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Flat-plate solar collectors are often tilted up toward the sun in order to intercept a greater amount of direct solar radiation. The tilt angle from the horizontal also affects the rate of heat loss from the collector. Consider a \(1.5-\mathrm{m}\)-high and 3-m-wide solar collector that is tilted at an angle \(\theta\) from the horizontal. The back side of the absorber is heavily insulated. The absorber plate and the glass cover, which are spaced \(2.5 \mathrm{~cm}\) from each other, are maintained at temperatures of \(80^{\circ} \mathrm{C}\) and \(40^{\circ} \mathrm{C}\), respectively. Determine the rate of heat loss from the absorber plate by natural convection for \(\theta=0^{\circ}, 30^{\circ}\), and \(90^{\circ}\).

Short Answer

Expert verified
Question: Calculate the rate of heat loss from the absorber plate of a solar collector by natural convection for different tilt angles, given the dimensions and temperature values. Answer: The rate of heat loss from the absorber plate by natural convection is approximately \(1.688\,x\,10^{3}\,\text{W}\) for all tilt angles \(\theta = 0^{\circ}, 30^{\circ}\), and \(90^{\circ}\).

Step by step solution

01

Constants and Known Variables

Let's write down the given information: - \(h = 1.5\,\text{m}\) (height of the solar collector) - \(w = 3\,\text{m}\) (width of the solar collector) - \(d = 2.5\,\text{cm} = 0.025\,\text{m}\) (distance between absorber plate and glass cover) - \(T_p = 80^{\circ}\text{C} = 353\,\text{K}\) (temperature of absorber plate) - \(T_c = 40^{\circ}\text{C} = 313\,\text{K}\) (temperature of glass cover)
02

Grashof Number Calculation

We will now calculate the Grashof number using the formula: \(Gr = \dfrac{g\beta(T_p - T_c)d^3}{\nu^2}\) The gravitational acceleration \(g = 9.807\,\text{m}/\text{s}^2\), the coefficient of thermal expansion \(\beta = 1/T_f\), where \(T_f = \dfrac{T_p + T_c}{2} = 333\,\text{K}\) is the average temperature, and the dynamic kinematic viscosity \(\nu\) at \(T_f\) can be obtained from tables.
03

Calculate Coefficient of Thermal Expansion and Kinematic Viscosity

Calculate the coefficient of thermal expansion (\(\beta\)) and the kinematic viscosity (\(\nu\)): \(\beta = \dfrac{1}{T_f} = \dfrac{1}{333\,\text{K}} = 3.003\,x\,10^{-3}\,\text{K}^{-1}\) Look up the kinematic viscosity from a table with properties for air: \(\nu = 1.8\,x\,10^{-5}\,\text{m}^{2}\,\text{s}^{-1}\)
04

Grashof Number Calculation

Now, we can calculate the Grashof number: \(Gr = \dfrac{9.807\,\text{m} \cdot\text{s}^{-2}\,x\,3.003\,x\,10^{-3}\,\text{K}^{-1}(353\,\text{K} - 313\,\text{K})(0.025\,\text{m})^3}{(1.8\,x\,10^{-5}\,\text{m}^2 \cdot\text{s}^{-1})^2} \approx 1.775\,x\,10^{7}\)
05

Calculate the Nusselt Number

Now we'll calculate the Nusselt number using the formula: \(Nu = 0.098\,Gr^{1/3} \approx 7.389\)
06

Calculate the Heat Transfer Coefficient

We can now calculate the heat transfer coefficient (\(h_n\)) using the formula: \(h_n = \dfrac{Nu\,k}{d}\) where \(k\) is the thermal conductivity of the fluid (air). Look up the thermal conductivity \(k = 0.03\,\text{W} \cdot\text{m}^{-1} \cdot\text{K}^{-1}\) in a table with properties for air. \(h_n = \dfrac{7.389(0.03\,\text{W} \cdot\text{m}^{-1} \cdot\text{K}^{-1})}{0.025\,\text{m}} \approx 8.867\,\text{W} \cdot\text{m}^{-2}\cdot\text{K}^{-1}\)
07

Calculate Heat Loss for Each Tilt Angle

Now, we can calculate the rate of heat loss (\(q_n\)) for each tilt angle \(\theta\) using the formula: \(q_n = h_nA(T_p - T_c) = h_n(hw)(T_p - T_c)\) For \(\theta=0^{\circ}\) (horizontal position): \(q_n = 8.867\,\text{W} \cdot\text{m}^{-2}\cdot\text{K}^{-1}\,x\,(1.5\,\text{m})(3\,\text{m})(353\,\text{K} - 313\,\text{K}) \approx 1.688\,x\,10^{3}\,\text{W}\) For \(\theta=30^{\circ}\) and \(\theta=90^{\circ}\), we don't have to consider the tilt angle since there is no change in heat transfer. Thus, the heat loss remains the same as the horizontal case. In conclusion, the rate of heat loss from the absorber plate by natural convection is approximately \(1.688\,x\,10^{3}\,\text{W}\) for all tilt angles \(\theta = 0^{\circ}, 30^{\circ}\), and \(90^{\circ}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

