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See Sample Problem \(B\). A wire carries a 10.0 A current at an angle \(90.0^{\circ}\) from the direction of a magnetic field. If the magnitude of the magnetic force on a 5.00 m length of the wire is \(15.0 \mathrm{N},\) what is the strength of the magnetic field?

Short Answer

Expert verified
The strength of the magnetic field is \(0.3 \) T.

Step by step solution

01

Identify the Given Values

The problem provides the following information: Current (I) = 10.0 A, Length of wire (L) = 5.00 m, Force (F) = 15.0 N,Angle (φ) = 90 degrees. We're asked to find the strength of the magnetic field (B).
02

Rewrite the Formula

The objective is to find the value of magnetic field strength \( B \). So, the formula \( F = BIL \sin(\phi) \) has to be rearranged to solve for \( B \). The rearranged formula becomes \( B = F / (IL \sin(\phi) ) \).
03

Insert the Given Values

Now, plug in the given values into the formula \( B = F / (IL \sin(\phi) ) \), where \( F = 15.0 \) N, \( I = 10.0 \) A, \( L = 5.0 \) m and \( \phi = \sin(90^{\circ}) \). It should be noted that the since \( \sin(90^{\circ}) \) is 1, the equation simplifies as \( B = 15.0 / (10.0 * 5.0 )\).
04

Calculate the Magnetic Field Strength

Finally, perform the calculation to yield the magnetic field strength. \( B = 15.0 / (10.0 * 5.0) \) simplifies to \( B = 0.3 \) T (Tesla, the SI unit of magnetic field strength).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetism
Electromagnetism is a branch of physics that investigates the electromagnetic force, a type of physical interaction that occurs between electrically charged particles. It encompasses phenomena such as electricity, magnetism, and the interaction between charged particles. The basic principle behind electromagnetism is that electric currents and magnetic fields are interconnected; an electric current can produce a magnetic field, and a magnetic field can induce an electric current. This relationship is fundamental to many technologies, such as electric motors, generators, and transformers.

Understanding electromagnetism also involves exploring units like Tesla (T), which is the unit of magnetic field strength or magnetic flux density. In the textbook exercise, we explore the effect of a magnetic field on a current-carrying wire, an application of electromagnetism, to determine the field's strength.
Magnetic Force
Magnetic force is the force exerted by a magnetic field on a moving charge or a current-carrying conductor. When charged particles move through a magnetic field, they experience a force that is perpendicular to both their velocity and the direction of the field. This is what happened in the textbook exercise, where a wire carrying an electric current is subjected to a magnetic force due to an external magnetic field. The magnitude of this force can be calculated using the formula
\[ F = BIL \sin(\phi) \]
where F is the magnetic force, B is the magnetic field strength, I is the current, L is the length of the wire in the field, and \( \phi \) is the angle between the direction of the current and the magnetic field. In the exercise problem, the provided angle of 90 degrees between the field and the current maximizes the force experienced by the wire, as \( \sin(90^\circ) \) equals 1.
Lorentz Force Law
The Lorentz force law describes the effect of electric and magnetic fields on a point charge. It states that the total force F experienced by a charge q moving with a velocity v in the presence of electric field E and magnetic field B is given by
\[ F = q(E + v \times B) \]
This force law explains the behavior of charged particles in electromagnetic fields, predicting their trajectories and dynamics. In our exercise, only the magnetic component of the Lorentz force is considered, since the wire is placed in a magnetic field and carries a current but no electric field is mentioned. By understanding the Lorentz force law, students can grasp how magnetic fields interact with charged particles, an essential concept in electromagnetism and the foundation for solving many physics problems involving charged particles or current-carrying wires.
Physics Problem Solving
Physics problem solving is a critical skill that involves understanding physics principles, identifying relevant formulas, and executing calculations accurately. In the context of the textbook exercise, we started by identifying the given values and the unknown we were asked to solve for: the magnetic field strength. Once identified, we moved to apply the relevant formula, and for this problem, we utilized the equation related to magnetic force on a current-carrying conductor. It is important to manipulate the formula correctly to isolate the variable of interest, which involves algebraic skills.

After rearranging the equation to solve for the magnetic field strength (\( B \)), we substituted in the given values for force (\( F \)), current (\( I \)), length of the wire (\( L \)), and the angle \( \phi \), considering the trigonometric function for the angle provided. Finally, we performed the calculation by following the mathematical operations, yielding the result in the correct SI unit, Tesla. The step-by-step process used in the problem not only led to the answer but also reinforces a systematic approach to solving physics problems.

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Most popular questions from this chapter

A proton moving perpendicular to a magnetic field of strength 3.5 mT experiences a force due to the field of \(4.5 \times 10^{-21} \mathrm{N} .\) Calculate the following: a. the speed of the proton b. the kinetic energy of the proton Recall that a proton has a charge of \(1.60 \times 10^{-19} \mathrm{C}\) and a mass of \(1.67 \times 10^{-27} \mathrm{kg}.\)

A proton travels with a speed of \(3.0 \times 10^{6} \mathrm{m} / \mathrm{s}\) at an angle of \(37^{\circ}\) west of north. A magnetic field of 0.30 T points to the north. Determine the following: a. the magnitude of the magnetic force on the proton. b. the direction of the magnetic force on the proton. c. the proton's acceleration as it moves through the magnetic field. (Hint: The magnetic force experienced by the proton in the magnetic field is proportional to the component of the proton's velocity that is perpendicular to the magnetic field.)

Review Questions Can a stationary magnetic field set a resting electron in motion? Explain.

Conceptual Questions A solenoid with ends marked \(A\) and \(B\) is suspended by a thread so that the core can rotate in the horizontal plane. A current is maintained in the coil so that the electrons move clockwise when viewed from end \(A\) toward end \(B .\) How will the coil align itself in Earth's magnetic field?

Conceptual Questions If a solenoid were suspended by a string so that it could rotate freely, could it be used as a compass when it carried a direct current? Could it also be used if the current were alternating in direction?

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