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Chapter 8: Problem 11

Consider the flow of oil in a tube. How will the hydrodynamic and thermal entry lengths compare if the flow is laminar? How would they compare if the flow were turbulent?

Short Answer

Expert verified
Question: Compare the hydrodynamic and thermal entry lengths in laminar and turbulent flows within a tube. Answer: In laminar flow, the hydrodynamic and thermal entry lengths have a similar magnitude due to their dependence on the Reynolds number and Prandtl number. In turbulent flow, the hydrodynamic entry length is approximately constant and typically shorter than the thermal entry length, as it takes longer for a stable temperature profile to establish in turbulent flows due to increased mixing.

Step by step solution

01

Define hydrodynamic and thermal entry lengths

The hydrodynamic entry length is the distance it takes for the flow to become fully developed from the point where the fluid enters a tube. The thermal entry length, on the other hand, is the distance required for the temperature profile to become established. These lengths depend on the Reynolds number (Re) and Prandtl number (Pr), respectively, for laminar flow, and on the tube diameter, fluid properties, and flow rate for turbulent flow.
02

Compare hydrodynamic and thermal entry lengths in laminar flow

For laminar flow, the relationship between the hydrodynamic entry length (Lh) and the Reynolds number (Re) is given by: Lh = 0.05 * Re * D where D is the diameter of the tube The relationship between the thermal entry length (Lt) and the Prandtl number (Pr) is given by: Lt = 0.05 * Re * Pr * D In laminar flow, the Reynolds number is small, and the Prandtl number is typically close to 1. Therefore, the thermal entry length and hydrodynamic entry length have a similar magnitude in a laminar flow.
03

Compare hydrodynamic and thermal entry lengths in turbulent flow

In turbulent flow, the hydrodynamic entry length is approximately constant and not dependent on the Reynolds number, with a value around 10 times the tube diameter: Lh_turbulent 鈮� 10 * D The thermal entry length in turbulent flow is more difficult to predict and depends on various factors, but it typically tends to be larger than the hydrodynamic entry length. This is because, in turbulent flow, there is a higher degree of mixing making it harder for a stable temperature profile to be established quickly.
04

Summarize the comparison

In laminar flow, the hydrodynamic and thermal entry lengths are of a similar magnitude due to their dependence on the Reynolds number and Prandtl number. In turbulent flow, the hydrodynamic entry length is approximately constant and is typically shorter than the thermal entry length, as it takes longer for a stable temperature profile to establish in turbulent flows due to increased mixing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laminar Flow
Laminar flow occurs when a fluid flows in parallel layers with no disruption between them. This type of flow is characterized by smooth, constant motion without turbulence. An ideal example is oil moving steadily through a tube.
In laminar flow, every particle of the fluid follows a path that does not intersect the path of any other particle, resulting in highly orderly flow characteristics.
  • This flow tends to occur at lower velocities and is less chaotic than turbulent flow.
  • It is stable, which makes predicting the behavior of fluids easier in laminar conditions.
The occurrence of laminar flow is highly dependent on the Reynolds number, a dimensionless value that helps characterize different flow regimes.
Turbulent Flow
Turbulent flow is the opposite of laminar flow. It occurs when there are chaotic changes in pressure and flow velocity. In turbulent flow, the fluid particles follow irregular paths, which makes it difficult to predict their movements over a short period.
Unlike laminar flow, turbulent flow is characterized by eddies, swirls, and other similar flow instabilities.
  • Turbulent flow is usually generated at high velocities.
  • This type of flow results in increased mixing, which can affect properties such as heat transfer.
Turbulent flow can be beneficial in processes where mixing is essential, but it also can result in higher energy losses due to the random nature of the flow.
Reynolds Number
The Reynolds number (Re) is a crucial dimensionless factor in fluid mechanics that determines whether flow will be laminar or turbulent. It is calculated using the formula:
\[Re = \frac{\rho v L}{\mu}\]
Here, \(\rho\) is the fluid density, \(v\) is the flow velocity, \(L\) is a characteristic length (such as tube diameter), and \(\mu\) is the dynamic viscosity of the fluid.
  • Reynolds number below 2000 indicates laminar flow.
  • Reynolds number above 4000 usually signals turbulent flow.
  • Values between 2000 and 4000 correspond to a critical zone characterized by transition between laminar and turbulent flow.
Reynolds number provides a comprehensive way to predict the nature of fluid flow and assist in designing more efficient systems.
Prandtl Number
The Prandtl number (Pr) is a dimensionless number crucial for heat transfer analysis. It represents the ratio of momentum diffusivity (viscous diffusion) to thermal diffusivity and is defined by:
\[Pr = \frac{c_p \mu}{k}\]
where \(c_p\) is the specific heat, \(\mu\) is the dynamic viscosity, and \(k\) is the thermal conductivity.
  • A low Prandtl number means that thermal diffusivity dominates, implying faster thermal conduction.
  • A high Prandtl number indicates that fluid motion contributes more to flow characteristics.
  • It helps determine the relative thickness of the momentum and thermal boundary layers.
The Prandtl number is particularly important in predicting thermal entry length in a flow system and informs on the thermal behavior of fluid flows, especially in heat exchanger designs.

