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A tube with a bell-mouth inlet configuration is subjected to uniform wall heat flux of \(3 \mathrm{~kW} / \mathrm{m}^{2}\). The tube has an inside diameter of \(0.0158 \mathrm{~m}(0.622 \mathrm{in})\) and a flow rate of \(1.43 \times\) \(10^{-4} \mathrm{~m}^{3} / \mathrm{s}(2.27 \mathrm{gpm})\). The liquid flowing inside the tube is ethylene glycol-distilled water mixture with a mass fraction of \(2.27\). Determine the fully developed friction coefficient at a location along the tube where the Grashof number is \(\mathrm{Gr}=\) 16,600 . The physical properties of the ethylene glycol-distilled water mixture at the location of interest are \(\operatorname{Pr}=14.85, \nu=\) \(1.93 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\), and \(\mu_{b} / \mu_{s}=1.07\).

Short Answer

Expert verified
Answer: The fully developed friction coefficient is approximately 0.01910.

Step by step solution

01

1. Calculate the Grashof Number

Given in the exercise is the Grashof number: \(\mathrm{Gr} =\) 16,600. We will use this value later in the analysis.
02

2. Determine the Reynolds number.

We can find the Reynolds number using the flow rate \((Q)\), the kinematic viscosity \((\nu)\), and the diameter of the tube \((D)\), using the relation: $$\textit{Re} = \frac{4Q}{\pi D \nu}.$$ For our problem, we have \(Q = 1.43 \times 10^{-4} \mathrm{~m}^{3} / \mathrm{s}\), \(D = 0.0158 \mathrm{~m}\), and \(\nu = 1.93 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\). Plugging these values, we get: $$\textit{Re} = \frac{4(1.43 \times 10^{-4})}{\pi(0.0158)(1.93 \times 10^{-6})} \approx 1026.$$
03

3. Calculate the buoyancy adjusted Reynolds number.

Use the given ratio of \(\mu_b/\mu_s = 1.07\) (bulk viscosity to surface viscosity) to calculate the buoyancy adjusted Reynolds number by the following equation: $$\textit{Re}_b = \textit{Re}(\frac{\mu_b}{\mu_s}) = 1026(1.07) \approx 1097.81.$$
04

