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Consider fully developed laminar flow in a circular pipe. If the viscosity of the fluid is reduced by half by heating while the flow rate is held constant, how will the pressure drop change?

Short Answer

Expert verified
Answer: The pressure drop will decrease by half.

Step by step solution

01

Understand the Hagen-Poiseuille equation

The Hagen-Poiseuille equation describes the pressure drop in laminar flow through a circular pipe. The equation is given by: \[\Delta P = \frac{8 \mu LQ}{\pi R^4}\] where: - ΔP: Pressure drop - µ: Fluid viscosity - L: Length of the pipe - Q: Flow rate - R: Radius of the pipe
02

Determine the initial pressure drop

Using the Hagen-Poiseuille equation, let's find the initial pressure drop with the given fluid viscosity. Keep the values as variables since the question asked is about how the pressure drop would change and not specific values. The initial pressure drop is: \[\Delta P_1 = \frac{8 \mu_1 LQ}{\pi R^4}\]
03

Determine the final pressure drop

Now, let's find the final pressure drop after the fluid viscosity is reduced by half while keeping the flow rate constant. The new viscosity is: \[\mu_2 = \frac{\mu_1}{2}\] Using the Hagen-Poiseuille equation with the reduced viscosity, the final pressure drop is: \[\Delta P_2 = \frac{8 \mu_2 LQ}{\pi R^4} = \frac{8 (\frac{\mu_1}{2}) LQ}{\pi R^4} = \frac{4 \mu_1 LQ}{\pi R^4}\]
04

Compare the initial and final pressure drops

To find the change in pressure drop, we can compare the initial and final pressure drops. Dividing the final pressure drop by the initial pressure drop gives: \[\frac{\Delta P_2}{\Delta P_1} = \frac{\frac{4 \mu_1 LQ}{\pi R^4}}{\frac{8 \mu_1 LQ}{\pi R^4}} = \frac{1}{2}\]
05

Conclusion

The pressure drop in the laminar flow through the circular pipe will decrease by half after reducing the fluid viscosity by half while keeping the flow rate constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hagen-Poiseuille equation
The Hagen-Poiseuille equation is crucial for understanding fluid dynamics in laminar flow through a circular pipe. It defines how various factors like viscosity, pipe dimensions, and flow rate affect the pressure drop in the system.
The equation is expressed as follows: \[\Delta P = \frac{8 \mu LQ}{\pi R^4}\] This equation relates:
  • \( \Delta P \): Pressure drop across the pipe
  • \( \mu \): Viscosity of the fluid
  • \( L \): Length of the pipe
  • \( Q \): Volumetric flow rate
  • \( R \): Radius of the pipe
The equation shows that pressure drop is directly proportional to viscosity, pipe length, and flow rate, and inversely proportional to the fourth power of the pipe radius. By manipulating this equation, you can understand how changes in these variables affect the pressure drop.
Pressure drop
Pressure drop is a key concept in fluid dynamics. It refers to the reduction in pressure as a fluid flows through a pipe.
Pressure drop is caused by frictional forces between the fluid layers and the walls of the pipe.
The Hagen-Poiseuille equation highlights that in laminar flow, pressure drop depends heavily on:
  • Viscosity
  • Flow rate
  • Pipe length
  • Pipe radius
In our exercise, we see that as viscosity is halved, the pressure drop is also reduced by half. This inverse relationship is characteristic of how viscosity affects the pressure drop in a system where other factors remain constant.
Viscosity
Viscosity measures a fluid's resistance to deformation or its 'thickness.' It's crucial in determining how a fluid flows through a pipe.
In laminar flow, viscosity plays a significant role in the frictional forces experienced by the fluid. Viscosity is denoted by the symbol \( \mu \) and can be influenced by temperature; heating typically reduces viscosity.
In our scenario, when the viscosity of the fluid decreases by half, the pressure drop also halves, which the Hagen-Poiseuille equation confirms - indicating a direct link between viscosity and friction in fluid dynamics.
Circular pipe
The geometry of a pipe significantly affects fluid dynamics, particularly in determining the pressure drop in laminar flow.
A circular pipe, which is commonly used in many systems, has the unique characteristic that the pressure drop is inversely proportional to the fourth power of its radius.
This means that even small changes in the radius of the pipe can have significant impacts on the pressure drop. Thus, increasing the radius slightly can dramatically decrease the pressure drop, and vice versa.
In our exercise, while the radius and flow rate remain constant, changes in fluid viscosity can also influence the resulting pressure drop as outlined in the Hagen-Poiseuille equation.

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Most popular questions from this chapter

Reconsider Prob. 8-70. Using the EES (or other) software, evaluate the effect of glycerin mass flow rate on the free-stream velocity of the hydrogen gas needed to keep the outlet mean temperature of the glycerin at \(40^{\circ} \mathrm{C}\). By varying the mass flow rate of glycerin from \(0.5\) to \(2.4 \mathrm{~kg} / \mathrm{s}\), plot the free stream velocity of the hydrogen gas as a function of the mass flow rate of the glycerin.

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Consider the velocity and temperature profiles for a fluid flow in a tube with diameter of \(50 \mathrm{~mm}\) can be expressed as $$ \begin{aligned} &u(r)=0.05\left[\left(1-(r / R)^{2}\right]\right. \\ &T(r)=400+80(r / R)^{2}-30(r / R)^{3} \end{aligned} $$ with units in \(\mathrm{m} / \mathrm{s}\) and \(\mathrm{K}\), respectively. Determine the average velocity and the mean (average) temperature from the given velocity and temperature profiles.

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