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Most popular questions from this chapter

Reconsider Prob. 8-70. Using the EES (or other) software, evaluate the effect of glycerin mass flow rate on the free-stream velocity of the hydrogen gas needed to keep the outlet mean temperature of the glycerin at \(40^{\circ} \mathrm{C}\). By varying the mass flow rate of glycerin from \(0.5\) to \(2.4 \mathrm{~kg} / \mathrm{s}\), plot the free stream velocity of the hydrogen gas as a function of the mass flow rate of the glycerin.

A tube with a square-edged inlet configuration is subjected to uniform wall heat flux of \(8 \mathrm{~kW} / \mathrm{m}^{2}\). The tube has an inside diameter of \(0.622\) in and a flow rate of \(2.16 \mathrm{gpm}\). The liquid flowing inside the tube is ethylene glycol-distilled water mixture with a mass fraction of \(2.27\). Determine the friction coefficient at a location along the tube where the Grashof number is \(\mathrm{Gr}=35,450\). The physical properties of the ethylene glycol-distilled water mixture at the location of interest are \(\operatorname{Pr}=13.8, v=18.4 \times 10^{-6} \mathrm{ft}^{2} / \mathrm{s}\), and \(\mu_{b} / \mu_{s}=1.12\). Then recalculate the fully developed friction coefficient if the volume flow rate is increased by 50 percent while the rest of the parameters remain unchanged.

In a food processing plant, hot liquid water is being transported in a pipe \(\left(k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, D_{i}=2.5 \mathrm{~cm}\right.\), \(D_{o}=3 \mathrm{~cm}\), and \(\left.L=10 \mathrm{~m}\right)\). The hot water flowing with a mass flow rate of \(0.15 \mathrm{~kg} / \mathrm{s}\) enters the pipe at \(100^{\circ} \mathrm{C}\) and exits at \(60^{\circ} \mathrm{C}\). The plant supervisor thinks that since the hot water exits the pipe at \(60^{\circ} \mathrm{C}\), the pipe's outer surface temperature should be safe from thermal burn hazards. In order to prevent thermal burn upon accidental contact with skin tissue for individuals working in the vicinity of the pipe, the pipe's outer surface temperature should be kept below \(45^{\circ} \mathrm{C}\). Determine whether or not there is a risk of thermal burn on the pipe's outer surface. Assume the pipe outer surface temperature remains constant.

A house built on a riverside is to be cooled in summer by utilizing the cool water of the river, which flows at an average temperature of \(15^{\circ} \mathrm{C}\). A 15 -m-long section of a circular duct of 20 -cm diameter passes through the water. Air enters the underwater section of the duct at \(25^{\circ} \mathrm{C}\) at a velocity of \(3 \mathrm{~m} / \mathrm{s}\). Assuming the surface of the duct to be at the temperature of the water, determine the outlet temperature of air as it leaves the underwater portion of the duct. Also, for an overall fan efficiency of 55 percent, determine the fan power input needed to overcome the flow resistance in this section of the duct.

Air at \(10^{\circ} \mathrm{C}\) enters an \(18-\mathrm{m}\)-long rectangular duct of cross section \(0.15 \mathrm{~m} \times 0.20 \mathrm{~m}\) at a velocity of \(4.5 \mathrm{~m} / \mathrm{s}\). The duct is subjected to uniform radiation heating throughout the surface at a rate of \(400 \mathrm{~W} / \mathrm{m}^{3}\). The wall temperature at the exit of the duct is (a) \(58.8^{\circ} \mathrm{C}\) (b) \(61.9^{\circ} \mathrm{C}\) (c) \(64.6^{\circ} \mathrm{C}\) (d) \(69.1^{\circ} \mathrm{C}\) (e) \(75.5^{\circ} \mathrm{C}\) (For air, use \(k=0.02551 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=0.7296, v=1.562 \times\) \(10^{-5} \mathrm{~m}^{2} / \mathrm{s}, c_{p}=1007 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \rho=1.184 \mathrm{~kg} / \mathrm{m}^{3}\).)
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