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See Sample Problem A. A shopper pushes a cart \(40.0 \mathrm{m}\) south down one aisle and then turns \(90.0^{\circ}\) and moves \(15.0 \mathrm{m} .\) He then makes another \(90.0^{\circ}\) turn and moves \(20.0 \mathrm{m}\) Find the shopper's total displacement. (There could be more than one correct answer.)

Short Answer

Expert verified
The total displacement of the shopper is 20.0 m towards the south and 15.0 m towards the west, indicating a south-west direction of displacement.

Step by step solution

01

Understand the problem and visualize the movement of the cart

The shopper first travels south a distance of 40.0 m, then the shopper turns 90 degrees and moves 15.0 m. The shopper turns 90 degrees again and travels a distance of 20.0 m. These movements form a rectangle. Each turn of 90 degrees does not affect the resting position of the shopper and can be thought of as changing the direction of subsequent movements.
02

Breaking down the total displacement

The total displacement is calculated by adding all different displacements. It is composed of three parts. The first displacement, \(d_1\), is in the south direction and has a magnitude of 40.0 m. The second displacement, \(d_2\), is in the west direction and has a magnitude of 15.0 m (since a 90 degrees turn to the left (from South) will be West). The third displacement, \(d_3\), is in the north direction and has a magnitude of 20.0 m (since another 90 degrees turn to the left (from West) will be North).
03

Calculating total displacement

Due to the rectangular direction of the shopper's movement, we calculate the resultant of displacement vector as the sum of his movements. The total displacement in the north-south direction would be the initial movement south subtracted by the final movement north, which comes up to be \(40.0m - 20.0m = 20.0m\). Here, it is still South as initial movement was more. In the east-west direction, the shopper has only moved west, so that will be the displacement in that direction, which is -15.0m. These two displacements combine to give the total displacement, which results in a vector pointing south-west.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
In physics, vectors are essential tools because they have both magnitude (size) and direction. When a problem involves multiple vectors, like our shopper's path, we need to use vector addition to determine the overall effect.

- **Vectors**: Think of vectors as arrows, each with a certain length and pointing in a specific direction.
- **Vector Addition**: When adding vectors, you place the tail of the next vector at the head of the previous one. This can help in visualizing and calculating the resultant vector — the vector that represents the total displacement.

In our shopper's journey, the total displacement can be seen as adding three separate vectors: south (40.0 m), west (15.0 m), and north (20.0 m). It's important to keep track of directions because they impact how vectors add up. For instance, the opposite directions (north and south) partially cancel each other out.
Rectilinear Motion
Rectilinear motion refers to movement along a straight line. In many physics problems, it can be simplified to horizontal or vertical components.

- **Straight Paths**: Even though the shopper turns, each segment of the path is a straight line.
- **Component Breakdown**: By breaking movement down into individual segments (south, west, north), we can analyze each one separately.

This simplifies the process of finding displacement because we can focus on one direction at a time. For instance, the movement south and north are in opposite directions along the same straight line, allowing us to calculate the resulting displacement directly by subtraction.
Magnitude and Direction
Determining the magnitude and direction of the resultant displacement is the key objective in problems involving vector operations.

- **Magnitude**: This refers to the length of the resultant vector and is often calculated using the Pythagorean theorem when dealing with perpendicular components. For our shopper, we can combine the south and west displacements to find the overall magnitude of his displacement.
- **Direction**: The direction of the resultant vector is given relative to a reference direction. For instance, a vector pointing southwest indicates a shift both towards the south and the west.

By understanding both the magnitude and direction, one can fully describe the resultant displacement of the shopper, as being 20.0 m south and 15.0 m west. This combination results in a diagonal path toward the southwest.

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Most popular questions from this chapter

A ball is projected horizontally from the edge of a table that is \(1.00 \mathrm{m}\) high, and it strikes the floor at a point \(1.20 \mathrm{m}\) from the base of the table. a. What is the initial speed of the ball? b. How high is the ball above the floor when its velocity vector makes a \(45.0^{\circ}\) angle with the horizontal?

A boat moves through a river at \(7.5 \mathrm{m} / \mathrm{s}\) relative to the water, regardless of the boat's direction. If the water in the river is flowing at \(1.5 \mathrm{m} / \mathrm{s}\), how long does it take the boat to make a round trip consisting of a \(250 \mathrm{m}\) displacement downstream followed by a \(250 \mathrm{m}\) displacement upstream?

A place kicker must kick a football from a point \(36.0 \mathrm{m} \text { (about } 40.0 \mathrm{yd})\) from the goal. As a result of the kick, the ball must clear the crossbar, which is \(3.05 \mathrm{m}\) high. When kicked, the ball leaves the ground with a speed of \(20.0 \mathrm{m} / \mathrm{s}\) at an angle of \(53^{\circ}\) to the horizontal. a. By how much does the ball clear or fall short of clearing the crossbar? b. Does the ball approach the crossbar while still rising or while falling?

Explain the difference between vector addition and vector resolution.

A spy in a speed boat is being chased down a river by government officials in a faster craft. Just as the officials' boat pulls up next to the spy's boat, both boats reach the edge of a \(5.0 \mathrm{m}\) waterfall. If the spy's speed is \(15 \mathrm{m} / \mathrm{s}\) and the officials' speed is \(26 \mathrm{m} / \mathrm{s}\) how far apart will the two vessels be when they land below the waterfall?

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