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Determine the convection heat transfer coefficient for the flow of \((a)\) air and \((b)\) water at a velocity of \(2 \mathrm{~m} / \mathrm{s}\) in an \(8-\mathrm{cm}\) diameter and 7-m-long tube when the tube is subjected to uniform heat flux from all surfaces. Use fluid properties at \(25^{\circ} \mathrm{C}\).

Short Answer

Expert verified
(a) The convection heat transfer coefficient for the flow of air inside the tube is approximately 44.73 W/(m虏路K). (b) The convection heat transfer coefficient for the flow of water inside the tube is approximately 43346.84 W/(m虏路K).

Step by step solution

01

Obtain fluid properties at 25掳C

For air at 25掳C: - Density (蟻) = 1.184 kg/m鲁 - Specific heat (Cp) = 1005 J/(kg路K) - Thermal conductivity (k) = 0.02624 W/(m路K) - Dynamic viscosity (渭) = 1.849x10鈦烩伒 kg/(m路s) For water at 25掳C: - Density (蟻) = 997 kg/m鲁 - Specific heat (Cp) = 4182 J/(kg路K) - Thermal conductivity (k) = 0.6075 W/(m路K) - Dynamic viscosity (渭) = 8.9x10鈦烩伌 kg/(m路s)
02

Calculate the Reynolds number (Re)

Re = (蟻 * V * D) / 渭 For air: Re_air = (1.184 * 2 * 0.08) / 1.849x10鈦烩伒 = 10237.43 For water: Re_water = (997 * 2 * 0.08) / 8.9x10鈦烩伌 = 179328.09
03

Determine the type of flow (laminar or turbulent)

For both fluids: - If Re < 2300, the flow is laminar - If Re > 2300, the flow is turbulent For air: Re_air = 10237.43, the flow is turbulent For water: Re_water = 179328.09, the flow is turbulent
04

Use appropriate correlation to calculate Nusselt number (Nu)

Since the flow is turbulent for both fluids, we will use Dittus-Boelter equation, for uniform heat flux: Nu = 0.023 * Re^0.8 * Pr^(1/3) For air: Pr_air = (1.849脳10鈦烩伒 * 1005) / 0.02624 = 0.707 Nu_air = 0.023 * (10237.43)^0.8 * (0.707)^(1/3) = 137.13 For water: Pr_water = (8.9脳10鈦烩伌 * 4182) / 0.6075 = 6.108 Nu_water = 0.023 * (179328.09)^0.8 * (6.108)^(1/3) = 5715.27
05

Calculate the convection heat transfer coefficient (h)

h = (k * Nu) / D For air: h_air = (0.02624 * 137.13) / 0.08 = 44.73 W/(m虏路K) For water: h_water = (0.6075 * 5715.27) / 0.08 = 43346.84 W/(m虏路K) The convection heat transfer coefficients for the flow of (a) air and (b) water inside the tube are approximately: (a) h_air = 44.73 W/(m虏路K) (b) h_water = 43346.84 W/(m虏路K)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds Number
In fluid mechanics, the Reynolds Number is a crucial dimensionless quantity used to predict the flow patterns in different fluid flow situations. It describes the ratio of inertial forces to viscous forces and provides insight into whether the flow will be laminar or turbulent. The formula for calculating the Reynolds Number is given by:\[ \text{Re} = \frac{\rho \cdot V \cdot D}{\mu} \]Where:
  • \( \rho \) is the fluid density
  • \( V \) is the velocity of the fluid
  • \( D \) is the characteristic length, often taken as the diameter in tube flows
  • \( \mu \) is the dynamic viscosity
The significance of Reynolds Number lies in its ability to indicate the behavior of flow:
  • If \( \text{Re} < 2300 \), the flow is typically considered laminar, meaning it flows in parallel layers with no disruption between them.
  • If \( \text{Re} > 2300 \), the flow starts to become turbulent, characterized by random and chaotic changes.
Nusselt Number
The Nusselt Number is another dimensionless number important in heat transfer analysis, specifically in convection. It represents the enhancement of heat transfer through a fluid layer as a result of convection relative to that by conduction. The formula to determine the Nusselt Number in a turbulent flow, using the Dittus-Boelter Equation, is:\[ \text{Nu} = 0.023 \cdot \text{Re}^{0.8} \cdot \text{Pr}^{1/3} \]The Nusselt Number allows engineers to predict the convection heat transfer coefficient from the known properties of the fluid and flow conditions. A higher Nusselt Number indicates a greater enhancement of heat transfer. In the exercise given, knowing the turbulent nature of the flow, the Nusselt Number is calculated using the Dittus-Boelter equation for both air and water.
Dittus-Boelter Equation
The Dittus-Boelter Equation is a commonly used empirical formula in thermal fluid systems to estimate the convective heat transfer coefficient for a fluid flowing through a pipe. It is specifically applied to turbulent flow situations. The formula is written as:\[ \text{Nu} = 0.023 \cdot \text{Re}^{0.8} \cdot \text{Pr}^{0.3} \]This equation helps in understanding how the heat transfer efficiency improves with increasing Reynolds and Prandtl numbers. It takes into account the significance of convection over conduction for different fluid characteristics and flow conditions.
Thermal Conductivity
Thermal Conductivity is a physical property that indicates a material's ability to conduct heat. It's denoted by \( k \) and reflects how well heat is transferred through a material due to a temperature gradient. The units of thermal conductivity are W/(m路K).When considering heat transfer in fluids like air and water, thermal conductivity plays an important role in determining the effectiveness of heat exchange in processes, such as those occurring in heat exchangers and cooling systems. Higher thermal conductivity means better capacity of the material to conduct heat.
Dynamic Viscosity
Dynamic Viscosity is a measure of a fluid's resistance to gradual deformation by shear or tensile stress. It is symbolized by \( \mu \) and is notably measured in kg/(m路s). Dynamic viscosity influences how a fluid flows under force and is an essential factor in determining the Reynolds Number.In fluid dynamic calculations, such as the one described in the exercise, understanding the viscosity is crucial because it affects the flow characterizations as either laminar or turbulent. Higher viscosity means a more significant resistance to flow, impacting how easily the fluid moves through the pipe.