4. Determining the friction factor.

Now, with the given Prandtl number of the fluid, \(\operatorname{Pr} = 14.85\), we can use the Grashof number \((\mathrm{Gr})\) and the buoyancy adjusted Reynolds number \((\textit{Re}_b)\) to calculate the fully developed friction factor \((f)\), given by the Petukhov-Kirillov equation: $$f = \frac{0.79 \operatorname{ln}\left(\textit{Re}_b\right) - 1.64}{\textit{Re}_b} \left[1+\textstyle\frac{185}{\textit{Re}_b^{1.5}} \frac{\mathrm{Gr}}{\textit{Re}_b \operatorname{Pr}}\right]^{\frac{1}{0.3}}.$$ Substituting the given values and simplifying, we get: $$f = \frac{0.79 \operatorname{ln}\left(1097.81\right) - 1.64}{1097.81} \left[1+\frac{185}{1097.81^{1.5}} \frac{16600}{1097.81 \times 14.85}\right]^{\frac{1}{0.3}} \approx 0.01910.$$ The fully developed friction coefficient at the location along the tube with Grashof number 16,600 is 0.01910.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Grashof Number
The Grashof number is a dimensionless number that helps in understanding natural convection processes in fluid flow. It essentially measures the ratio between buoyancy forces, which drive flow, and viscous forces, which resist flow. Think of it as a way to determine whether the flow is more likely to be buoyancy-driven or not. The Grashof number is given by the formula:\[ \text{Gr} = \frac{g \beta (T_m - T_c) L^3}{u^2} \]where
  • g is the acceleration due to gravity.
  • β is the coefficient of thermal expansion.
  • Tm and Tc are the temperatures of the fluid at two different points.
  • L is the characteristic length.
  • ν is the kinematic viscosity.
A high Grashof number indicates that buoyancy forces are dominant, making natural convection significant. In our exercise, the Grashof number of 16,600 suggests a moderate role of buoyancy in the system's heat transfer process.
Reynolds Number
The Reynolds number is another vital dimensionless quantity in fluid mechanics, indicating whether a flow will be laminar or turbulent. It represents the ratio of inertial forces to viscous forces in the fluid. The formula to calculate the Reynolds number is:\[ \(\textit{Re}\) = \frac{VD}{u} \]where
  • V is the fluid velocity.
  • D is the diameter of the tube or characteristic length.
  • ν is the kinematic viscosity.
In the step-by-step solution, the calculated Reynolds number was 1026, suggesting a transitional flow, which means the flow is neither entirely laminar nor fully turbulent. This information is crucial in determining factors like heat transfer rates and pressure drops within the tube, alongside the friction factor later on.
Friction Factor
The friction factor is a dimensionless number used in calculating the pressure drop or head loss due to friction in a pipe or duct. This factor is essential in the engineering and modeling of fluid systems, linking flow behavior and pipe characteristics. It is often determined using known equations such as the Petukhov-Kirillov equation for turbulent flow. This is given by:\[ f = \frac{0.79 \operatorname{ln}(\(\textit{Re}\)_b) - 1.64}{\(\textit{Re}\)_b} \left[1+\frac{185}{\(\textit{Re}\)_b^{1.5}} \frac{\mathrm{Gr}}{\(\textit{Re}\)_b \operatorname{Pr}}\right]^{\frac{1}{0.3}}\]Our exercise applies this equation using the Prandtl number, Grashof number, and Reynolds number to find a fully developed friction factor of approximately 0.01910. This factor plays a vital role in evaluating the energy loss due to fluid friction, which is critical for designing efficient thermal systems.
Prandtl Number
The Prandtl number is a dimensionless quantity that acts as a bridge between thermal diffusion and momentum diffusion in a fluid medium. It tells us how fast heat is conducted relative to the rate at which momentum is transferred. The formula of the Prandtl number is given by:\[ \operatorname{Pr} = \frac{u}{\alpha} \]where
  • ν is the kinematic viscosity.
  • α is the thermal diffusivity.
In simpler terms, the Prandtl number describes whether the velocity boundary layer will grow faster than the thermal boundary layer or vice versa. A high Prandtl number, like the 14.85 seen in this problem, indicates that the fluid's viscosity heavily influences its thermal characteristics. Understanding these influences is crucial in predicting and controlling the efficiency of heat transfer processes in various engineering applications.

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Most popular questions from this chapter

A \(15-\mathrm{cm} \times 20\)-cm printed circuit board whose components are not allowed to come into direct contact with air for reliability reasons is to be cooled by passing cool air through a 20 -cm-long channel of rectangular cross section \(0.2 \mathrm{~cm} \times 14 \mathrm{~cm}\) drilled into the board. The heat generated by the electronic components is conducted across the thin layer of the board to the channel, where it is removed by air that enters the channel at \(15^{\circ} \mathrm{C}\). The heat flux at the top surface of the channel can be considered to be uniform, and heat transfer through other surfaces is negligible. If the velocity of the air at the inlet of the channel is not to exceed \(4 \mathrm{~m} / \mathrm{s}\) and the surface temperature of the channel is to remain under \(50^{\circ} \mathrm{C}\), determine the maximum total power of the electronic components that can safely be mounted on this circuit board. As a first approximation, assume flow is fully developed in the channel. Evaluate properties of air at a bulk mean temperature of \(25^{\circ} \mathrm{C}\). Is this a good assumption?

A tube with a square-edged inlet configuration is subjected to uniform wall heat flux of \(8 \mathrm{~kW} / \mathrm{m}^{2}\). The tube has an inside diameter of \(0.622\) in and a flow rate of \(2.16 \mathrm{gpm}\). The liquid flowing inside the tube is ethylene glycol-distilled water mixture with a mass fraction of \(2.27\). Determine the friction coefficient at a location along the tube where the Grashof number is \(\mathrm{Gr}=35,450\). The physical properties of the ethylene glycol-distilled water mixture at the location of interest are \(\operatorname{Pr}=13.8, v=18.4 \times 10^{-6} \mathrm{ft}^{2} / \mathrm{s}\), and \(\mu_{b} / \mu_{s}=1.12\). Then recalculate the fully developed friction coefficient if the volume flow rate is increased by 50 percent while the rest of the parameters remain unchanged.

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What do the average velocity \(V_{\mathrm{avg}}\) and the mean temperature \(T_{m}\) represent in flow through circular tubes of constant diameter?

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