/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 154 A large heated steel block \(\le... [FREE SOLUTION] | 91Ó°ÊÓ

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A large heated steel block \(\left(\rho=7832 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=\right.\) \(434 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=63.9 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\left.\alpha=18.8 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)\) is allowed to cool in a room at \(25^{\circ} \mathrm{C}\). The steel block has an initial temperature of \(450^{\circ} \mathrm{C}\) and the convection heat transfer coefficient is \(25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming that the steel block can be treated as a quarter-infinite medium, determine the temperature at the edge of the steel block after 10 minutes of cooling.

Short Answer

Expert verified
The temperature at the edge of the steel block after 10 minutes of cooling is 450°C.

Step by step solution

01

Gather given information

We are given the following information in the problem: - Initial temperature: \(T_{i} = 450^{\circ} \mathrm{C}\) - Room temperature: \(T_{\infty} = 25^{\circ} \mathrm{C}\) - Thermal diffusivity: \(\alpha = 18.8 \times 10^{-6} \mathrm{m}^2/\mathrm{s}\) - Time: \(t = 10 \,\text{minutes}\) We have the distance from the edge \(x=0\) since we are looking for the temperature at the edge of the steel block.
02

Convert given time to seconds

The time in the problem is given in minutes, so we need to convert it to seconds: \(t = 10 \,\text{minutes} \times \frac{60\,\text{seconds}}{1\,\text{minute}} = 600\,\text{seconds}\)
03

Calculate the temperature at the edge of the steel block

Now, we can use the formula for the temperature at the edge of the steel block: \(T(s) = T_{i} + (T_{\infty} - T_{i}) erf(\frac{x}{2\sqrt(\alpha t)}) \) Substitute the values into the formula: \(T(s) = 450 + (25 - 450) erf(\frac{0}{2\sqrt(18.8 \times 10^{-6} \times 600)}) \) Since we have \(x=0\), the formula simplifies to: \(T(s) = 450 + (25 - 450) \cdot 0 = 450\) So, the temperature at the edge of the steel block after 10 minutes of cooling is \(450^{\circ} \mathrm{C}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermal Diffusivity
Thermal diffusivity is a property that measures how quickly heat spreads through a material. It is represented by the symbol \( \alpha \) and is defined by the equation \( \alpha = \frac{k}{\rho \cdot c_p} \) where \( k \) is the thermal conductivity, \( \rho \) is the density, and \( c_p \) is the specific heat capacity at constant pressure. An intuitive way to think of thermal diffusivity is to imagine pouring a cup of hot coffee into a lake. The rate at which the heat from the coffee spreads throughout the water is akin to a material's thermal diffusivity.

Materials with high thermal diffusivity, like our steel block in the exercise, can transfer heat rapidly throughout their volume. This is crucial when considering the cooling or heating processes, as it allows for a quick response to temperature changes in the environment.
Convection Heat Transfer Coefficient
The convection heat transfer coefficient, denoted by \( h \) is a measure of the convective heat transfer between a surface and a fluid moving over it. It is part of the Newton's Law of Cooling and is used in the equation \( Q = hA(T_{surface} - T_{fluid}) \) where \( Q \) is the heat transfer rate, \( A \) is the surface area, and \( T_{surface} \) and \( T_{fluid} \) are the temperatures of the surface and fluid, respectively.

In the context of our steel block problem, the convection heat transfer coefficient plays a critical role. The higher this coefficient, the more efficient the heat removal from the block's surface into the surrounding air, which influences the cooling rate. The given value of \( 25 \, \mathrm{W/m^2 \cdot K} \) indicates the amount of heat that can be transferred per unit area and per degree temperature difference between the block's surface and the ambient air.
Transient Heat Conduction
Transient heat conduction refers to the time-dependent process of heat transfer within a material as it moves towards thermal equilibrium with its surroundings. Unlike steady-state conduction, where temperatures remain constant over time, in transient heat conduction, temperatures can vary both in space and time.

When addressing problems involving transient heat conduction, such as the cooling of the steel block, it is essential to know the initial temperature distribution, properties of the material, and boundary conditions. The solution presented in the exercise assumes that the steel block can be treated as a quarter-infinite medium, which means it is semi-infinite in reality, and only a quarter is considered for simplification. Mathematical tools like the error function (erf) are often used to solve these kinds of heat transfer problems. The heat conduction in the block changes over time, leading us to determine the temperature at a specific moment, which in this case is 10 minutes after the cooling process begins.

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Most popular questions from this chapter

The 40-cm-thick roof of a large room made of concrete \(\left(k=0.79 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \alpha=5.88 \times 10^{-7} \mathrm{~m}^{2} / \mathrm{s}\right)\) is initially at a uniform temperature of \(15^{\circ} \mathrm{C}\). After a heavy snow storm, the outer surface of the roof remains covered with snow at \(-5^{\circ} \mathrm{C}\). The roof temperature at \(18.2 \mathrm{~cm}\) distance from the outer surface after a period of 2 hours is (a) \(14^{\circ} \mathrm{C}\) (b) \(12.5^{\circ} \mathrm{C}\) (c) \(7.8^{\circ} \mathrm{C}\) (d) \(0^{\circ} \mathrm{C}\) (e) \(-5^{\circ} \mathrm{C}\)

Lumped system analysis of transient heat conduction situations is valid when the Biot number is (a) very small (b) approximately one (c) very large (d) any real number (e) cannot say unless the Fourier number is also known.

Long aluminum wires of diameter \(3 \mathrm{~mm}(\rho=\) \(2702 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=0.896 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}, k=236 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\alpha=\) \(9.75 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\) ) are extruded at a temperature of \(350^{\circ} \mathrm{C}\) and exposed to atmospheric air at \(30^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (a) Determine how long it will take for the wire temperature to drop to \(50^{\circ} \mathrm{C}\). (b) If the wire is extruded at a velocity of \(10 \mathrm{~m} / \mathrm{min}\), determine how far the wire travels after extrusion by the time its temperature drops to \(50^{\circ} \mathrm{C}\). What change in the cooling process would you propose to shorten this distance? (c) Assuming the aluminum wire leaves the extrusion room at \(50^{\circ} \mathrm{C}\), determine the rate of heat transfer from the wire to the extrusion room.

The soil temperature in the upper layers of the earth varies with the variations in the atmospheric conditions. Before a cold front moves in, the earth at a location is initially at a uniform temperature of \(10^{\circ} \mathrm{C}\). Then the area is subjected to a temperature of \(-10^{\circ} \mathrm{C}\) and high winds that resulted in a convection heat transfer coefficient of \(40 \mathrm{~W} / \mathrm{m}^{2}\). \(\mathrm{K}\) on the earth's surface for a period of \(10 \mathrm{~h}\). Taking the properties of the soil at that location to be \(k=0.9 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and \(\alpha=1.6 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\), determine the soil temperature at distances \(0,10,20\), and \(50 \mathrm{~cm}\) from the earth's surface at the end of this \(10-\mathrm{h}\) period.

A body at an initial temperature of \(T_{i}\) is brought into a medium at a constant temperature of \(T_{\infty}\). How can you determine the maximum possible amount of heat transfer between the body and the surrounding medium?

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