P_{i} = m_1 * v_1 + m_2 * v_2\], where \(v_2\) is the velocity of the second car that we don't yet know. The final momentum is the momentum of both cars together (since they stick together) after the collision: \[P_{f} = (m_1 + m_2) * V_f\]. Calculate \(P_{f}\) using the given values.
03

Find the initial velocity of the second car

Now that we have expressions for the initial and final momenta, set them equal to each other: \(P_{i} = P_{f}\). Substitute the known values and expressions from steps 1 and 2, and solve for \(v_2\), the initial velocity of the second car. Note that when the velocity is negative, it indicates that the car is moving toward the south, which is in the opposite direction of our convention.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Collision
In the world of physics, a collision occurs when two or more objects hit each other. Whether it's a car crash or a football player tackling another, the same principles apply. Collisions are categorized into elastic and inelastic types. In an elastic collision, both momentum and kinetic energy are conserved. Meanwhile, inelastic collisions, like the one in our exercise, conserve momentum but not kinetic energy.
In our example, two cars stick together after colliding, which is a classic case of an inelastic collision. As they lock together, they move in a new direction at a combined velocity. Understanding such events helps us analyze movements and forces in everyday situations.
In collisions, various factors like mass, velocity, and direction come into play. In this exercise, determining the velocity of the second car before impact relies heavily on understanding these principles.
Physics Problem Solving
Physics problem solving involves breaking down a scenario into manageable parts. It's like piecing together a puzzle. First, gather all known data—mass, velocity, and direction. Then, identify what you're solving for—in this case, the velocity of one car before impact.
A systematic approach is crucial. Start by defining a positive direction for velocity. In the exercise, north is positive. This consistency aids in clearing potential confusion. Always remember unit conversions if necessary, ensuring calculations are accurate and coherent.
After framing the problem, apply relevant physics principles, like the conservation of momentum. Using known quantities, equate expressions to solve for the unknowns. Logical sequence and attention to details are key to arriving at a satisfactory solution.
Momentum Equation
Momentum is a fundamental physics concept defined as the product of an object's mass and its velocity. Mathematically, it's expressed as \( p = m imes v \). It's a vector quantity, meaning it accounts for both magnitude and direction.
The concept of conservation of momentum states that in a closed system with no external forces, total momentum remains constant. This is a cornerstone for solving collision problems. Before and after any collision, total system momentum should be equal.
In our exercise, the momentum equation helps evaluate initial and final states. The initial momentum is the collective momentum before impact: \( P_i = m_1 imes v_1 + m_2 imes v_2 \). The final momentum combines the masses since the cars stick post-collision: \( P_f = (m_1 + m_2) imes V_f \). Setting these equations equal lets us find the unknown velocity \( v_2 \).
Velocity Calculation
Calculating velocity in physics is about determining the rate at which an object's position changes. It's expressed as meters per second (\( ext{m/s} \)) and can be both positive and negative, indicating direction.
In the collision problem, we calculate the initial velocity of the second car. We set up our conservation of momentum equations, where \( P_i = P_f \). Given \( m_1 = 1550 ext{ kg}, v_1 = 10.0 ext{ m/s} \), and post-collision velocity \( V_f = 5.22 ext{ m/s} \) affecting both cars, calculating the car's initial velocity becomes straightforward.
We solve the equation for \( v_2 \): \[ m_1 imes v_1 + m_2 imes v_2 = (m_1 + m_2) imes V_f \]
By isolating \( v_2 \), students find its value, considering the direction (north or south). It's key to remember the conventions of direction to interpret the result correctly.

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