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If an automobile engine delivers 50.0 hp of power, how much time will it take for the engine to \(\operatorname{do} 6.40 \times\) \(10^{5}\) J of work? (Hint: Note that one horsepower, \(1 \mathrm{hp}\), is equal to \(746 \text { watts. })\)

Short Answer

Expert verified
It will take approximately 17.15 seconds for the engine to do \(6.40 \times 10^{5}\) J of work.

Step by step solution

01

Convert horsepower to watt

Given that \(1 hp = 746 watts\), our engine power will be: \(50.0 hp \times 746 = 37,300 watts\)
02

Use the formula of work

Work equals power times time. Therefore, time can be calculated as: \(Time = \frac{Work}{Power}\)
03

Substitute values into the formula

The work is given as \(6.40 \times 10^{5} J\) and the power calculated in step 1 is \(37,300 watts\). Substituting these values into the formula yields: \(Time = \frac{6.40 \times 10^{5} J}{37,300 watts} ≈ 17.15 seconds\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Converting Horsepower to Watts
When dealing with engines or electrical devices, it's common to encounter the unit of horsepower (hp), which is a measure of power. However, in the realm of physics, particularly when performing calculations, it is often necessary to use the International System of Units (SI). In SI, the unit of power is the watt (W). Understanding how to convert between these units is essential for solving problems correctly.

One horsepower is equivalent to 746 watts. So, if you have an engine that delivers 50.0 hp, you simply multiply this value by 746 to find out how many watts it equals. This is an important conversion to make before performing further calculations because it aligns the units with the standard measurement system used in physics.
Work Energy Theorem
The work-energy theorem is a foundational concept in physics, providing a link between work and the energy of an object. The theorem essentially states that the work done on an object is equal to the change in its kinetic energy. What does this mean in practical terms? When work is done on an object by applying a force over a distance, the object's kinetic energy changes.

If you push a box across a room, the work you do on the box results in an increase in the box's kinetic energy. Conversely, if you apply a force to bring the box to a stop, you are doing negative work, and the box's kinetic energy decreases. This theorem is crucial for understanding how energy is transferred and transformed in physical systems.
Calculating Time from Work and Power
Power is defined as the rate at which work is done. In mathematical terms, power is the amount of work divided by the time it takes to do that work. Rearranging this formula gives us a way to calculate the time it takes to do a certain amount of work when the power is known. This is pivotal when planning tasks or understanding how quickly systems can operate.

To calculate time, you use the formula:\[Time = \frac{Work}{Power}\].By substituting in the amount of work to be done and the power of the device or engine doing the work, you can solve for the time it will take to complete a task. For example, if an automobile engine delivers a certain number of watts of power and has to perform a specified amount of work in joules, you can figure out how long the engine must run to accomplish the work. This concept has wide-ranging applications in everything from industrial machinery to household appliances.

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Most popular questions from this chapter

A person drops a ball from the top of a building while another person on the ground observes the ball's motion. Each observer chooses his or her own location as the level for zero potential energy. Will they calculate the same values for: a. the potential energy associated with the ball? b. the change in potential energy associated with the ball? c. the ball's kinetic energy?

Tarzan swings on a \(30.0 \mathrm{m}\) long vine initially inclined at an angle of \(37.0^{\circ}\) with the vertical. What is his speed at the bottom of the swing if he does the following? a. starts from rest b. starts with an initial speed of \(4.00 \mathrm{m} / \mathrm{s}\)

A \(25 \mathrm{kg}\) child on a \(2.0 \mathrm{m}\) long swing is released from rest when the swing supports make an angle of \(30.0^{\circ}\) with the vertical. a. What is the maximum potential energy associated with the child? b. Disregarding friction, find the child's speed at the lowest position. c. What is the child's total mechanical energy? d. If the speed of the child at the lowest position is \(2.00 \mathrm{m} / \mathrm{s},\) what is the change in mechanical energy due to friction?

A weight is connected to a spring that is suspended vertically from the ceiling. If the weight is displaced downward from its equilibrium position and released, it will oscillate up and down. How many forms of potential energy are involved? If air resistance and friction are disregarded, will the total mechanical energy be conserved? Explain.

Can the speed of an object change if the net work done on it is zero?

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