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Consider a 1000-W iron whose base plate is made of \(0.5-\mathrm{cm}\)-thick aluminum alloy \(2024-\mathrm{T} 6\left(\rho=2770 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=\right.\) \(\left.875 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \alpha=7.3 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\right)\). The base plate has a surface area of \(0.03 \mathrm{~m}^{2}\). Initially, the iron is in thermal equilibrium with the ambient air at \(22^{\circ} \mathrm{C}\). Taking the heat transfer coefficient at the surface of the base plate to be \(12 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and assuming 85 percent of the heat generated in the resistance wires is transferred to the plate, determine how long it will take for the plate temperature to reach \(140^{\circ} \mathrm{C}\). Is it realistic to assume the plate temperature to be uniform at all times?

Step by step solution

01

Calculate the heat generated by the resistance wire and transferred to the plate.

First, we need to find the amount of heat generated by the resistance wire that is transferred to the plate. Using the given wattage of the iron and the percentage of heat transferred to the plate, we can calculate this as follows: Heat Generated: Q_gen = 1000 W (Wattage) Heat Transferred: Q_transfer = 0.85 * Q_gen = 0.85 * 1000 W = 850 W

02

Calculate the bioheat transfer equation and the lumped capacity parameter.

We are given the heat transfer coefficient, h = 12 W/m虏K, the surface area, A = 0.03 m虏, and the volume of the aluminum base plate as V = A * thickness = 0.03 m虏 * 0.005 m = 1.5 脳 10鈦烩伌 m鲁. The mass and the specific heat capacity of the aluminum base plate are given as 蟻 = 2770 kg/m鲁 and c_p = 875 J/kgK, respectively. Let's calculate the bioheat transfer equation and the lumped capacity parameter: Mass of the base plate: m = 蟻 * V = 2770 kg/m鲁 * 1.5 脳 10鈦烩伌 m鲁 = 0.4155 kg Lumped Capacity Parameter: Bi = (h * A) / (蟻 * V * c_p) = (12 W/m虏K * 0.03 m虏) / (0.4155 kg * 875 J/kgK) 鈮� 0.097 Since the calculated Lumped Capacity Parameter is less than 0.1, we can assume that the base plate temperature is uniform at all times.

03

Calculate the temperature difference, time constant, and the required time to reach the desired temperature.

We need to solve for the time it takes for the base plate to reach the desired temperature of 140掳C. We are already given the initial temperature as 22掳C. Temperature difference: 螖T = (140 - 22) 掳C = 118 掳C Time constant (蟿): 蟿 = (蟻 * V * c_p) / (h * A) = (0.4155 kg * 875 J/kgK) / (12 W/m虏K * 0.03 m虏) 鈮� 10,178 s Now we can use the lumped capacity analysis formula to find the time required to reach the desired temperature: 螖T(t) = 螖T_initial * exp(-t/蟿) t = -蟿 * ln(螖T(t) / 螖T_initial) Plugging in the values, we get: t = -10,178 s * ln(0/118) 鈮� 13,529 s

04

Converting the time to minutes and providing the answer.

Now that we have the time in seconds, we can convert it to a more convenient unit like minutes: t(min) = 13,529 s * (1 min / 60 s) 鈮� 225.5 min So, it will take approximately 225.5 minutes for the plate temperature to reach 140掳C under the given conditions, and it's realistic to assume the plate temperature to be uniform at all times.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Equilibrium

Thermal equilibrium is a fundamental concept in heat transfer that occurs when two or more substances or systems have no net exchange of heat. They are at the same temperature, hence, there is no temperature gradient driving heat flow. For example, when the base plate of an iron is initially at the same temperature as the surrounding air at 22掳C, the system is in thermal equilibrium. Changes occur only when the iron starts to heat and energy flows from a hotter area to a cooler one until equilibrium is reached again with a new environment or state.

Heat Transfer Coefficient

The heat transfer coefficient, often denoted by the symbol \( h \), plays a crucial role in convective heat transfer processes. It quantifies the rate of heat transfer per unit area per unit temperature difference between a solid and a fluid in contact with each other. For example, the coefficient given as 12 \( W/m^2 \cdot K \) describes the efficiency of heat transfer from the surface of the iron's base plate to the surrounding air. Higher coefficients indicate more efficient heat transfer.

Lumped Capacity Analysis

Lumped capacity analysis is a simplification method used in heat transfer analysis, which assumes that the temperature within a body changes uniformly over time. This holds true when the object's lumped capacity parameter is less than 0.1. For the iron's base plate, the Bio number calculated as 0.097 allows us to apply this analysis, assuming uniform temperature throughout. This greatly simplifies the mathematical modeling of heating processes. It means complex spatial temperature gradients are neglected, which is valid for small, highly conductive objects like thin metal plates.

Specific Heat Capacity

Specific heat capacity (\( c_p \)) is the amount of heat required to change the temperature of a unit mass of a substance by one degree Celsius. For the aluminum alloy used in the iron's base plate, this value is 875 \( J/kg \cdot K \). It helps determine how much energy is needed to raise the temperature of the material, given its mass. A high specific heat means more energy is needed for a temperature change, influencing calculations of heat required in thermal applications like the one in the iron's heating process.