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Show that the volume expansion coefficient of an ideal gas is \(\beta=1 / T\), where \(T\) is the absolute temperature.

Short Answer

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Question: Show that the volume expansion coefficient of an ideal gas is inversely proportional to the absolute temperature. Answer: The volume expansion coefficient (β) of an ideal gas is inversely proportional to the absolute temperature, which means β = 1 / T.

Step by step solution

01

Understand the volume expansion coefficient and ideal gas law

The volume expansion coefficient (β) of a substance is a measure of how the volume of the substance changes with temperature, at a constant pressure. Mathematically, it is defined as: \(\beta = \frac{1}{V} \frac{\partial V}{\partial T}\Big|_P\) where V is the volume, T is the absolute temperature, and P is the pressure. The ideal gas law relates the pressure (P), volume (V), and temperature (T) of an ideal gas: \(PV = nRT\) where n is the number of moles of the gas and R is the ideal gas constant.
02

Express the volume as a function of temperature and pressure

From the ideal gas law, we can express the volume (V) as a function of temperature (T) and pressure (P): \(V = \frac{nRT}{P}\)
03

Calculate the partial derivative of the volume with respect to the temperature

Now, we will calculate the partial derivative of the volume with respect to the temperature (keeping the pressure constant): \(\frac{\partial V}{\partial T}\Big|_P = \frac{\partial}{\partial T} \left(\frac{nRT}{P}\right)\Big|_P = \frac{nR}{P}\) Here, we treat n, R, and P as constants.
04

Calculate the volume expansion coefficient

Finally, we will plug our expression for the partial derivative of the volume with respect to the temperature back into the equation for the volume expansion coefficient: \(\beta = \frac{1}{V} \frac{\partial V}{\partial T}\Big|_P = \frac{1}{\frac{nRT}{P}} \frac{nR}{P}\) Simplifying, we get: \(\beta = \frac{1}{T}\) Therefore, the volume expansion coefficient of an ideal gas is inversely proportional to the absolute temperature, β = 1 / T.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a fundamental equation in thermodynamics, which describes how gases behave under various conditions. It connects pressure \(P\), volume \(V\), and temperature \(T\) in a simple way. The law is expressed as:\[PV = nRT\]where:
  • \(n\) represents the number of moles of the gas.
  • \(R\) is the ideal gas constant, valued at 8.314 J/(mol·K).
This equation implies that if you know any three properties of a gas, you can calculate the fourth. The relationship shows that as temperature increases, volume increases if pressure remains constant. It forms the basis for understanding gas behaviors and is widely applicable in various science fields. This can be particularly helpful when dealing with changes in conditions such as temperature and pressure.
Volume Change with Temperature
Volume change with temperature is often observed in gases and is measured by the volume expansion coefficient \(\beta\). This coefficient indicates how much the volume of a substance changes with a temperature shift while under constant pressure. Mathematically, it's expressed as:\[\beta = \frac{1}{V} \frac{\partial V}{\partial T}\Big|_P\]The intuition here is simple: if you heat a gas, it will generally expand or increase in volume if the pressure is the same. For ideal gases, as derived in the exercise, \(\beta = \frac{1}{T}\), indicating that the expansion is inversely proportional to temperature. This insight is critical for applications like designing systems and processes where temperature fluctuations are a concern.
Partial Derivative
Partial derivatives play a vital role in understanding how a function changes as one specific variable changes, while others are held constant. It's a common tool in calculus used to explore multi-variable functions. In the context of thermodynamics, it helps us determine the rate of change of variables like volume and temperature.For instance, in calculating the volume expansion coefficient of an ideal gas, the partial derivative of volume with respect to temperature is:\[\frac{\partial V}{\partial T}\Big|_P = \frac{nR}{P}\]This step is crucial because it shows how the volume changes as temperature changes, specifically when pressure is held steady. Understanding partial derivatives helps in analyzing complex systems where multiple factors interact.
Thermodynamics
Thermodynamics is the branch of physics that deals with heat, work, and energy. It examines how energy is transferred and transformed within systems. The fundamental laws of thermodynamics provide the framework for understanding these processes. Key principles include:
  • Energy can neither be created nor destroyed (First Law of Thermodynamics).
  • The entropy of a system tends to increase (Second Law of Thermodynamics).
With regards to gas laws, thermodynamics helps explain how gases expand and contract with changes in temperature and pressure. The concept of the volume expansion coefficient, as discussed in the exercise, is a perfect example of applying thermodynamic principles to predict how an ideal gas will behave under specific conditions. Understanding these relationships is vital in fields ranging from engineering to natural sciences.

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Most popular questions from this chapter

In an ordinary double-pane window, about half of the heat transfer is by radiation. Describe a practical way of reducing the radiation component of heat transfer.

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A solar collector consists of a horizontal aluminum tube of outer diameter \(5 \mathrm{~cm}\) enclosed in a concentric thin glass tube of \(7 \mathrm{~cm}\) diameter. Water is heated as it flows through the aluminum tube, and the annular space between the aluminum and glass tubes is filled with air at \(1 \mathrm{~atm}\) pressure. The pump circulating the water fails during a clear day, and the water temperature in the tube starts rising. The aluminum tube absorbs solar radiation at a rate of \(20 \mathrm{~W}\) per meter length, and the temperature of the ambient air outside is \(30^{\circ} \mathrm{C}\). Approximating the surfaces of the tube and the glass cover as being black (emissivity \(\varepsilon=1\) ) in radiation calculations and taking the effective sky temperature to be \(20^{\circ} \mathrm{C}\), determine the temperature of the aluminum tube when equilibrium is established (i.e., when the net heat loss from the tube by convection and radiation equals the amount of solar energy absorbed by the tube). For evaluation of air properties at \(1 \mathrm{~atm}\) pressure, assume \(33^{\circ} \mathrm{C}\) for the surface temperature of the glass cover and \(45^{\circ} \mathrm{C}\) for the aluminum tube temperature. Are these good assumptions?

A 0.5-m-long thin vertical copper plate is subjected to a uniform heat flux of \(1000 \mathrm{~W} / \mathrm{m}^{2}\) on one side, while the other side is exposed to air at \(5^{\circ} \mathrm{C}\). Determine the plate midpoint temperature for \((a)\) a highly polished surface and \((b)\) a black oxidized surface. Hint: The plate midpoint temperature \(\left(T_{L / 2}\right)\) has to be found iteratively. Begin the calculations by using a film temperature of \(30^{\circ} \mathrm{C}\).

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