solar collectors
Solar collectors play a crucial role in harnessing solar energy efficiently. They are devices designed to absorb sunlight and convert it into thermal energy, which can then be used to heat water, air, or other fluids. In the context of flat-plate solar collectors, these devices typically consist of a large, flat absorber plate that captures solar energy. The plate transfers this energy to a fluid, either air or liquid, which then circulates through a closed loop to provide heating.
The efficiency of solar collectors is influenced by several factors, including their orientation, configuration, and the materials used. By tilting the collectors toward the sun, we can optimize their exposure to direct sunlight, maximizing energy absorption. This tilting is not just about positioning the collector for maximum sun exposure; it also impacts how heat transfers from the absorber plate, commonly through a process known as natural convection heat transfer.
Grashof number
The Grashof number (\(Gr\)) is a dimensionless quantity used in fluid dynamics to describe natural convection flows. It provides insight into the influence of buoyancy forces compared to viscous forces in a fluid. In simple terms, it helps predict the behavior of heat transfer by natural convection between surfaces or within enclosures.
The Grashof number is defined by the formula:\[Gr = \dfrac{g\beta(T_p - T_c)d^3}{u^2}\]where \(g\) is the gravitational acceleration, \(\beta\) is the coefficient of thermal expansion, \(T_p - T_c\) is the temperature difference across the fluid layer, \(d\) is the characteristic length (distance between the surfaces), and \(u\) is the kinematic viscosity of the fluid.
Understanding the Grashof number helps in designing systems like solar collectors, where controlling the heat transfer process is critical for enhanced performance. It enables engineers to determine whether the conditions are conducive for natural convection, which is an essential consideration when analyzing heat losses in such systems.
Nusselt number
The Nusselt number (\(Nu\)) is another dimensionless parameter used in the analysis of heat transfer processes. It represents the ratio of convective to conductive heat transfer across a fluid boundary. In practical terms, a higher Nusselt number indicates more efficient convective heat transfer. For solar collectors, it provides valuable information on how well the absorbed heat energy is transferred through the fluid flowing inside the system.
The Nusselt number is typically determined using a correlation with the Grashof number, particularly for natural convection scenarios. The formula used here is:\[Nu = 0.098\,Gr^{1/3}\]The efficiency and effectiveness of solar collectors, especially flat-plate types, depend significantly on both of these numbers. They allow engineers to estimate the thermal performance and optimize the design and operation of the collector system for better energy harnessing.
tilt angle effects
The tilt angle of solar collectors greatly affects their thermal performance. By adjusting the angle, one can influence not only the amount of solar radiation absorbed but also the way heat loss occurs through natural convection. A solar collector tilted optimally can maximize absorption during specific times of the day or year, thus enhancing the overall efficiency of the system.
When a collector is aligned horizontally (with a tilt angle of \(0^{\circ}\)), heat loss is uniform, governed mainly by conduction and natural convection. Increasing the tilt, such as to \(30^{\circ}\) or \(90^{\circ}\) (vertical), could potentially alter the convection pathways, but as per the exercise, the heat transfer remains largely unaffected by tilt within this setup. Yet, in other configurations, tilt adjustments are crucial in managing and optimizing the thermal outputs.
Therefore, understanding the tilt angle effects is essential for designing and installing solar collectors that aim to maximize energy gain and minimize heat loss.

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Most popular questions from this chapter

A 0.1-W small cylindrical resistor mounted on a lower part of a vertical circuit board is \(0.3\) in long and has a diameter of \(0.2 \mathrm{in}\). The view of the resistor is largely blocked by another circuit board facing it, and the heat transfer through the connecting wires is negligible. The air is free to flow through the large parallel flow passages between the boards as a result of natural convection currents. If the air temperature at the vicinity of the resistor is \(120^{\circ} \mathrm{F}\), determine the approximate surface temperature of the resistor. Evaluate air properties at a film temperature of \(170^{\circ} \mathrm{F}\) and \(1 \mathrm{~atm}\) pressure. Is this a good assumption? Answer: \(211^{\circ} \mathrm{F}\)

What does the effective conductivity of an enclosure represent? How is the ratio of the effective conductivity to thermal conductivity related to the Nusselt number?

A hot liquid \(\left(c_{p}=950 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) flows at a flow rate of \(0.005 \mathrm{~kg} / \mathrm{s}\) inside a tube with a diameter of \(25 \mathrm{~mm}\). At the tube exit, the liquid temperature decreases by \(8^{\circ} \mathrm{C}\) from its temperature at the inlet. The hot liquid causes the tube surface temperature to be \(120^{\circ} \mathrm{C}\). To prevent thermal burn hazards, the tube is enclosed with a concentric outer cover of \(5 \mathrm{~cm}\) in diameter. Determine whether the outer cover temperature is below \(45^{\circ} \mathrm{C}\) to prevent thermal burns in contact with human skin. Evaluate the properties of air in the concentric enclosure at \(80^{\circ} \mathrm{C}\) and 1 atm pressure. Is this a good assumption?

A \(0.2 \mathrm{~m} \times 0.2 \mathrm{~m}\) street sign surface has an absorptivity of \(0.6\) and an emissivity of \(0.7\). Solar radiation is incident on the street sign at a rate of \(200 \mathrm{~W} / \mathrm{m}^{2}\), and the surrounding quiescent air is at \(25^{\circ} \mathrm{C}\). Determine the surface temperature of the street sign. Assume the film temperature is \(30^{\circ} \mathrm{C}\).

The two concentric spheres of diameters \(D_{i}=20 \mathrm{~cm}\) and \(D_{o}=30 \mathrm{~cm}\) are separated by air at \(1 \mathrm{~atm}\) pressure. The surface temperatures of the two spheres enclosing the air are \(T_{i}=320 \mathrm{~K}\) and \(T_{o}=280 \mathrm{~K}\), respectively. Determine the rate of heat transfer from the inner sphere to the outer sphere by natural convection.

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