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Most popular questions from this chapter

To cool a storehouse in the summer without using a conventional air- conditioning system, the owner decided to hire an engineer to design an alternative system that would make use of the water in the nearby lake. The engineer decided to flow air through a thin smooth 10 -cm-diameter copper tube that is submerged in the nearby lake. The water in the lake is typically maintained at a constant temperature of \(15^{\circ} \mathrm{C}\) and a convection heat transfer coefficient of \(1000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If air (1 atm) enters the copper tube at a mean temperature of \(30^{\circ} \mathrm{C}\) with an average velocity of \(2.5 \mathrm{~m} / \mathrm{s}\), determine the necessary copper tube length so that the outlet mean temperature of the air is \(20^{\circ} \mathrm{C}\).

A 10 -m-long and 10 -mm-inner-diameter pipe made of commercial steel is used to heat a liquid in an industrial process. The liquid enters the pipe with \(T_{i}=25^{\circ} \mathrm{C}, V=0.8 \mathrm{~m} / \mathrm{s}\). A uniform heat flux is maintained by an electric resistance heater wrapped around the outer surface of the pipe, so that the fluid exits at \(75^{\circ} \mathrm{C}\). Assuming fully developed flow and taking the average fluid properties to be \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=\) \(4000 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mu=2 \times 10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, k=0.48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\operatorname{Pr}=10\), determine: (a) The required surface heat flux \(\dot{q}_{s}\), produced by the heater (b) The surface temperature at the exit, \(T_{s}\) (c) The pressure loss through the pipe and the minimum power required to overcome the resistance to flow.

Water enters a circular tube whose walls are maintained at constant temperature at a specified flow rate and temperature. For fully developed turbulent flow, the Nusselt number can be determined from \(\mathrm{Nu}=0.023 \mathrm{Re}^{0.8} \mathrm{Pr}^{0.4}\). The correct temperature difference to use in Newton s law of cooling in this case is (a) The difference between the inlet and outlet water bulk temperature. (b) The difference between the inlet water bulk temperature and the tube wall temperature. (c) The log mean temperature difference. (d) The difference between the average water bulk temperature and the tube temperature. (e) None of the above.

Consider a fluid with mean inlet temperature \(T_{i}\) flowing through a tube of diameter \(D\) and length \(L\), at a mass flow rate \(\dot{m}\). The tube is subjected to a surface heat flux that can be expressed as \(\dot{q}_{s}(x)=a+b \sin (x \pi / \mathrm{L})\), where \(a\) and \(b\) are constants. Determine an expression for the mean temperature of the fluid as a function of the \(x\)-coordinate.

Consider fully developed laminar flow in a circular pipe. If the diameter of the pipe is reduced by half while the flow rate and the pipe length are held constant, the pressure drop will \((a)\) double, \((b)\) triple, \((c)\) quadruple, \((d)\) increase by a factor of 8 , or \((e)\) increase by a factor of \(16 .\)

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